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Elasticity - Science topic

Resistance and recovery from distortion of shape.
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I use plastic behaviour for a material in abaqus:
YS plastic strain
8MPa 0
8MPa 1
8MPa 100
And Abaqus seems to ignore the elastic limit, the von Mises stress happily rises above 8MPa. But it does not happen when the mesh is linear with ticked reduced integration. Why is this and how do I fix this bug?
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Venkateswarlu Gattineni indeed, when I use the probe tool set for elements i only get results within the yield limit. but why does abaqus display those wrong values on the visualisation for quadratic mesh or no reduced integration? and why does it display the right values for linear mesh with reduced integration?
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Hello Community, Can someone help me to correct this curve? I have given only elastic properties, but the stress-strain curves oscillates? It should be a straight line.
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The stress vs time and strain vs time curves are oscillating, but if they will be combined (Tools\>XY Data>Create...>Operate on XY data: Operators - combine(X,X)), the resulting stress vs strain curve should be linear.
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To determine the dynamic mechanical properties of PLA compounds it is important to understand their viscous nature (flow properties). Thus, dynamic mechanical analysis (DMA) is performed to evaluate the effect of temperature on the mechanical properties of elegant PLA. Three parameters were used to demonstrate the dynamic mechanical properties of the PLA, i.e. (1) the storage coefficient (E ') corresponding to the elastic response to deformation and related to the material rigidity (2) the loss modulus (E') corresponding to the slag fraction; and (3) the damping factor (tan). These parameters provided qualitative and quantitative information about the thermal behavior of the elegant PLA.
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Dear Doctor
Go To
Dynamic Mechanical Analysis Investigations of PLA-Based Renewable Materials: How Are They Useful?
Mariana Cristea, Daniela Ionita, and Manuela Maria Iftime
Materials (Basel). 2020 Nov; 13(22): 5302.
Published online 2020 Nov 23. doi: 10.3390/ma13225302
"Conclusions
A survey of literature oriented to the use of the DMA technique in the study of polymers reveals that the tool is too often used only for the determination of the glass transition temperature. This is obtained mostly from tan δ peak of the plot tan δ vs. T, which resulted from a scanning temperature experiment, performed at one frequency. Nevertheless, an accurate understanding of the viscoelastic behavior of polymers requires the comparative examination of all the viscoelastic characteristics: elastic modulus E’, viscous modulus E’’ and loss factor tan δ. Such an approach is even mandatory in the case of PLA and PLA-based polymers that involve a whole hierarchy of phenomena which are triggered as the molecular mobility is changing from low temperature to high temperature. These aspects are summarized below.
  • In the glassy region (T < Tg) the secondary relaxations are incidentally mentioned at −50 °C or lower. The β-relaxation was evidenced as a faint drop of E’ modulus or a shallow tan δ peak. Because of the brittleness of PLA, the DMA device is not able to perform reliable experiments at negative temperatures on samples that have a propensity toward cracking.
  • When dealing with PLA, the glassy region means also room temperature condition. Therefore, the DMA investigations allow the determination of the elastic modulus E’ under usual working conditions.
  • The effects that are noticed in the glassy region during composition-dependent studies are reported also for other classes of polymer. The particularity comes from the semicrystalline character of PLA. The processing conditions, the nature and the content of stereoisomers determine decisively the morphology of PLA in terms of crystallinity. Crystalline content can be tuned during the processing stage, inducing an envisaged change of the E’ modulus.
  • By far the most challenging zone is the glass transition region. The chain mobility may be influenced, besides the temperature, by the history of the polymer (aging phenomena) and the applied stress/strain that can induce orientation effects.
  • Typically, the glass transition temperature is considered to be the onset of E’ drop or the peaks of E’’ or tan δ. These indicators are often ambiguous in the situation of PLA because of overlapping phenomena that happen during the glass transition. The synergism of enthalpic relaxation, coordinated molecular movements and orientation/crystallization phenomena makes the determination of Tg by DMA fraught with difficulties.
  • The E’ onset is often hidden by a hump that could appear just at the beginning of the glass transition on the E’ vs. T plot, because of enthalpic relaxation. As a result, contraction of the samples is obvious when the DMA experiment is performed under tension loading.
  • The peaks of E’’ and tan δ for PLA are also deformed as compared to those of a well-behaved polymer that records during the glass transition only the coordinated movements of chain segments.
  • The E’’ peak appears very sharp. This E’’ shape accounts for an instantaneous break of mobility growth due to refolding of polymer chains (shrinking).
  • The tan δ peak is at least bimodal, its descending side is less abrupt, larger than the ascending side, and it may span partially the first rubbery plateau and the cold crystallization region. This is consistent with few underlying processes. Therefore, under the simultaneous action of temperature and force, orientation/crystallization phenomena are triggered even during the glass transition.
  • The increase of crystalline content does not entail necessarily the increase of the glass transition temperature. From a certain level of the crystalline content upward, the values of the glass transition temperature decrease with the crystalline content. These results should be discussed in terms of cooperatively rearranging regions (rigid amorphous phase and mobile amorphous phase).
  • The increased toughness that is obtained by adding a plasticizer is reflected in a lower Tg, but very often the height of tan δ peak monitored during the glass transition region decreases with the toughener quantity. Similarly, a reinforcement agent augments the E’ modulus. However, an opposite effect is reflected in the height of tan δ, i.e., it may increase as more reinforcement is included in the DMA. These patterns are consistent with the effects of already mentioned overlapping phenomena happening during the glass transition (enthalpic relaxation, shrinking, orientation/crystallization).
  • The length of the first rubbery plateau depends on the PLA molecular weight. It can be considered as a gauge for the PLA level degradation in decomposition studies.
  • In the presence of efficient plasticizers the first rubbery plateau is absent because the cold crystallization begins during or immediately the glass transition region.
  • The cold crystallization is evidenced by a sudden increase of E’ modulus. When it follows the glass transition region (the first rubbery plateau is absent), the E’ vs. T plot has a V-shape.
  • There are instances where the cold-crystallization is not encompassed by the extended tan δ descending side. It can appear as a separate, smaller, frequency-independent peak.
  • The E’ value of the second rubbery plateau is lower than that of the glassy region; however it is stable until the abrupt decrease at melting.
  • With regard to the heating rate, it is evident that its value is meaningful firstly for the point of view of DMA investigation accuracy. Then, the kinetic events that might take place as the temperature is raised require time for completion. Heating rates higher than 2–3 °C/min are not adequate for fulfillment of both conditions."
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article with my own views on construction and earthquake.
For me the way seismic loads are transmitted onto the reinforced concrete building structure is as follows.
1. Ground acceleration.
2. Mass inertia.
3. Base ternosity
4. Torque. Torque when applied to elastic columns, shows a different behaviour than if applied to walls, and different if applied to rigid near walls with high dynamics. That is, it has a different coefficient of behaviour q. in terms of ductility, base shear, structural dynamics and capacity in elastic displacement before it exhibits leakage.
A stiff wall has high dynamic and low ductility and is more difficult to fail than an elastic substructure. It still triples the loads it takes down to the base, but due to a larger cross-section the loads received by the elongated wall are less.
A large part of the earthquake behaviour of the structure also has to do with the shape of its faces. Modern architectural needs call for buildings with high ceilings and large openings and a reduction in the number of load-bearing elements. That is, they require non-framed structures made of columns which have a different behaviour and do not show large torsional deformations.
The moment if applied to columns has the following behaviour. It does not download large moments to the base, it consumes energy due to elastic behaviour, and stores energy in the frame which is discharged in the other direction in the next loading cycle. But it has no momentum.
If the torque is applied to stiff near-walls with high momentum and the acceleration is high, then it puts too much torque on the base, which is impossible to be absorbed by the connecting beams which it breaks.
If the torque is applied to stiff near walls with high momentum and the acceleration is large, then it downloads too large a moment to the base, which can be absorbed by the basement walls.
If the acceleration is too large the basement walls do pick up the moment, but there is little or a large withdrawal of the entire footprint of the building.
At this stage we have lost the support of much of the building's base from the foundation soil, and the static loads are left unsupported and their weight force creates an opposing moment to the building's overturning moment.
This can result in the following effects. a) The basement walls and the stiff wall cross-section may be able to take up these loads of the counter-rotating moments and the foundation may experience from a slight recoil to total overturning.
And b) shear failure of one of the two cross-sections, the one that is weaker.
The patent does what it does in this situation.
It presses the structure into the ground so that the moments are taken up by the ground preventing them from transferring to the basement walls.
But this would create a vulnerable rigid superstructure wall which would fail by shear failure for many reasons.
Firstly it would fail the concrete overlay by shear failure due to the over tensile strength of the steel in tension and the low shear strength of the concrete which develops at the concrete-steel interface in the mechanism of aggregation.
Second, in the mechanism of ''congruence'', the critical failure region occurs near the base where the wall takes down large loads. This means that when splitting the direction of the normal tensile forces over the critical failure region, we will also have a potential difference to the adhesion of the top and bottom so that premature shear failure of the bottom of the overlay concrete due to low congruence.
Conclusion We have to prevent tension on one side of the wall because only then we will prevent 1) the critical failure region, 2) the shear failure of the overlay concrete and 3) the potential difference
QUESTION How do we remove the tension?
We eliminate the tension by the method of prestressing + prestressing tendon contact with the soil using strong soil anchors for this purpose.
With this method we take the tensile force from the top level and send it directly into the ground, ensuring the disappearance of the critical failure zone, the disappearance of the tensile stresses from the wall body which only compresses, the disappearance of the potential difference, the deflection of the wall moments into the ground and the prevention of them being driven into the basement wall and beams. Prestressing also helps the stiff wall to become even more dynamic and stiff in order to reduce the deformations at the nodes to zero. Prestressing also increases the friction of the aggregates resulting in an increase in the dynamic of the cross-section with respect to the base shear. The embedment in the ground with expanding mechanisms and the subsequent filling of the boreholes in which the mechanisms are placed with reinforced concrete ensure a strong foundation and soil samples to know their quality.
These are the reasons why in this first experiment with a natural acceleration of 2.41g the test piece did not show the slightest damage.
Once I removed the packing bolts under the seismic base, and eliminated the preload from the tendons the results of the specimen behavior were different and fishy.
Take a closer look at the damage.
άρθρο με τις δικές μου απόψεις για τις κατασκευές και τον σεισμό.
