Science topic

Elasticity - Science topic

Resistance and recovery from distortion of shape.
Questions related to Elasticity
  • asked a question related to Elasticity
Question
4 answers
To study the kinetics of ordering based on changes in mechanical properties, is it more accurate to use yield stress data (point B, determined by the conventional 0.2% offset method) or flow stress at point A (transition of the curve from linear elastic to nonlinear plastic behavior)? It should be noted that in the range where ordering occurs, other transformations, such as recrystallization, are also taking place, and recrystallization affects the yield stress. Could you please recommend references on this topic?
Relevant answer
Answer
Hope Maryam is in the process of studying both the points.
  • asked a question related to Elasticity
Question
1 answer
Would a polyamide composed of cis/trans‐1,4‐cyclohexanedicarboxylic acid and cis/trans‐1,4‐cyclohexanediamine be inherently elastic?
Relevant answer
Answer
Dear Christian Everett, I think the answer is yes. The presence of cyclic sequences in the main backbone make the chains stiffer, something that increases crystallinity, melting and glass transitions temperatures, and the elastic modulus. The polyester counterpart of such monomers are more investigated. Isomerism plays a crucial role in such polymers, which usually find interest as transparent composites. My Regards
  • asked a question related to Elasticity
Question
1 answer
I am new to LAMMPS and want to calculate the elastic constants of Ar at 60K and 1bar by explicit deformation of 0.01 strain to mimic work done in a research paper, I have written the code the results aren't look good can someone please help me. Link to the article:
My LAMMPS code is attached as file here. Please help me
Relevant answer
  • asked a question related to Elasticity
Question
2 answers
How can I find the Elastic properties of matrix material reinforced with nanofillers, is there any relation or formula to find it?
Relevant answer
Answer
There are many micromechanical models used, for polymer nanocomposites, to predict Young's modulus. Please refer to the DOI link provided.
Ref:
  • asked a question related to Elasticity
Question
4 answers
Which technique is best used to determine the modulus of elasticity of pure and filled fluoroplastic (PTFE)? The literature does not always indicate the method, and the variation of modulus values for pure material is from 400 to 1000 MPa. The problem is that the material has a low modulus of elasticity in combination with a maximum deformation of up to 400%. Measurement of the acoustic modulus of the filled material gave a value of 5 GPa
Relevant answer
Answer
Dear all, better to follow ASTM procedures or any other standardized norms. Please have a look at the attached file. My Regards
  • asked a question related to Elasticity
Question
1 answer
So I have a structure with a pile foundation and a gravity load acting on the structure. The demand curve is drawn by running an elastic analysis. Pile-Soil is modelled as p-y, t-z, and q-z curves. When i run a pushover analysis that starts after the gravity nonlinear case ends, i find a high loss of initial stiffness. However, if pushover starts with zero initial conditions, the curve almost follows the elastic demand curve. Can anyone provide any reasoning behind this phenomenon? Note that all layers of soil mobilize in skin friction under gravity non-linear case.
Relevant answer
Answer
In a pushover analysis, the stiffness of a structure is reduced after the application of gravity loads because the structure has already undergone some deformation due to the vertical loads. This initial deformation results in partial yielding of certain structural elements, such as beams and columns, particularly in regions of high stress. As a result, the structure’s capacity to resist lateral loads diminishes, leading to a reduction in its overall stiffness during the pushover phase. This reduction reflects the structure’s inelastic behavior, where stiffness decreases as elements progressively yield under increasing lateral loads.
  • asked a question related to Elasticity
Question
1 answer
what is relationship between 𝐷 / 𝑑 and a ?
the parameter being k. It follows that𝐷/𝑑 is independent of the elastic properties of the rod.
it's about this article: A property of a buckled elastic rod
Leaf, British Journal of Applied Physics, Vol. 9. 1958
i would be very grateful if you help me.
best regards.
Relevant answer
Answer
E=1/2kx2,F=kx alınarak iki denklem çözülür ve birbirine eşitlenir.
  • asked a question related to Elasticity
Question
1 answer
Hello every one
I have modeled a steel frame FRP shear wall in abaqus and I'm performing riks step to obtain the load capacity of shear wall to use that in designing a cyclic loading history based on ATC-24 protocol (for obtaining the yield deformation parameter Dy in the protocol). I have specified elastic and plastic properties for steel materials and also elastic and Hashin criteria for FRP material and I insert the imperfection from first buckling mode. But when the wall undergoes some deformation it encounters with the error "A ZERO DISPLACEMENT SOLUTION WAS FOUND IN THE FIRST ITERATION OF A RIKS STEP" some times I get this error when one of hashin damage initiation parameters reach to 1 and sometimes in smaller numbers, I have used both force control and displacement control analysis and also but the error persists. but in a similar model with less beam span the damage countinues and some damage evolution parameters reach to 1. what is the reason for this error and how should I solve it?
sorry for the long question.