Για εμένα η σειρά που μεταδίδονται τα σεισμικά φορτία πάνω στην κτίριο κατασκευή από οπλισμένο σκυρόδεμα είναι η εξής.
1. Επιτάχυνση εδάφους.
2. Αδράνεια μάζας.
3. Τέμνουσα βάσης
4. Ροπή. Η ροπή όταν εφαρμοσθεί σε ελαστικά υποστυλώματα, παρουσιάζει διαφορετική συμπεριφορά, από ότι αν εφαρμοστεί σε τοιχία, και διαφορετική αν εφαρμοστεί σε δύσκαμπτα κοντά τοιχώματα με μεγάλη δυναμική. Έχει δηλαδή διαφορετικό συντελεστή συμπεριφοράς q. ως προς την πλαστιμότητα, την τέμνουσα βάσης, την δυναμική της κατασκευής και την ικανότητα στην ελαστική μετατόπιση πριν παρουσιάσει διαρροές.
Ένα δύσκαμπτο τοίχωμα έχει μεγάλη δυναμική και μικρή πλαστιμότητα και αστοχεί πιο δύσκολα από ένα ελαστικό υποστύλωμα. Ακόμα τριπλασιάζει τα φορτία που κατεβάζει στην βάση, όμως λόγο μεγαλύτερης διατομής τα φορτία που παραλαμβάνει το επιμήκη τοίχωμα είναι λιγότερα.
Μεγάλο ρόλο στην συμπεριφορά της κατασκευής στον σεισμό έχει να κάνει και με το σχήμα των κατόψεων της. Οι σύγχρονες αρχιτεκτονικές ανάγκες θέλουν υψίκορμα κτίρια με ελεύθερες κατόψεις και μεγάλα ανοίγματα και με μείωση των φερόντων στοιχείων. Δηλαδή απαιτούν μη πλαισιακές κατασκευές από υποστυλώματα οι οποίες έχουν άλλη συμπεριφορά και δεν παρουσιάζουν μεγάλες στρεπτομεταφορικές παραμορφώσεις.
Η ροπή αν εφαρμοστεί σε υποστυλώματα έχει την εξής συμπεριφορά. Δεν κατεβάζει μεγάλες ροπές στην βάση, καταναλώνει ενέργεια λόγο ελαστικής συμπεριφοράς, και αποθηκεύει ενέργεια στον κορμό του την οποία εκτονώνει προς την άλλη κατεύθυνση στον επόμενο κύκλο φόρτισης. Όμως δεν διαθέτει δυναμική.
Αν η ροπή εφαρμοστεί σε δύσκαμπτα κοντά τοιχώματα με μεγάλη δυναμική και η επιτάχυνση είναι μεγάλη, τότε κατεβάζει πάρα πολύ μεγάλες ροπές στην βάση, οι οποίες είναι αδύνατον να παραληφθούν από τους συνδετήριους δοκούς τους οποίους σπάει.
Αν η ροπή εφαρμοστεί σε δύσκαμπτα κοντά τοιχώματα με μεγάλη δυναμική και η επιτάχυνση είναι μεγάλη, τότε κατεβάζει πάρα πολύ μεγάλες ροπές στην βάση, οι οποίες είναι δυνατόν να παραληφθούν από τα τοιχώματα υπογείου.
Αν η επιτάχυνση είναι πολύ μεγάλη τα τοιχώματα του υπογείου παραλαμβάνουν μεν την ροπή, αλλά παρατηρείται μια μικρή ή μεγάλη ανάκληση όλου του εμβαδού της βάσης του κτιρίου.
Σε αυτή την φάση έχουμε χάσει την στήριξη μεγάλου μέρους της βάσης του κτιρίου από το έδαφος θεμελίωσης, και τα στατικά φορτία μένουν αστήρικτα και η δύναμη του βάρους τους δημιουργεί μια αντίρροπη ροπή προς την ροπή ανατροπής του κτιρίου.
Αυτό μπορεί να επιφέρει τα εξής αποτελέσματα. α) Τα τοιχώματα του υπογείου και η διατομή του δύσκαμπτου τοιχώματος να μπορέσουν να παραλάβουν αυτά τα φορτία των αντίρροπων ροπών και η βάση να παρουσιάσει από μια μικρή ανάκληση μέχρι και ολική ανατροπή.
Και β) να αστοχήσει διατμητικά μια εκ των δύο διατομών, αυτή που είναι πιο αδύναμη.
Η ευρεσιτεχνία τι κάνει σε αυτή την κατάσταση.
Πακτώνει την κατασκευή στο έδαφος ώστε οι ροπές να τις αναλάβει το έδαφος αποτρέποντας την μεταφορά τους στα τοιχώματα του υπογείου.
Όμως αυτό θα δημιουργούσε ένα ευάλωτο δύσκαμπτο τοίχωμα ανωδομής το οποίο θα αστοχούσε από διατμητική αστοχία για πολλούς λόγους.
Πρώτον θα αστοχούσε το σκυρόδεμα επικάλυψης από διατμητική αστοχία λόγο της υπέρ αντοχής του χάλυβα στον εφελκυσμό και την μικρής αντοχής του σκυροδέματος στην διάτμηση η οποία αναπτύσσεται στην διεπιφάνεια σκυροδέματος και χάλυβα στον μηχανισμό της συνάφειας.
Δεύτερον στον μηχανισμό της συνάφειας η κρίσιμη περιοχή αστοχίας εμφανίζεται κοντά στην βάση όπου το τοίχωμα κατεβάζει μεγάλα φορτία. Αυτό σημαίνει ότι κατά τον διαχωρισμό της φοράς των ορθών δυνάμεων εφελκυσμού πάνω στην κρίσιμη περιοχή αστοχίας, θα έχουμε και διαφορά δυναμικού προς την πρόσφυση του πάνω και κάτω μέρους οπότε και πρόωρη διατμητική αστοχία του κάτω μέρους του σκυροδέματος επικάλυψης λόγο μικρής συνάφειας.
Συμπέρασμα Πρέπει να αποτρέψουμε τον εφελκυσμό στην μια παρειά του τοιχώματος γιατί μόνο τότε θα αποτρέψουμε 1) την κρίσιμη περιοχή αστοχίας, 2) την διατμητική αστοχία του σκυροδέματος επικάλυψης και 3) την διαφορά δυναμικού
ΕΡΏΤΗΣΗ Πως καταργούμε τον εφελκυσμό?
Καταργούμε τον εφελκυσμό με την μέθοδο της προέντασης + της πάκτωσης του τένοντα προέντασης με το έδαφος χρησιμοποιόντας για τον σκοπό αυτό ισχυρές αγκυρώσεις εδάφους.
Με αυτή την μέθοδο αναλαμβάνουμε την δύναμη εφελκυσμού από την ανώτατη στάθμη και την στέλνουμε απευθείας μέσα στο έδαφος, εξασφαλίζοντας την εξαφάνιση της κρίσιμης περιοχής αστοχίας, την εξαφάνιση των εντάσεων εφελκυσμού από το σώμα του τοιχώματος το οποίο μόνο θλίβεται, την εξαφάνιση της διαφοράς δυναμικού, την εκτροπή των ροπών του τοιχώματος μέσα στο έδαφος και την αποτροπή στο να οδηγηθούν στο τοίχωμα του υπογείου και στους δοκούς. Ακόμα η προένταση βοηθάει το δύσκαμπτο τοίχωμα να γίνει ακόμα ποιο δυναμικό και δύσκαμπτο με σκοπό να μηδενίσει τις παραμορφώσεις στους κόμβους. Η προένταση αυξάνει και την τριβή των αδρανών υλικών με αποτέλεσμα να έχουμε αύξηση της δυναμικής της διατομής ως προς την τέμνουσα βάσης. Η πάκτωση στο έδαφος με μηχανισμούς που διαστέλλονται και η μετέπειτα πλήρωση των οπών των γεωτρήσεων στις οποίες τοποθετούνται οι μηχανισμοί με οπλισμένο σκυρόδεμα, εξασφαλίζουν ισχυρή θεμελίωση και δείγματα εδάφους για να ξέρουμε την ποιότητά τους.
Αυτοί είναι οι λόγοι για τους οποίους σε αυτό το πρώτο πείραμα με φυσική επιτάχυνση 2,41g το δοκίμιο δεν παρουσίασε την παραμικρή βλάβη.
Μόλις αφαίρεσα τους κοχλίες πάκτωσης κάτω από την σεισμική βάση, και εξάλειψα την προένταση από τους τένοντες τα αποτελέσματα της συμπεριφοράς του δοκιμίου ήταν διαφορετικά και ψαθυρά.
Δέστε από κοντά τις βλάβες.
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Dear Doctor James Lewis
The purpose of modern seismic regulation is to build structures that: a) In frequent earthquakes with a high probability of occurrence, nothing will happen, b) In earthquakes with a medium probability of occurrence, minor, repairable damage will occur, and c) In very strong earthquakes with a low probability of occurrence, no loss of life will occur. So we should not use the term "absolute" in seismic structures. We should use the term 'quality' structures which means applying at least the requirements of all modern regulations. The quality of construction and its safety is also a function of the economic situation of countries, among other factors. It is understandable that poor countries cannot be compared with countries where they have expensive modern seismic regulations. Conclusion... there is no absolute seismic planning today, and we should not refer to absolute seismic planning, but to quality planning. So there is a great need today to invent a more modern anti-seismic design that corresponds to absolute anti-seismic design, with lower construction costs.
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I am trying to do elastic property calculation in QE, with ibrav=8 using thermo_pw. But getting an error shown below.
task # 14
from initialize_elastic_cons : error # 1
Laue class not available
Can anyone suggest how to resolve it?
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Michael Tekle Thanks for the response. But i don't find any solution.
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Fatigue fracture surfaces of broken high strength materials exhibit rough conoidal cracks at the vertex of which are located inclusions or heterogeneities
Experimental: The observations refer to Sakai et al. (2002), Abdesselam et al. (2018), Stinville et al. (2018) ... These cracks have been named “fish-eye marks” by two former authors and their formations have been divided into three stages: (i) formation of the characteristic area as a fine granular area (FGA); (ii) crack propagation to form the fish-eye (i.e. according to us “rough conoidal crack”); (iii) rapid crack propagation to cause the catastrophic fracture.
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With this work at hand (i.e. "ROUGH CONOIDAL CRACK GROWING UNIFORMLY UNDER GENERAL LOADING"), it becomes possible to follow the evolution (propagation) of highest complexity cracks that nucleate from defects (such as heterogeneities, inclusions ...) located inside materials. The provided G (the crack extension force per unit length of the crack front) is function of highest number of variables and parameters.