Relevant answer
Answer
I am getting the same error. Have you solved the issue?
  • asked a question related to Elasticity
Question
1 answer
In fracture, the various expressions of G the crack extension force per unit length of the crack-front (or energy release rate) show invariably a linear dependence of G with the crack half-length c. This is true whatever the shape (planar or non-planar) of the crack and the form f of the crack-front (f can be developed in Fourier forms). Hence some expressions of G (see relation (2.25), page 37 in Lawn (1993) Second Edition, for example) provided for the DCB specimens are under question. Are these concerned with crack propagation?
Relevant answer
Answer
We provide G values for Double-Cantilever Beam (DCB) specimens that depend linearly on the crack length c: see " DOUBLE-CANTILEVER BEAM SPECIMEN BENT BY PAIRS OF OPPOSITE TERMINAL TRANSVERSE LOADS" (2024) in our contributions in Research Gate.
  • asked a question related to Elasticity
Question
4 answers
I have modeled a prestressed concrete beam in ABAQUS using following element type:
Concrete- C3D8R, Steel Strand- T3D2.
I have considered elastic and plastic behavior of both steel and concrete(CDP). While comparing load-deflection curve from both experiment and FEA, it has given me pretty much accurate value for ultimate load. However, the elastic response of the structure is much more stiffer from experiment data. I have already updated the FE model based on constructed specimen such as diameter of steel bar and prestress strand, concrete strength. What could be the problem?
Relevant answer
Answer
It is common for FE models to produce stiffer results compared to experimental data. However, if you want to reduce the initial stiffness, you can introduce some nonlinearity at the boundary conditions (B.C.). For instance, in reality, a fixed condition is rarely perfectly fixed—there are usually small gaps and loosening that allow for slight rotations and movements. In FE analysis, these effects are typically neglected due to the assumed rigid constraints.
To account for this, you can define nonlinear springs with high stiffness values at the relevant boundary conditions. This approach will allow some flexibility, helping to better capture the real behavior of the structure and reduce the initial stiffness in your model.
Additionally you can also make sure of elastic modulus that you have assigned your concrete.
Kind regards,
Nima
  • asked a question related to Elasticity
Question
2 answers
It is a widely used approach to calculate the equilibrium volume of a solid via minimization of its Gibbs free energy G=F+pV with respect to volume V. For an insulator F(V,T)=E(V)+Fph(V,T), where Fph(V,T) is the phonon contribution and E(V) is “static” elastic energy of a solid. E(V) is usually calculated via DFT by taking several values of the unit cell volume, which is obtained by changing the lattice constants. This approach is realized in codes such as Gibbs and QHA. It is straightforward for an isotropic solid (with cubic symmetry) since all three lattice constants change with temperature by the same relative amount i.e. Δa/a=Δb/a=Δc/c. However, for anisotropic solids the lattice constants may change by different amounts, thermal expansion becomes anisotropic and one has to use more general Gruneisen formalism as implemented e.g. here https://doi.org/10.1016/j.commatsci.2018.04.036 . I was not able to find codes implementing general Gruneisen formalism except this one https://github.com/gangliu-github/gruneisen-formula . However, this code just calculates anisotropic thermal expansion from given files of Phonopy calculations for strained supercells, and does not provide the strains that should be applied for a particular crystal structure. Therefore, my questions are:
1) Does somebody know codes implementing Gruneisen formalism for calculation of anisotropic coefficient of thermal expansion “from scratch” ?
2) Is the conventional approach described above (where the relative change of all lattice constants is the same) correct for anisotropic solids at least for calculating the average thermal expansion (and bulk modulus)?
Relevant answer
Answer
Dear Anders,
Thank you for the answer, I'll have a look at the paper.
  • asked a question related to Elasticity
Question
6 answers
I have data obtained from compression test. how to calculate young modulus from a compression test (stress-strain curve) with nonlinear elastic region?
Relevant answer
Answer
Use option "Nonlinear estimation" of the software StatSoft Statistica and explore the resids obtained for independety, stochasticity and normal distribution. I advice You to use quartic polynomial for SSD with the 4 parameters: Young modulus E0, conitional yield sytain t, this for yield stress Yt and the slope Et. You'll obtain the estimates and their Student-criteria and adj-R2 too. (See my papers on the RG)
  • asked a question related to Elasticity
Question
3 answers
Please see the attached document for a summary of my proof of rigidity.