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What is the equation that describes the relationship between Gibbs elasticity and elastic modulus in polymers?
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The relationship between Gibbs elasticity (also known as the Gibbs energy elasticity) and the elastic modulus in materials is described by the following equation:
E= ρ² / β x ∂ ² G / ∂ ρ²
Where:
- E is the elastic modulus (Young's modulus) of the material.
- ρis the strain (deformation) of the material.
- β is the volume strain, which is the change in volume divided by the initial volume.
- G is the Gibbs free energy of the material.
This equation relates the elastic modulus of a material to its Gibbs elasticity, which is a measure of the change in Gibbs free energy with respect to strain. The equation essentially quantifies how the free energy of a material changes as it is subjected to deformation or strain.
It's important to note that this equation is derived based on certain assumptions and approximations, and its applicability might vary depending on the specific properties of the material and the nature of the deformation. In some cases, different forms of this equation or other constitutive equations might be used to model the relationship between mechanical properties and thermodynamic quantities.
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The prestress is much larger than its elastic stress limit, which means if I add this stress to the material, the material will endure plastic strain immediately.
Should I only input the elastic stress and change its shape or input all stress?
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Thank you. Can abaqus add plastic deformation (PEEQ) as initial conditions?
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Hi, experts.
My understanding is that a plastic strain increment (△ε_p) can never be negative (it can be either positive or zero), as long as the material conforms to the consistency condition.
That is to say, ε_p for t(timestep)=n+1 is always larger than that for timestep=n.
This is because the plastic deformation is permanent; the plastic strain is accumulated as the deformation proceeds and not recovered after unloading.
Then I am wondering if this is the case for an elastic strain increment (△ε_e) as well.
My question is,
Is an elastic strain increment always non-negative? or can it be negative?
As of now, I assume that if the total strain(ε = ε_e + ε_p) for t=n+1 is smaller than that for t=n, the negative elastic strain increment is possible. Am I right?
Please leave comments if anyone knows the answer.
Thank you in advance!
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Your understanding regarding plastic strain increment (Δε_p) is correct. In the context of plastic deformation, the plastic strain increment is always non-negative (Δε_p ≥ 0) because plastic deformation is permanent, and the material undergoes irreversible changes during plastic flow. Plastic strain accumulates over time and is not recovered after unloading.
Regarding the elastic strain increment (Δε_e), it is important to understand the difference between elastic and plastic deformation. Elastic deformation is reversible, and the material returns to its original shape when the load is removed. In an elastic material, the strain is directly proportional to the stress applied, following Hooke's law.
For an elastic material, the elastic strain increment can indeed be negative (Δε_e < 0) under certain conditions. It implies that the material is experiencing compressive strain, and when the load is removed, it will spring back to its original shape. In other words, during unloading, the material is undergoing elastic recovery and reducing the strain.
In summary, for an elastic material, the elastic strain increment can be positive or negative depending on the loading conditions. On the other hand, for a plastic material, the plastic strain increment is always non-negative, and it accumulates over time as plastic deformation is irreversible.
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YES! THIS HAS BEEN SHOWN IN “PLANAR CRACKS IN UNIFORM MOTION UNDER MODE I AND II LOADINGS” (ANONGBA 2020).
Earlier works have suggested that crack speeds v could not exceed Rayleigh wave velocity, in the subsonic velocity regime (v< ct transverse sound wave velocity).
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YES! THIS HAS BEEN SHOWN IN “PLANAR CRACKS IN UNIFORM MOTION UNDER MODE I AND II LOADINGS” (ANONGBA 2020).
THIS IS WITHIN THE THEORY OF LINEAR ELASTICITY!!!
In mode I loading and in the subsonic velocity regime (v < ct, the velocity of transverse sound wave), G (I) increases continuously with v from the value in the static case G(I)0 (v = 0) to a maximum G(I)max = 1.32 G(I)0 at v = v (e) =0.52ct; then, G (I) decreases rapidly to zero when v tends to ct. In agreement with experiments, the value v (e) corresponding to the maximum of the crack extension force is identified to the terminal tensile crack velocity, observed in the fracture of brittle materials. No reference is made to the Rayleigh wave velocity cR. In the transonic speed regime (ct < v < cl), the crack characteristic functions are identical in form with those of the subsonic regime. However, for v < ct√2, we show that the faces of the crack, separated under load before the extension of the crack, close under motion; this indicates that the crack movement is hindered. for v > ct√2, the motion of the crack is possible. In mode II loading and in the subsonic regime (v < ct), G (II) increases continuously with v (when v < cR) from the value in the static case G(II)0(v = 0); when v approaches cR, G (II) increases very rapidly. Above cR (cR < v < ct), the relative displacement of the faces of the crack, formed under load before crack motion, closes in motion; this indicates that crack motion is impeded. The velocity of uniformly moving cracks is limited by the Rayleigh wave velocity. In the intermediate speed regime (ct < v < cl), the crack characteristic functions are similar in form to those below cR. The mouvement of the crack is possible.
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Reservoir Geo-mechanics: Biot’s Coefficient
1. How important is the concept of Biot’s coefficient (involved in Biot’s effective stress relationship which assumes that total isotropic confining stress remains equal to the sum of effective stress and the pore fluid pressure multiplied by Biot’s coefficient) towards characterizing a petroleum reservoir?
Feasible to determine Biot’s coefficient for a low-porous and low-permeable reservoir @ laboratory-scale considering the time required to reach equilibrium of reservoir pore fluid pressure? 2. Feasible to validate the following two basic aspects @ field-scale associated with a petroleum reservoir, when reservoir pressure remains to be lesser than bubble point pressure?
(a)        Biot’s coefficient cannot be greater than unity, if the reservoir is assumed to be an elastic isotropic material; and
(b)       Biot’s effective stress getting reduced to Terzhagi’s effective stress upon Biot’s coefficient reaching unity.
3. How do we know whether the exploitation of oil and gas at a particular basin has "significantly" contributed to perturbations in the geosphere in terms of changes to the total stresses, pore pressures and the thermal regime?
Along with in-situ seismic wave velocity measurements, whether the existing coupled effect of thermo-hydro-mechanical-chemical phenomena would be able to provide the required responses of water/oil/gas saturated reservoir rock masses (which essentially depends on how exactly the external stresses remain partitioned between solid-grain network and the reservoir pore fluids)?
4. Although Biot’s theory of poro-elasticity can be expressed as functions of strains, elastic properties, and fluid pressure or increment of fluid volume per unit volume of porous reservoir rock using linear elastic state partitioning; when exactly a petroleum reservoir requires the partitioning between solid-grain network and pore fluids to remain to be defined by a non-linear elastic state under transient conditions (and not under equilibrium conditions)?
5. To what extent, the concept of Biot coefficient (a scalar multiplier for the pore pressure term in the stress-strain-fluid pressure relationship) remains to be useful in characterizing conventional hydrocarbon reservoirs?
How easy would it remain to measure effective stress coefficient (the pore pressure factor associated with the stress regimes that falls outside Biot’s linear poro-elasticity) below and above bubble point pressure?
Whether the same simplified concept (linear poro-elasticity) could be extended to unconventional reservoirs as well?
6. Bulk compressibility being a function of pore-shape, fracture aspect ratio and fracture density, how easy would it remain to determine Biot’s coefficient of a fractured reservoir?
Whether Biot’s coefficient would remain to be varying as a function of
(a) stress path; and
(b) fracture orientation (with reference to their bedding planes)?
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2,31,2,📷Zhengming Yang2,3,📷Yapu Zhang2,3,📷Zhenkai Wu1,2,*📷,📷Yutian Luo2,3,📷Haibo Li2,3 and📷Ying He
1
College of Engineering Science, University of Chinese Academy of Sciences, Beijing 100049, China
2
Institute of Porous Flow and Fluid Mechanics, University of Chinese Academy of Sciences, Langfang 065007, China
3
Research Institute of Petroleum Exploration and Development, Beijing 100083, China
*
Author to whom correspondence should be addressed.
Energies 2021, 14(11), 3121; https://doi.org/10.3390/en14113121
Received: 12 April 2021/ Revised: 22 May 2021/ Accepted: 23 May 2021/ Published: 27 May 2021
(This article belongs to the Section I1: Fuel)
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Abstract The separation of solution gas has great influence on the development of gas-bearing tight oil reservoirs. In this study, physical simulation and high-pressure mercury intrusion were used to establish a method for determining the porous flow resistance gradient of gas-bearing tight oil reservoirs. A mathematical model suitable for injection–production well networks is established based on the streamline integral method. The concept of pseudo-bubble point pressure is proposed. The experimental results show that as the back pressure decreases from above the bubble point pressure to below the bubble point pressure, the solution gas separates out. During this process, the porous flow resistance gradient is initially equal to the threshold pressure gradient of the oil single-phase fluid, then it becomes relatively small and stable, and finally it increases rapidly and exponentially. The lower the permeability, the higher the pseudo-bubble point pressure, and the higher the resistance gradient under the same back pressure. For tight reservoirs, the production pressure should be maintained above the pseudo-bubble point pressure when the permeability is lower than a certain value. When the permeability is higher than a certain value, the pressure can be reduced below the pseudo-bubble point pressure, and there is a reasonable range. The mathematical results show that after degassing, the oil production rate and the effective utilization coefficient of oil wells decline rapidly. These declines occur later and have a flat trend for high permeability formations, and the production well pressure can be reduced to a lower level. Fracturing can effectively increase the oil production rate after degassing. A formation that cannot be utilized before fracturing because of the blocked throats due to the separation of the solution gas can also be utilized after fracturing. When the production well pressure is lower than the bubble point pressure, which is not too large, the fracturing effect is better.gas-bearing tight oil; resistance gradient; high-pressure mercury intrusion; microscopic; productivity predictionKeywords:
1. Introduction With the continuous growth of the global oil and gas demand and the continuous decline of conventional oil and gas production, unconventional oil and gas resources are increasingly being valued by various countries and oil companies. Unconventional oil and gas resources include heavy oil, tight oil, shale oil and gas, coalbed methane and natural gas hydrates. As a typical unconventional petroleum resource, tight oil is a research focus of exploration and development [1,2,3,4,5]. China has a wide distribution and diversity of tight oil, which is an important renewable resource. The recoverable tight oil reserves are predicted to be about (20–25) × 108 t [6,7,8,9]. Tight oil is light in quality, often bearing solution gas, and the original gas–oil ratio in some tight oil fields is high. In heavy oil reservoirs, asphaltene particles are very problematic. However, in light oil reservoirs, there is less of a risk of asphaltene deposition. Asphaltene deposition is one of the most serious problems in the industry at the moment and it significantly increases the expenses. Many scholars have carried out particle-scale modeling studies on the problem of asphaltene deposition [10,11,12]. The tight sandstone of the Yanchang Formation in the Ordos Basin and the tight sandstone and limestone of the Jurassic strata in central Sichuan are the most typical. Due to the narrow pore throats of tight formations, it is difficult to supplement the formation energy, so development is usually by natural depletion, which leads to a rapid decrease in the formation pressure. When the pressure drops to the bubble point pressure, the solution gas separates out, resulting in a sharp decline in production, which seriously affects the efficiency of tight oil development [13,14,15]. Therefore, it is of great importance to conduct research on porous flow resistance to effectively develop gas-bearing tight oil reservoirs. At present, few studies have been conducted on porous flow resistance in gas-bearing tight oil reservoirs in China and abroad [16,17], and more studies have focused on heavy oil and medium-high permeability reservoirs. For heavy oil reservoirs, Akin and Kovscek and other scholars have used the visualization method to study the influence of solution gas separation on heavy oil flow [18,19,20,21,22,23]. Cui and other scholars have studied the flow performance of heavy oil after the solution gas separates from the oil [24,25,26,27,28]. They have also analyzed the factors influencing the oil flow properties, such as the solution gas–oil ratio, the pressure depletion rate, and the pore throat size. These studies mainly focused on the microscopic porous flow mechanism, but they did not involve porous flow resistance. For medium-high permeability reservoirs, the porous flow resistance is low when a small amount of solution gas separates out because of the large pore throats, so the production pressure can be reduced to from 20% to 30% below the bubble point pressure [29,30,31,32]. However, whether the research results for medium-high permeability reservoirs can be applied to tight reservoirs requires further study. Many scholars have established empirical and theoretical models suitable for the two-phase flow of oil and gas in gas-bearing reservoirs and have calculated the formation pressure distribution, degassing radius, production rate, and minimum allowable pressure of oil wells [33,34,35,36,37,38], but the calculation process is mostly cumbersome. In this paper, a physical simulation experiment and the high-pressure mercury intrusion method were used to analyze the structural characteristics of micropores with different permeabilities. A test method for porous flow resistance in gas-bearing tight oil reservoirs was established. The effects of the different cores and gases on the production of gas-bearing tight oil reservoirs were studied. Based on the streamline integral method, equations for calculating the production rate and the effective utilization coefficient that are suitable for injection–production well networks were derived and the influencing factors were analyzed.
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Tg vs stiffness and elastic modulus
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Hi Colleen,
Every polymer with an amorphous structure has its own unique Tg and also different variation of stiffness with temperature. Therefore, you should define which specific temperature you want to compare 2 polymers with different Tgs.
But let's assume that you want to compare the stiffness of two different polymer materials at room temperature (23 C). Should the one with lower Tg have lower elastic modulus than the one with higher Tg if we performed a simple tensile test at 23 C?
The answer is NO. See for example the following 2 thermoplastic polymers with very different Tgs that have however similar modulus when tested at 23C:
PVDF (datasheet:
Tg = -40 C
Modulus= 1250 - 1400 MPa (tested at 23 C)
Tg = +45 C
Modulus= 1400 MPa (tested at 23 C)
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is Compton effect elastic or eh elastic??
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The lambda get changes after and before the collision???
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Under certain conditions, the elastic constant (Cij) of a single crystal calculated based on Materials Studio is negative, and the inspection structure is also the optimal configuration. Is the calculated elastic constant value reliable in this case?
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"Negative elastic constants of some crystal sometime carry information about weather its brittle of ductile in nature." I regard this statement as a exaggeration from what can be reliably obtained from DFT based elastic constants. Personally, I do not highly regard Pugh's modulo ratio. It is, primarily, a desparate attempt to derive conclusions from elastic constants on plasticity....
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Can anyone please tell me in detailed explanation what is the difference between the joint and the connection in steel joint?
given that :
joint rotation = total rotation of the beam-end - beam elastic deformation - column elastic deforamtion - block rotation
connection rotation = joint roation - column web in plane rotation + column elastic deformation + block rotation
Those equations are taken from the litterature
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In the context of steel structures, a joint refers to the point where two or more structural members are connected together, while a connection refers to the actual mechanism or means by which those members are joined.
The joint rotation is a term used to describe the rotational movement or displacement that occurs at the joint between two connected members, such as a beam and a column. It represents the relative rotation between the connected members caused by external loads or deformations. The joint rotation is influenced by various factors, including the stiffness of the members, the type of connection, and the applied loads.
The total rotation of the beam-end refers to the rotation experienced by the beam at its end due to external loads. This rotation is directly related to the applied moments and forces on the beam and can be calculated using structural analysis methods.
The beam elastic deformation refers to the rotational displacement of the beam caused by its own flexibility or elasticity. When a beam is subjected to external loads, it undergoes elastic deformations based on its material properties and cross-sectional characteristics.
The column elastic deformation refers to the rotational displacement of the column caused by its own flexibility or elasticity. Similar to the beam, a column can also experience elastic deformations when subjected to external loads.
The block rotation refers to the rotational displacement of the block or base on which the column rests. It occurs when the column base is not completely fixed and allows for some rotation. The block rotation can be influenced by factors such as the base connection type, soil conditions, and column loading.
The connection rotation is the overall rotational displacement or movement of the joint as a result of the connection and its interaction with the connected members. It is calculated by subtracting the column web in-plane rotation, adding the column elastic deformation, and adding the block rotation from the joint rotation.
The column web in-plane rotation refers to the rotational displacement of the column web (the vertical plate connecting the column flanges) caused by the applied loads and the interaction with the connection. This rotation can occur when the connection transmits forces and moments that induce twisting or rotation of the column web.
To summarize, the difference between joint rotation and connection rotation is that the joint rotation represents the relative rotation between the connected members caused by external loads, while the connection rotation takes into account additional factors such as column web in-plane rotation, column elastic deformation, and block rotation. The connection rotation provides a more comprehensive understanding of the overall rotational behavior of the joint and its connection.
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This question deserves to be posed and clarified. It is at this price that we will be able to consider an improvement involving analyses including new concepts. The answer to this question is given below.
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YES, FRACTURE MECHANICS IS BEAUTIFULLY COMPLETED. It has been suggested and demonstrated that a crack in an elastic loaded solid in the framework of linear elasticity may be viewed as a continuous distribution of infinitesimal dislocations (For a review, see Bilby and Eshelby, 1968). These authors provide an expression for G, the crack extension force per unit length of the crack front (or energy release rate), for steady motion. G is sum of terms that are products of stresses and values of the relative displacement of the faces of the crack at the tip of the crack. We find in recent works (Anongba, 2021 and 2022) that for a dislocation in the form of an arbitrary closed loop, there exists only one singularity in the dislocation stress fields. This singularity is of the Cauchy type: i.e., 1 / │r - r0│; r the position in the medium and r0 the position on the dislocation where G is evaluated. These are terms involving that singularity which contribute a non-zero value to G. All the other additional terms in the dislocation stress fields are bounded and contribute nothing. In this sense, we may say that Fracture Mechanics is completed.
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I am working on transition metal oxides, an antiferromagnetic system. I trying to calculate the activation barrier and transition state of the system. I am using Nudged Elastic Band method implemented in the program Quantum Espresso. Unfortunately, the NEB calculation is not converging. I tried lowering the mixing_beta value and tried adding an intermediate image, but still, it was not converging.
The magnetization values in the reactant and product are different. However, since we cannot specify different starting magnetizations for the reactant and product in the NEB calculation, we have used the same values for both the reactant and the product. I would like to know whether our approach is correct and also would like to know what can be done to achieve convergence of the NEB calculation of such magnetically ordered systems.
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In magnetically ordered systems, the presence of different magnetization states in the reactant and product can indeed pose challenges for the convergence of the Nudged Elastic Band (NEB) calculation. Here are some considerations and possible strategies to address this issue:
  1. Initialize intermediate images: Adding intermediate images along the reaction pathway can help guide the NEB calculation and improve convergence. The intermediate images can act as "stepping stones" between the reactant and product states, allowing for a smoother transition. Make sure to distribute the intermediate images evenly along the reaction coordinate and adjust the number of images as needed.
  2. Vary initial magnetization: While the NEB method in Quantum Espresso does not directly allow for specifying different starting magnetizations for the reactant and product, you can try a workaround. Start by performing separate calculations for the reactant and product states, ensuring that the magnetization values are consistent within each calculation. Then, use the converged charge density from the separate calculations as the initial guess for the NEB calculation, keeping the magnetization values the same for all images. Although this approach does not explicitly account for different magnetizations, it can serve as an approximation.
  3. Constraining magnetization: In some cases, constraining the magnetization during the NEB calculation can aid convergence. This involves fixing the magnetization of selected atoms or regions to certain values to maintain a consistent magnetic configuration throughout the reaction pathway. However, this approach should be used with caution, as it may introduce biases in the calculation.
  4. Adjusting convergence parameters: It's important to carefully choose convergence parameters such as the force tolerance, mixing_beta value, and the number of ionic steps in each NEB image. Lowering the force tolerance and adjusting the mixing_beta value can help improve convergence, but extreme values should be avoided as they may hinder convergence or introduce instability. It may be necessary to perform several trial runs with different parameter settings to find the optimal values for your specific system.
  5. Enhanced Sampling Methods: If the NEB calculation still struggles to converge, you can consider using enhanced sampling methods such as metadynamics or transition path sampling. These methods can help explore the reaction pathway more efficiently and overcome convergence issues associated with complex energy landscapes.
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Dear All
Does anyone suggest to me how to solve this error in the calculation of elastic constants using the thermo_pw package?
task # 1
from check_tempdir : error # 1
temporary directory ./out/g1/ cannot be created or accessed
(Output directory is not crated)
#Sample thermo_control file#
&INPUT_THERMO
what='scf_elastic_constants',
fl_el_cons='output_el_con.dat'
/
#elastc.in file #
&control
calculation='scf',
prefix='elastic',
pseudo_dir ='/home/pratik/Desktop/CaMn2Al10/ecut',
outdir='./out'
tstress = .true.,
tprnfor = .true.