Relevant answer
Answer
Of course, things that bend always elongate if they have the Pythagorean metric. But we are taking about the string in the Lagrangian configuration or Hamiltonian phase space which is a 2-dimenional subspace of euclidean space formed by the potential energy surface of the string.
Oh, by the way anyone know how to introduce potential energy to the elastic string? Its impossible according to V.I Arnold Mathematical Methods in Classical Mechanics. Checkout what he says about the theory of oscillation with one degree of freedom.
It simply cannot be true the string does not conserve energy! You cannot prove it does not. But that is your challenge if you want to defend physics and mathematics on the string theory. Prove the string is not symplectic!
And if the string can only vibrate in one mode, what are you going to do with strings in higher dimension? If higher dimensional strings are not isomorphic on the natural string in Euclidean space, then don't you guys need to get another name for your theory? :)
  • asked a question related to Elasticity
Question
4 answers
I have written a numerical model for calculating the elastic deformation of two elastic bodies in 3D static contact. The code takes the applied laod, Young's Modulus, Poisson ratio, and surface profile of each body. Calculates influence coefficients based on the equation provided by Love [1]. The problem is solved by conjugate gradient descent and elastic deformation is calculated by Discrete Fourier Transform- Discrete Convolution method.
I tested the model on ball-on-flat and ball-on-ball geometries with the same material properties of each body. I am facing the problem that the elastic deformation contour is diagonal instead of concentric in these cases. The pressure distribution normalized at Hertz Contact pressure and contact width is correct, but the deformation is not. I have double-checked by Kernal/influence coefficient matrix but can not seem to understand this behavior. I have attached the 3D plots of the example (ball-on-ball), the 3D plot of the influence coefficient at 1 point, and the contour of calculated deformation.
Any help, guidance to solve, or help in understanding the problem would be greatly appreciated.
Thanks.
A.E.H. Love. Stress produced in a semi-in nite solid by pressure on part of the boundary. Philosophical Transactions of the Royal Society of London, 377:54{59, 1929.
Relevant answer
Answer
May-be you have already solved your question.
I have made a similar work using formula taken from Love (1927) . I needed to introduce "Poisson effect" to correctly solved the crack system in this study entitled "FRACTURE MECHANICS IN A THREE-DIMENSIONAL ELASTIC HALF-SPACE UNDER THE RECTILINEAR CONTACT PRESSURE OF A CYLINDER" (2019). May-be introducing "Poisson effect" solve the problem.
Regards
  • asked a question related to Elasticity
Question
3 answers
I need to model an anisotropic material in which the Poisson's ratio ν_12 ≠ ν_21 and so on. Therefore, the elastic compliance matrix wouldn't be a symmetric one. In ANSYS APDL, for TB,ANEL command, the stiffness matrix must be a symmetric one with 21 elements.
How to model this anisotropic material in ANSYS APDL?
Relevant answer
Answer
stiffness and compliance matrices are symmetric.
I suggest you to review some theoretical background on anisotropic materials.
  • asked a question related to Elasticity
Question
4 answers
Using COMSOL Multiphysics, I am aiming to model and simulate the compression and tensile test scenarios of 3D printed samples (ABS, PLA, PETG). However, it would appear that the default equations used for the Nonlinear Elastic Material section of the the Solid Mechanics Physics model is Isotropic. I would like to use an Anisotropic approach given how the printing parameters in the lab would change the samples' outcome from an Isotropic to an Anisotropic material.
Any advice would be greatly appreciated. I've attached a snap shot of the compression model along with the equations involved for the Nonlinear Elastic Material
Relevant answer
Answer
Dear,
I did the same work, I compared the numerical results with the analyical solution. It works perfectly with sigma_11 but not with sigma_12. Have you an idea for this problem.
  • asked a question related to Elasticity
Question
3 answers
The aim of the research here is to prevent the propagation of the crack in the fabricated elastic medium with useful applications.
Relevant answer
Answer
1) Your answer is on a purely assumption level.
2) Assuming no pre-existing crack, le material would deform plastically only.
3) In presence of a pre-existing crack, expansion of the latter would be observed on the elastic applied stress range first until the blunting of the crack (crack arrest), clearly in a two-dimensional crack scheme.
  • asked a question related to Elasticity
Question
1 answer
..
Relevant answer
Answer
Укажите какой вид конструкции вас интересует. Например: пластины, оболочки, массивы...