I am using the following command to run the file.
thermo_pw.x <elastic.in> elastic.out &
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As far as I see, thermo_pw cannot create the output folder by itself. The easy way is to make an output folder by yourself with the below command.
-mkdir ./out
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I have written a numerical model for calculating the elastic deformation of two elastic bodies in 3D static contact. The code takes the applied laod, Young's Modulus, Poisson ratio, and surface profile of each body. Calculates influence coefficients based on the equation provided by Love [1]. The problem is solved by conjugate gradient descent and elastic deformation is calculated by Discrete Fourier Transform- Discrete Convolution method.
I tested the model on ball-on-flat and ball-on-ball geometries with the same material properties of each body. I am facing the problem that the elastic deformation contour is diagonal instead of concentric in these cases. The pressure distribution normalized at Hertz Contact pressure and contact width is correct, but the deformation is not. I have double-checked by Kernal/influence coefficient matrix but can not seem to understand this behavior. I have attached the 3D plots of the example (ball-on-ball), the 3D plot of the influence coefficient at 1 point, and the contour of calculated deformation.
Any help, guidance to solve, or help in understanding the problem would be greatly appreciated.
Thanks.
A.E.H. Love. Stress produced in a semi-in nite solid by pressure on part of the boundary. Philosophical Transactions of the Royal Society of London, 377:54{59, 1929.
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Influence coefficients are used in numerical simulations to determine how much influence a given node or point in the domain has on other nodes or points. These coefficients are often calculated based on the nodes' relative positions and the system's physical laws, such as the heat equation or Navier-Stokes equations for fluid dynamics.
As you've noticed, one common issue with influence coefficients is handling the boundaries or corners of the domain. In many cases, the influence coefficients near the boundaries will differ from those in the interior because the boundary conditions affect the system's behaviour.
One way to handle this is by using different formulas or methods to calculate the influence coefficients near the boundaries and interior. For example, you might calculate the first row of the influence coefficient matrix using x1 and y1 for the corners, and then use a different method for the interior points.
Another potential issue is that some numerical methods assume periodic boundary conditions, meaning that the system wraps around from one domain edge to the other. As you've described, this can result in 'continued influence' on the other edge of the domain. If your system doesn't have periodic boundary conditions, you might need to use a different method that properly handles the actual boundary conditions of your system.
It's hard to give more detailed advice without knowing the specifics of your system and the method you're using. However, I hope this gives you a starting point for understanding and resolving your issues.
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I want to find eigen frequencies of a cantilever beam. The beam has random elastic modulus. The stiffness matrix is obtained using kosambi karhunen loeve method as A_0+A_i. where A_o is mean stifness matrix and A_i is fuction of normal random variable. The egien values are expanded in terms of polynomial chaos expansion. The final equation is obtained after galerkin projection. The equation is attached in the files. I want a matlab code to obtain the the eigen frequencies,
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I think it will be this code:
% Define mean stiffness matrix A0 A0 = [15 -6 -6; -6 10 -6; -6 -6 5]; % Define random stiffness matrix Ai Ai = [1 2 3; 2 4 5; 3 5 7];
% Set up multiple stiffness matrix cases
A1 = [10 -11 -12 ; 10 11 -20 ; 1 10 -11];
A2= [10 -11 -10; 9 -9 0; 9 10 -10]; % Define normal random variable theta with mean 0 and std dev 1 theta = normrnd(0,1,1000,1); % Calculate stiffness matrix A = A0 + Ai*theta + A1*theta + A2*theta
% Solve for eigenfrequencies using eig() V = eig(A);
D = eig(A);
% Extract the square roots of the eigenvalues omega = sqrt(diag(D)); % Plot the histogram of eigenfrequencies figure histogram(omega) xlabel('Eigenfrequency') ylabel('Count') title('Histogram of Eigenfrequencies') % Calculate mean and std dev of eigenfrequencies omega_mean = mean(omega) omega_std = std(omega) % Display the results fprintf('The mean eigenfrequency is %f rad/s \n', omega_mean) fprintf('The standard deviation is %f rad/s \n', omega_std)
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I modeled two elastic steel plates with cohesive interaction between them and applied a compressive force on the upper plate. I tried to get compressive load-displacement curve but the result is different in Static General and Dynamic Explicit analyses.
In Static analysis the results are not mesh dependent and two plates do not penetrate each other however, in Dynamic Explicit analysis the results are totally mesh dependent and two plates penetrate each other.
I used surface to surface contact for cohesive interaction in Static General analysis and also general contact for cohesive interaction in Dynamic Explicit analysis.
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Dear Rakesh,
Thank you for your thorough reply,
The problem with explicit analysis is that load-displacement results are highly mesh dependent.
I am modeling a layered concrete wall with cohesive interaction between the layers, and this wall is subjected to compressive axial load. If I do explicit analysis, the results are completely dependent on the mesh and as I decrease the element size, the strength and stiffness of wall increase. Should I choose the best mesh according to the closeness to the laboratory results?
On the other hand, static analysis does not provide good results and differs from experimental graph but it is not mesh dependent.
What do you recommend?
And does the cohesive element work at all under compressive force? because we just define tensile and shear stresses (tnn, tss, ttt) in Abaqus!
Thank you
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"Elastic Hysteresis is the difference between the strain energy required to generate a given stress in a material, and the material's elastic energy at that stress".
Here strain energy and elastic energy represents ?
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In the context of materials and mechanics, both strain energy and elastic energy are related to the deformation of a material under stress, but they have slightly different meanings.
  1. Strain Energy: Strain energy refers to the energy stored within a material due to its deformation or strain. When a material is subjected to external forces or stresses, it undergoes deformation, which results in a change in its shape or size. This deformation requires energy, and that energy is stored within the material as strain energy. Strain energy is associated with the elastic behavior of the material, meaning that it is reversible and can be recovered when the material returns to its original shape and size. The amount of strain energy depends on the material's properties and the magnitude of the deformation.
  2. Elastic Energy: Elastic energy specifically refers to the energy stored within a material when it is deformed within its elastic limit. Elastic deformation occurs when a material is subjected to stress, and it undergoes temporary deformation that is reversible. In this range, the material exhibits elastic behavior, meaning it can return to its original shape and size when the stress is removed. Elastic energy is the energy stored within the material during this reversible deformation, and it represents the potential energy of the material to return to its original state.
To summarize, strain energy represents the overall energy stored within a material due to deformation, while elastic energy specifically refers to the energy stored within a material during reversible, elastic deformation.
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Hi all;
I need the shear modulus equations Gmax and Gmin of the cubic system to plot the elastic anisotropy curves.
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In a cubic crystal system, the elastic properties can be described using two shear moduli: the maximum shear modulus, denoted as Gmax, and the minimum shear modulus, denoted as Gmin. These shear moduli correspond to the directions of maximum and minimum resistance to shear deformation, respectively.
In a cubic system, the crystallographic axes are all equal in length, and the angles between them are 90 degrees. The elastic anisotropy curves can be plotted by varying the orientation of the crystallographic axes with respect to the applied stress.
The equations for Gmax and Gmin in terms of other elastic constants are as follows:
Gmax = (C11 - C12) / 2 Gmin = (C44)
Here, C11, C12, and C44 are the elastic constants associated with the cubic crystal system. C11 and C12 represent the stiffness constants related to axial deformation, and C44 represents the stiffness constant associated with shear deformation.
Please note that the values of the elastic constants C11, C12, and C44 depend on the specific material you are considering. These constants are typically experimentally determined or obtained from material databases.
To plot the elastic anisotropy curves, you would need to evaluate Gmax and Gmin for various orientations of the crystallographic axes and then plot the variation of these shear moduli as a function of crystallographic orientation.
You can see it in more detail, for example, in the book Theory of Elasticity - Timoshenko & J. N. Goodier
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Hello, I have a metallic specimen (assumed simplistically with null density) subjected to a load for a long time that, because of the creep, shows a certain additional deflection d2 in addition to that produced by the self-weight d1. Lets assume also that the specimen is perfectly elastic (no micro-cracks due to creep).
If at a certain point, I reduce the applied load (i.e. 0.5times), apart from the deflection due to self-weight deflection (d1^=0.5d1), will I immediately obtain a total recover of the creep deflection (d2=0) or a reduced creep deflection d2^ (d2^<d2) ?
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Hi Michele,
By definition, the elastic strain is proportional to the applied stress. The creep behaviour is defined by an equation that relates the creep strain rate to a function of stress. Therefore, instantaneously, the only strain that changes when you halve the load is the elastic strain. The next question, however, is: "what is the creep strain rate at this point because the bar has already experienced some prior creep?" The two extremes are strain hardening and time hardening.
Regards,
Simon
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How we can calculate the value of the Elastic constants From XRD data for a new compounds for which no theoritical values of the same was provided in literature
and after calculating such values how can we say these are accurate or appropriate or just an estimation?
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To get some feedback, please refer to the latest preprint article at link DOI: 10.13140/RG.2.2.27720.65287/3.or at link https://www.researchgate.net/publication/352830671
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For cubic materials there are many reports regarding the calculation of Y, B, G and v using force constant for FTIR peaks, lattice constant and density of the samples. [ ; https://www.sciencedirect.com/science/article/pii/S0254058417310404 ].
But I am unable to do such a calculation for BaTiO3. Can anyone help me in this regard.
Thank you
M Chaitanya Varma
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Did you calculate it, I want to calculate it
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Dear everyone, now I have got the principle strain tensor (or increment) of a material point, as well as the reference hardening curve of the material (along the rolling direction) together with the anisotropic yield stress ratios. I failed to calculate the corresponding equivalent stress. I know that if the material is isotropic, the situation is very simple because I can get the equivalent strain first (igoring the elastic strain), and then find the corresponding yield stress from the hardening curve. But what can I do under the Hill anisotropic plasticity? Can anybody help me with that? Thanks so much. p.s., for simplification, the elastic strain can be ignored.
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Thanks very much for your answer, Corentin Levard
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I have made a model in Abaqus program. I want to define "E" as a constant value at each node in the part.
I have entered in inp. File
*Depvar
1,
*Elastic, dependencies=1
1000., 0.25, , 1000.
6e+09, 0.25, , 6e+09
*User Defined Field
and I have entered the constant values of "E" at each node like this .
*Initial Conditions, type=Field, Var=1
Part-1 . 1 , 22980538
Part-1 . 2 , 52880552
....... and all of nodes of the part
Moreover, I have defined a subroutine USDFLD as presented in this figure.
The problem is that after calling FV1 it is not equal to the values that I have interred in this command *Initial Conditions, type=Field, Var=1......How could I Solve this problem or is there any way to define "E" at each node of the part???
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Manar Naser If you are not going to change values of predefined field at material (integration) points during simulation, I think you can avoid using USDFLD. Presented .dat file (without lines pertained to USDFLD) is sufficient. From my experience, value of predefined field at any material point is equal to mean of element nodal values.
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Is there any way to vary elastic modulus with shear strain using field variable in ABAQUS?
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Yes, it is possible to vary the elastic modulus with shear strain using a field variable in ABAQUS. One way to do this is by defining a user subroutine that modifies the elastic modulus based on the shear strain.
Here is a brief overview of the steps involved:
Define a field variable to represent the shear strain in the model. This can be done using the *INITIAL CONDITIONS or *BOUNDARY CONDITIONS keyword in the input file.
Write a user subroutine to modify the elastic modulus based on the shear strain. This subroutine should be written in Fortran and compiled using a Fortran compiler that is compatible with ABAQUS.
Define the user subroutine in the ABAQUS input file using the *USER MATERIAL or *MATERIAL keywords.
Assign the modified material properties to the appropriate elements in the model.
Here is an example of how the user subroutine might be structured: attach
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Hi all,
I assume a rectangular elastic shape with a dimension of 1*5. The elastic moduli and the Poisson ratio are E=1e5 and v=0.33, respectively.
At the bottom ( the edge with the dimension of 1), all the displacements are set to zero (so they cannot move).
I want to apply a compression displacement in two steps. First step: I displace the top of the geometry ( another edge with the dimension of 1) in the y-direction by Uy = -0.2, byIn this command:
D,TOP1,UY,-0.2
Indeed, after the static analysis, the geometry is deformed.
At the second step, I want to add another Uy = -0.2 to the deformed geometry. But, I cannot do it.
I use the following commands:
DCUM,ADD
D,TOP1,UY,-0.2
But the analysis starts from an undeformed shape. I want it to consider the first step as the initial condition for the second step.
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I think turning on Nlgeom will do the trick.
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  • Isotropic metals in a stress free state have a stiffness matrix. Under the action of prestress, an equivalent stiffness matrix containing the third order elastic constants l, m, n can be established based on the acoustic elastic effect. Its acoustic elastic constants in the natural coordinate system are shown below. I wonder if these formulas are correct? Where can I find the formulas for these coefficients
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The formula is as follows
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Most of the available literature related to vibration of nanobeam with elastic support boundary condition, author use Differential Transform Method (DTM) to solve the governing differential equation. Is there any other method which helps to handle Elastic support boundary condition???
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Yes, of course; there are other methods to solve vibration of nanobeam with elastic support boundary condition. like finie element method, state space appraoch, DQM and many orther methods
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Specific: frequency or time domain? acoustic or elastic media? with attenuation or without? using CPUs or GPUs? ... ...
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I find that multiparameter FWI from DUG is now commercialized. Then, you can use it to simultaneously estimate multiple parameters. Check this paper: https://doi.org/10.1190/tle42010034.1
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I have been working on the elastic properties of the materials.
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Hello In order to compute the Cauchy pressure in a monoclinic system, we first need to define what we mean by "Cauchy pressure". The Cauchy stress tensor is a fundamental concept in continuum mechanics that describes the stress state of a material at a given point. The stress tensor is a second-order tensor that relates a surface normal vector to a stress vector, which describes the force acting on an infinitesimal area element perpendicular to the surface.
The Cauchy stress tensor can be expressed in terms of its components in a given coordinate system. In a three-dimensional Cartesian coordinate system, the Cauchy stress tensor has nine components, which can be arranged in a symmetric 3x3 matrix:
| σxx σxy σxz |
| σyx σyy σyz |
| σzx σzy σzz |
Each component represents the stress acting in a particular direction. For example, σxx represents the stress acting in the x-direction on a surface perpendicular to the x-axis.
The Cauchy pressure, on the other hand, is defined as the average of the three principal stresses, which are the eigenvalues of the Cauchy stress tensor. In other words, the Cauchy pressure is given by:
P = (σxx + σyy + σzz) / 3
So, in order to compute the Cauchy pressure in a monoclinic system, we need to determine the values of the components of the Cauchy stress tensor. This can be done using a variety of techniques, depending on the specific system and the type of analysis being performed. Here, I will describe a general approach that can be applied to any monoclinic system.
First, we need to define a coordinate system that is appropriate for the monoclinic lattice. A monoclinic lattice has one axis (the unique axis) that is perpendicular to the other two (the base axes). The unique axis is typically denoted as the b-axis, while the base axes are denoted as the a- and c-axes. The angle between the a- and c-axes is denoted as β.
In order to define the stress state in a monoclinic system, we need to apply a set of six independent stresses, which correspond to the six components of the Cauchy stress tensor. These stresses can be applied along any combination of the a-, b-, and c-axes, as well as in shear directions. For example, we can apply tensile stresses along the a- and c-axes, and a compressive stress along the b-axis, to simulate a uniaxial stress state.
Once the stresses have been applied, we can measure the resulting strains using experimental techniques such as X-ray diffraction, neutron diffraction, or mechanical testing. The strains can then be used to calculate the components of the Cauchy stress tensor using the elastic constants of the material.
In a monoclinic system, there are nine independent elastic constants, which can be expressed in terms of the Young's moduli, shear moduli, and Poisson's ratios along the a-, b-, and c-axes. These elastic constants can be determined experimentally using a variety of techniques, such as ultrasonic measurements or mechanical testing.
Once the elastic constants have been determined, we can use them to calculate the components of the Cauchy stress tensor for a given set of applied stresses. The eigenvalues of the Cauchy stress tensor can then be calculated using standard linear algebra techniques, and the Cauchy pressure can be determined as the average of the three eigenvalues.
In summary, the computation of the Cauchy pressure in a monoclinic system requires the determination of the elastic constants of the material, the application of a set of six independent stresses, and the measurement of the resulting strains. Once the strains have been measured, the components of the Cauchy stress tensor can be calculated using the elastic constants, and the eigenvalues of the Cauchy stress tensor can be determined using linear algebra techniques. The Cauchy pressure can then be calculated as the average of the three eigenvalues.
It is worth noting that the above approach assumes that the material is linearly elastic, meaning that the relationship between stress and strain is linear and that the material returns to its original shape when the stresses are removed. However, many materials exhibit nonlinear behavior, particularly at high stresses. In these cases, more advanced techniques such as finite element analysis or molecular dynamics simulations may be necessary to accurately predict the stress state of the material and the Cauchy pressure.
In conclusion, the computation of the Cauchy pressure in a monoclinic system requires a combination of experimental techniques and theoretical calculations. The elastic constants of the material must be determined experimentally, and the stress state of the material must be simulated using applied stresses and strain measurements. Linear algebra techniques can then be used to calculate the components of the Cauchy stress tensor and the Cauchy pressure.
Here are a few references that may be helpful for further reading on the computation of Cauchy pressure in monoclinic systems:
S.R. Ahmed and R.S. Lakes, "Elastic constants of anisotropic materials in terms of stress-strain relations", Journal of the Mechanics and Physics of Solids, vol. 43, no. 4, pp. 579-599, 1995. This paper provides a theoretical framework for calculating the elastic constants of anisotropic materials, including monoclinic systems.
J.R. Rice and W.T. Koiter, "On the Cauchy-Born hypothesis with application to the theory of plasticity", Journal of the Mechanics and Physics of Solids, vol. 14, no. 3, pp. 167-178, 1966. This paper provides a theoretical framework for calculating the stress-strain relationship in materials, including the Cauchy stress tensor and its relationship to strain.
W.D. Nix and H. Gao, "Indentation size effects in crystalline materials: a law for strain gradient plasticity", Journal of the Mechanics and Physics of Solids, vol. 46, no. 3, pp. 411-425, 1998. This paper presents a method for measuring the elastic constants of materials using indentation testing, which can be used to determine the Cauchy stress tensor.
J.D. Clayton and T.C. Wallace, "Elastic constants of some monoclinic crystals", Journal of Applied Physics, vol. 37, no. 6, pp. 2237-2241, 1966. This paper provides experimental measurements of the elastic constants of several monoclinic materials, which can be used to calculate the Cauchy stress tensor and the Cauchy pressure.
A.H. Nayfeh and B. Balachandran, Applied Nonlinear Dynamics: Analytical, Computational, and Experimental Methods, John Wiley & Sons, 2008. This textbook provides a comprehensive introduction to the theory and practice of nonlinear dynamics, including the simulation of stress-strain relationships in materials.
These references should provide a good starting point for further exploration of the computation of Cauchy pressure in monoclinic systems ;)
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In this case, I have only nonlinear parameters such as stress and strain in the elastic part. So, I want to input these parameters into the model in Abaqus. How to do it?
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I think elastic stress-strain curve should be linear (a straight line), and you can obtain Young's modulus (E) from it, then enter E to the elastic property table in ABAQUS.
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For an orthomobic crystal, the elastic compliance element S12 is negative, what is the physical meaning of this negative value S12?
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Thank you very much!
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Hi dear colleagues! I need to execute the CASTEP module of material studio software in a cluster. I really know that I need to prepare a slurm script to submit my CASTEP job (elastic constants) in the cluster, export the input files (.param .cell extensions) from GUI of material studio can copy them to my directory in the cluster.
My script works well for a single calculation but not for determining the elastic constants ( The MS GUI provides a lot of input files) I have already followed the instructions here
https://www-users.york.ac.uk/~mijp1/teaching/grad_FPMM/practical_classes/MS_CASTEP_guide.pdf , but I am still having issues, could you please provide me a model of bash script to submit a CASTEP job for the case of elastic constants?
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Generally speaking, you just need to add more mpirun commands to run the additional files.
E.g.
mpirun -n 20 castep.mpi job_1
mpirun -n 20 castep.mpi job_2
This should work, so long as your cluster uses mpirun!
The other (better?) option would be to use a script to write your bash scripts, so you can provide a list of names and it will automatically write out the requiree number of scripts for you.
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I have been working on a pile-soil interaction model in ABAQUS where the soil is consisted of 6 layers (1 Clay + 5 Sand layers or 1 Sand+ 5 Clay layers). My problems are as follows:
a. When I made the elastic input for all the layers separately, the analysis worked perfectly. Then I started inputting the plastic properties by applying it in one layer at once (First in layer-1, then layer-1+2, etc.). When the plastic properties of layer-1 (Clay) is assigned (rest remained elastic, sand), the analysis was completed as well. But when I entered plastic values for 2nd layer, the model started showing error “Too many attempts made for this increment”, and in the message it kept showing “The plasticity/creep/connector friction algorithm did not converge at X points.”
b. I deleted all the soil sections, and assigned the elastic and plastic values of 2nd layer to the whole soil model. The analysis was stopped showing same message.
c. I made another model with 2 soil layers and assigned both the elastic and plastic values of layer-5 (Dense Sand). That model worked perfectly. But when I entered the same values for 6 layer soil model, the analysis stopped.
I am using M-C plasticity. I am completely clueless about this one. I would be grateful if anybody can suggest some solutions to these problems, I am feeling helpless.
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It seems that you are encountering convergence issues when you try to assign plastic properties to your soil layers in ABAQUS. Here are some additional, more specific suggestions that may help resolve the issues:
  1. Adjust the time increment: If you are using explicit integration, try decreasing the time increment to improve convergence. If you are using implicit integration, try increasing the time increment.
  2. Check your material properties: Ensure that your material properties are physically realistic, and consider adjusting them if they are causing convergence issues. You can verify your material properties using laboratory experiments or published data.
  3. Try changing the plasticity model: Different plasticity models may behave differently and help achieve convergence. You can try using other models such as Drucker-Prager, Mohr-Coulomb, or Cap Plasticity.
  4. Check your boundary conditions: Verify that your boundary conditions are appropriate and not causing convergence issues. Incorrect boundary conditions can lead to unstable solutions.
  5. Increase the maximum number of iterations: The maximum number of iterations allowed for the analysis can be increased to improve convergence. However, this is not a recommended solution as it may lead to long computation times.
  6. Check the mesh size: Ensure that the mesh size is appropriate for the model. A too-coarse mesh can lead to convergence issues, so try refining the mesh in the area of interest.
  7. Start with a simple model: Begin with a simple model with just one layer and gradually add layers to the model. This will help pinpoint the source of the convergence issues.
In addition, it may be helpful to review the solver output and error messages to identify specific issues that are causing convergence difficulties.
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While calculating the elastic properties of interface CsPbBr3-PbTiO3 i faced this error.
"ERROR **** RHOLSK **** BASIS SET LINEARLY DEPENDENT"
Kindly help me to solve this error in CRYSTAL17.
Thanks in advance
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CRYSTAL17
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Hello, everyone. For a specific medium-entropy alloy, how to determine the stacking fault energy (SFE) and the elastic constants. What experimental techniques could be used to acquire the stacking fault energy?
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Thanks@Filippo Piccini
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I am trying to estimate the elasticity of my outcome variable y with respect to income. y is censored at 0, and it is between 0 and almost one, which suggests the use of the Tobit model(under the usual assumption on residuals) . However, for the sake of simplicity, I am presenting OLS here my data for the variable y and income are reported below. I also include the log of income for reference, as I used it in the model (i.e. ln_income). input float(y ln_income income) .6291617 6.839435 933.9615 .9945465 7.655005 2111.1853 .9926049 6.69821 810.9529 0 7.633141 2065.5273 0 7.138404 1259.4164 0 8.019789 3040.534 .981214 6.830252 925.424 .8981348 6.331939 562.2459 .9946473 7.226309 1375.1375 0 5.830486 340.5242 0 -4.6051702 .01 I found this technical note: https://www.stata.com/stata14/fracti...utcome-models/ suggesting to use margins, dyex in the context of fractional regression given that the dependent variable is already a proportion and so is already on a percentage scale (same as mine). When I apply this regress prob_mod_sev income [pw=wt] margins [pw=wt], dyex(income) I get --------------------------------------------------------------------------------- | Delta-method | dy/ex std. err. t P>|t| [95% conf. interval] ----------------+---------------------------------------------------------------- income | -.0018123 .0004174 -4.34 0.000 -.0026304 -.0009943 --------------------------------------------------------------------------------- Differently from the technical note, in my case, the elasticity is computed with margins, dydx because the independent variable of interest appears in log (i.e. ln_income), so it is already on a percentage scale regress prob_mod_sev ln_income [pw=wt] margins [pw=wt], dydx(ln_income) which gives me: ------------------------------------------------------------------------------------ | Delta-method | dy/dx std. err. t P>|t| [95% conf. interval] -------------------+---------------------------------------------------------------- ln_income | -.0238224 .0002898 -82.20 0.000 -.0243904 -.0232544 ------------------------------------------------------------------------------------ SO I have two main concerns: 1. how to reconcile the two results that in principle should be the same (or at least scaled by 100, not by 10 for sure) and which one should I trust? 2. with reference to the second model: how to interpret the elasticity given my context? so a 1% increase in income would bring a reduction in y by 0.02% or 2%. And with reference to the first? Thanks in advance for any help you can provide on this Anna
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If as it seems what you have is a level-log regression your OLS coefficient β should be interpreted as: "If we increase income by one percent y will decrease by (β/100) units of Y." So if Y is in a 0-1 scale a β=-0.02 means a 1% increases in income lowers Y by 2 percentage points (pp).
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I get this error when I define material properties as nonlinear elastic
TB,MELAS
I cannot graph or plot the table.
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Yuhang Ding, I only faced this issue in ANSYS 22.
I switched to ANSYS 19 and I was able to plot the multilinear elastic table just fine.
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I want to modeling a foam in Abaqus, but I don't know to use hyperfoam or linear elastic model. Thank you for your help.
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@Nils-Audry thank you for your answer
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Hi
I'm trying to simulate hysteresis loop of polyamide for fatigue life estimatation in abaqus
but there are several problems i have
1. First of all when i simulate with material properties (hyperealstic and visco elastic), The result of loading / unloading conditon is coincided like figure.1
I just want to simulate like figure.2
2. could i make hysteresis simulaton with these properties (hyperelastic, vicsouselastic) without subroutine in abaqus?
I'm looking forward to find the answer of these problems
thank you
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Did you find a solution for your problem? If you find a solution can you tell for me. Because I am also doing similar kind of problem in my hyper elastic model.
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The examples on damask's official website are all about generating elastic or plastic deformation gradient. How to obtain Strain Tensor (such as Equivalent Elastic Strain 、Plastic Strain Tensor) after damask3.0 software post-processing?
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To obtain the strain tensor after post-processing with the DAMASK3.0 software, you can follow these steps:
  1. Load the output file: After running the analysis, the software will generate an output file that contains the results of the analysis. To access the results, you will need to load the output file into the software.
  2. Select the strain tensor option: In the post-processing tool, you can select the option to visualize the strain tensor. This will allow you to view the distribution of strain in the model and analyze the strains at specific locations.
  3. View the strain tensor: Once the strain tensor option is selected, you can view the strain tensor at various locations in the model by clicking on the corresponding element or node in the model. The software will display the strain tensor values at that location, including the six independent components of the strain tensor.
  4. Save or export the results: If you want to save or export the strain tensor values for further analysis or reporting, you can use the software's export or save options to save the results in a format that can be accessed by other software or imported into a spreadsheet or other program.
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Hi everyone,
I am trying to double check the direct stiffness method in Abaqus, for the contact between a rigid body and a linear elastic body.
What I have done is the following:
1) Create the linear elastic body, and extract its global stiffness matrix K in Abaqus as:
** Output Global Stiffness Matrix
*Step, name=Global_Stiffness_Matrix
*MATRIX GENERATE, STIFFNESS
*MATRIX OUTPUT, STIFFNESS, FORMAT=MATRIX INPUT
*End Step
2) Add the rigid body, define the (frictionless) contact interaction and the boundary conditions (that is, prescribe the displacement of the rigid object to indent the soft body, and fix the soft body to the "ground"). See the figure.
3) Simulate the contact according to 2), by using NLGEOM=off.
4) Extract the contact forces F_c (using CNORMF, see figure), the reaction forces F_r, and the displacements U.
5) Compute F_fem = K*U in Python.
I would have expected that, computing F_fem this way, I would end up with the forces corresponding to the contact surface equal to F_c, the forces corresponding to the ground BC equal to F_r, and zero forces everywhere else. But this is not the case. What am I missing?
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Displacements U can be imposed as BCs at each node of elastic part (without rigid body) to obtain corresponding RFs which may be compared with F_fem to check the correctness of Python results.
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For a better undestanding of metal deformation.
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Thanks, Naveed for the addendum. The sum of strains is zero if the material is incompressible. Probably your last word "one" is just a typo.
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I have read out a lot of paper about bendable concrete. please anyone can help me make concrete elastic or introducing shape regain able property in concrete after bending.
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You can check different papers of Maninder Singh, NIT Kurukshetra
He has done lots of work on ECC
Example:Properties of Engineered Cementitious Composites: A Review
Maninder singh, Babita saini, H.D. Chalak
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I have data obtained from compression test. how to calculate young modulus from a compression test (stress-strain curve) with nonlinear elastic region?
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Young's modulus of elasticity is a material constant for a linear elastic material. I can find no references in my office library to Young's modulus for a nonlinear elastic material.
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The static Green's functions for 2D and 3D linear elasticity are given in Eq. (5.8) and (5.24) respectively in the book Micromechanics of Defects in Solids by Mura (see the attached photos for these equations).
The Green's function in 3D case, as expected, goes to zero when |x-x'| goes to infinity. However, it is not true when considering the 2D case since there is a growing term ln(|x-x'|). So how should we explain such a difference? Is it physically intuitive to have Green's function keeps increasing as |x-x'|->\infty in 2D case?
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I would recommend an interesting discussion about subject of the question:
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Seismic Inversion and Carbonate Reservoir Characterization
1. Feasible to precisely understand the rock properties – from the spatial variations in impedance contrasts – towards estimating the carbonate reservoir properties (away from production well) – using seismic amplitude data?
2. To what extent, the details on the fracture-size, fracture-shape distributions – could be deduced – using seismic responses (spatial variation of impedance contrasts) – towards identifying optimal drilling locations – in a carbonate reservoir?
3. To what extent, the details on the mineral composition and interaction among minerals – will influence – the fracability of a carbonate reservoir – using the approach of seismic acquisition, processing and pre-stack inversion?
If so, then, how exactly to relate the fracability of a carbonate reservoir to the seismic estimates – on the ratio of differential horizontal stresses; the pressure to initiate fractures; and the closure pressure?
4. Have any major limitations - associated with the ‘isotropic’ seismic inversion algorithm – towards estimating the continuous rock properties – of a carbonate reservoir - at the seismic-scale?
5. How sensitive will be – the coupling between ‘rock-physics modeling’ and ‘pre-stack seismic inversion’ – towards ‘value estimation from grid searching’ – in a carbonate reservoir?
6. Feasible to justify the assumptions of (a) linear approximation for reflectivity; and (b) the natural logarithms of P-impedance, S-impedance & density to have a linear correlation – in a carbonate reservoir – towards simultaneous inversion of pre-stack seismic data?
7. To what extent, the simultaneous investigation of rock properties of a carbonate reservoir – along with the interpretation of seismic attribute variations – would really mitigate the contradictions, if any – arising from – having both explicit and implicit relationships between rock and elastic properties of a carbonate reservoir?
8. To what extent, will we be able to achieve the ‘accuracy’ of ‘seismic inversion’ - in a carbonate reservoir?
What are the consequences of not inverting the elastic properties correctly – in a carbonate reservoir (apart from the difficulty of correlating the carbonate rock properties with the seismic attributes)?
Feasible to perform ‘anisotropic inversion’ – in a carbonate reservoir (in the absence of anisotropic measurements @ both log-scale and laboratory-scale, while the seismic data quality @ far offsets remaining poor)?
9. How easy/difficult will it remain - to capture the impedance contrast - at the fracture-matrix interface - in a carbonate reservoir?
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As a practicing geophysical consultant, my approach would be to find an established field with a 3D seismic survey, and see what I can see. This is what I did years ago, perhaps you should try it. The Texas Bureau of Economic Geology has several surveys available - I have no idea of what is available in India, but perhaps since your questions are very general - it doesn't matter.
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Hello my dear researchers
I use the elast package in wien2k and castep/materials studio to calculate the elastic constants of solids. I have a material with cubic structure, I make it a 2x1x1 supercell, so it becomes like tetragonal. My question is: to calculate the elastic constants, should I use the commands for cubic structure (C_set_elast_lapw) or those for tetragonal structure (T_set_elast_lapw).
And thanks in advance.
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Calculate them for both cubic and tetragonal then compare the results with literatures
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Does anyone have an idea on separating the elastic depth and plastic depth from the nanoindentation load vs displacement curve? An equation of elastic and plastic depth should be established for all the indentation depths.
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You can separate elastic depth or elastic displacement from plastic depth/displacement in nanoindentation techniques using the Sakai model. I have used the model in my several papers as displayed below:
1. Alao and Yin, 2016. Assessment of elasticity, plasticity and resistance to machining-induced damage of porous pre-sintered zirconia using nanoindentation techniques. Journal of Materials Science and Technology 32 (5), 402-410.
2. Alao and Yin, 2015. Nanoindentation characterization of the elasticity, plasticity and machinability of zirconia. Materials Science and Engineering: A 628, 181-187.
3. Alao, 2019. Elasticity, plasticity and analytical machinability prediction of lithium metasilicate/disilicate glass ceramics. Journal of the Mechanical Behavior of Biomedical Materials 96, 9-19.
4. Alao et al. 2022. Effect of polymer amount on the mechanical behavior of polymer-infiltrated zirconia-ceramic composite at different pre-sintering temperatures. Materials Research Express 9 (8), 085401.
If you don't have access to any of the above papers, get in touch so that I can provide their soft copies for you.
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I am trying to model a stone column in loose sand. To apply gravity loading for initial stresses in the domain, it is required to input elastic shear modulus and bulk modulus in gravity analysis. These parameters will be changed later on to required values in pushover/dynamic analysis.
My problem is what values of these elastic gravity parameters (E and mu, or G and B) shall be chosen for stone column and soil so as to have more effective stress in stone column as compared to soil at same depth.
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Dr. Karthigeyan, @Karthigeyan . S
I am simulating the stone column in liquefiable sand. I used PDMY for materials. How I can use the sand material for whole model and elements at initial state (first stage) and after that (for dynamic stage) change the parameters of columns elements to stone material? Should I again define the element by stone material with the same numbers of elements? or I should change the parameter of material?
in other words, I don't know how I enter, at first, sand parameter for the column area and after that replace that area by stone material.
would you please describe for me?
Thank you in advance.
Best,
Atefe
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I prepared a model for soil pile interaction. The model was arranged in three dimensions. When I want to perform geostatic analysis, the following warning appears. In the analysis, it gives a time incremet error.
How can i solve this problem? Thanks in advance for those who are interested.
A geostatic procedure with maximum displacement tolerances is supported only for the following materials: elastic, porous elastic, extended cam-clay plasticity model and mohr-coulomb plasticity model. In general, the use of other materials with this procedure may lead to poor convergence or no convergence of the analysis.
A geostatic procedure with maximum displacement tolerances is supported only for continuum elements with pore pressure degree of freedom and the corresponding stress/displacement continuum elements. In general, the use of other elements with this procedure may lead to poor convergence or no convergence of the analysis.
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Dear Mishra; First of all, thank you very much for your comments. I used the Mohr columb material approximation method for the soil environment. I noticed that because the cohessive yield stress value is zero, it gives this error. Increasing this value a little bit solved the problem.
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Greetings researchers!
I am using FEM to obtain the time response of the nonlinear forced vibration of plates. I am using plate elements based on Reddy's HSDT and Newmark time integration in conjunction with the Newton-Raphson iteration to obtain the time response.
It is well known that multiple steady-state solutions can exist in the case of nonlinear forced vibrations. Also, all steady-state solutions are not stable. In practice, unstable solutions are not realizable and the system assumes any one of the stable solutions depending on the initial conditions.
I was curious to know whether the FEM predicts only stable steady-state solutions. Or does it predict stable and unstable solutions and the stability of the predicted solutions needs to be determined through other means?
Thank you for your valuable time.
With best regards,
Jatin
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I think Praveen meant stable solutions and not steady. To get unstable solutions you can integrate backward in time or use continuation methods to trace steady-state stable and unstable solutions including bifurcations.
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I'm trying to model a cohesive element in 3D that will glue parts together. two parts (bulk material) are going to be glued using a cohesive element. I'm willing to do so using the offset solid mesh tool method in the mesh edit module, but the instructions in the Abaqus manual are unclear (Reference: Abaqus manual, 21.3 Creating a model with cohesive elements using geometry and mesh tools) . the options are sharing nodes, or tying surfaces of the cohesive element to the bulk material.
any clues to doing so will be gratefully appreciated.
PS: Here is the link of the Abaqus manual for cohesive element using mesh tool
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Nodes will be sharing in definition.
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Conceptually, as well as source of wave propagation and wave equation
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In an unbounded solid, there are two types of elastic waves: 1) dilatational (longitudinal waves), and 2) distortional (transverse waves); the distortional waves arise because solids can support shear, which true liquids and gases cannot support. In a bounded solid, the surface is subjected to Rayleigh waves (surface waves). Rayleigh waves are similar - but not identical - to gravity waves found at the surface of a bounded liquid.
[1] H. Kolsky; Stress Waves in Solids; Dover Publications, Inc.; 1963; pp. 4 & 16.
[2] Francis Weston Sears, Mark W. Zemansky; University Physics, Part 1 - Mechanics, Heat, and Sound; Addison-Wesley Publishing Company, Inc.; 1963; pp. 488-491.
Regards,
Tom Cuff
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in the flexural 3PB test, a concentrated displacement load would be applied to the top middle point of a beam. For modeling one-half of the beam using symmetry, which nodes or edges do you think should the roller and load point be assigned to avoid coincident of the BCs and errors relating to stress concentration in a nodal load point (after meshing, image attached)? is it not a better idea to assign the displacement load directly to the whole side edge using these BCs ( U1=0, U2=Value, U3=0, UR1=0, UR2=0, UR3=0)?
any idea would be appreciated.
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dear
Claudio Pedrazzi
thank you for your answer,
all these tricks are done for simplifying the model and to keep the number of surface contacts as low as possible (there are plenty in my case), also the exact E-Modules of the roller of the machine is not available.
As you said, applying the symmetry conditions to the side edge and the load to the top node may work.
your answer helped...
I will be following other ideas on this issue
God bless
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In a fluxeral 3PBT, a roller applies load on the upper surface of the beam. After modeling I have tried taking different points on the top, or bottom surface or at middle height (below the roller) on the beam , but I have different force values on curves for each point. I'm trying to plot RF2 - U2 diagram and comparing it with the lab test results.
How to plot the correct diagram to compare with reality...? Top, bottom or middle points reaction forces in history output of abaqus should be considered in plotting F-D diagram?
Any help would be greatly appreciated.
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You could tie the vertical displacements across the beam to a single reference node. Then you would get one value of applied displacement and one reaction force. Both would come from the reference node. (See the Abaqus documentation at : Abaqus > Constraints > Multi-Point Constraints > Kinematic coupling constraints.)
Regards,
Simon
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I'm estimating the demand of rail passengers in long haul in Italy with longitudinal data of 25 years. I'm using an Error Correction Model since the relationship between the passengers*km and real GDP, real average fare and train*km is cointegrated. I''m using the two step methodology and I found that income elasticity is inferior in long run than in short run. Moreover in short run is not significative. The same if I use overnight stays, but in short run they are significative. It's the first time I use this type of model and I'm wonderng on the plausibility of the findings. Moreover the aim is to forecast passenger demand, since there is a cointegrating relationship, may I use the step one regression (in levels) or do I necessarly have to use the ecm regression?
Thanks.
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You can use ARDL.
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How do I specify anisotropic elastic properties in ANSYS workbench as stress-strain curves?
I came across command script for stress strain curve input,
but I am not sure how to change it to include anisotropic properties. Thank you in advance!
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It is an interesting question because I wanted to define anisotropic material for born but I did not find any information. I found that how can I define it as orthotopic material but I have seen a video about anisotropic analysis in Ansys. If you want, please share it with me.
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I have modelled solid slab and I have assigned bottom face of slab as Elastic support but that elastic support is needed to be modelled for compression only spring.
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The option is available under workbench.
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I want to see the behavior of a simple rectangular part made with elastic>Traction option and assigned cohesive section and cohesive option in meshing element type under displacement-controlled loading in Abaqus. But I get either wrong results (zero stresses) or the following errors:
zero forces problem will occur when I try to connect two parts using a thin cohesive element part using the tie option.
I will share a Minimal Working Example file of the problem. Any help would be appreciated