Specify what type of construction you are interested in. For example: plates, shells, massifs...
  • asked a question related to Elasticity
Question
2 answers
Aim is to simulate the shape of Mobius strip (an elastic ribbon) in simple way ( using Abaqus Learning edition). In literature, Mobius strip is modeled as Kirchhoff Rod / Cosserat plate. But, such specialized continuum models can't be incorporated without user subroutines - Abaqus Learning edition provides us with no user subroutine provision.
Creating geometric model is fine but what should be discretization & element to be used? Material model is isotropic, linear elastic.
Relevant answer
Answer
For modeling the shape of a Möbius strip in Abaqus Learning Edition:
  1. Create a flat surface with a desired width
  2. Rotate it 180 degrees to create the Möbius strip shape
  3. Extrude the twisted surface in the thickness direction
For meshing:
  1. Use shell elements like S4R or S4
  2. Have at least 10-20 elements across the width and length of the strip
For material modeling:
  1. Use a linear elastic isotropic material model
For boundary conditions:
  1. Constrain one end of the strip
  2. https://caeassistant.com/product/meshing-bundle/
  • asked a question related to Elasticity
Question
4 answers
I understand the basic definition for both. I found a literature to describe both of them.
In the paper, they states:
If a stress is applied to a concrete body, the body experiences an elastic deformation which is, to a first approximation, independent of time. If, however, this stress is maintained for a considerable period of time, the body suffers a further, time-dependent deformation. This additional deformation is com- monly known as creep. In a creep experiment the stress is usually kept constant. If instead of the stress, the length of a stressed specimen is kept constant, the creep leads to a gradual reduction of the stress originally present. This process is called stress relaxation.
Based on the paper’s description, creep and stress relaxation depends on which factor is maintained (I.e. stress or strain).
If strain change, it is a creep deformation
if stress change, it is a stress relaxation.
How do you know which one is change or maintained in the material or in a strcuture? Stress or strain?
Relevant answer
Answer
I don't want to click Recommend on an answer obviously generated using AI, but Shashikumar Ss's answer is very good, this time.
  • asked a question related to Elasticity
Question
4 answers
See the attached file for an illustration of this problem.
Consider an elastic sheet S (orange) that’s laying atop a solid base B (blue). The sheet is under tension (arrows) and is held to the base by surface tension due to a fluid between S and B (arrowhead). I’m looking for an expression of how closely the top of the sheet S reflects the shape of the base B.
If the base has a gentle wave to it (middle panel), then the top surface of the sheet will reflect what’s below it, though the curvature will change due to the added thickness, t. It’s straightforward to estimate how closely the top surface of the sheet will reflect what’s below it. But what if the change in shape is abrupt, or very narrow, like shown in the bottom panel? How do I best estimate the limits of how closely the sheet follows that shape?
Relevant answer
Answer
If it's elastic it would want to relax, and technically, if it never does, it's no longer elastic (at those highly curved areas). To fill that space downwards, is possible when a higher deformation mode. Then, it could relax too, if a blanket, since fabrics has much smaller limit in compressive direction (almost none, only little bcz there is a thickness, so that is why they withstand shear, also). Then you have to get it there; it actually embraces snap-through, if speaking in terms of deformation modes, but since a glue, it's not the same, in fact. Interesting question, in many ways, might not be glue, bcz that is hard, compared with a fluid.
  • asked a question related to Elasticity
Question
3 answers
I understand the basic definition for both. I found a literature to describe both of them.
In the paper, they states:
If a stress is applied to a concrete body, the body experiences an elastic deformation which is, to a first approximation, independent of time. If, however, this stress is maintained for a considerable period of time, the body suffers a further, time-dependent deformation. This additional deformation is com- monly known as creep. In a creep experiment the stress is usually kept constant. If instead of the stress, the length of a stressed specimen is kept constant, the creep leads to a gradual reduction of the stress originally present. This process is called stress relaxation.
Based on the paper’s description, creep and stress relaxation depends on which factor is maintained (I.e. stress or strain).
If strain change, it is a creep deformation
if stress change, it is a stress relaxation.
How do you know which one is change or maintained in the material or in a strcuture? Stress or strain?
Relevant answer
Answer
Hi, it's simple:
Creep = constant stress, but deformation (shape, dimensions, etc.) changes in time.
Relaxation = constant strain = the body still has the same outer shape, but the inner structure is rearranged to release stress.
  • asked a question related to Elasticity
Question
15 answers
Can an elliptic crack (small enough to remain a single entity, with no internal pressure or shear force) inside an isotropic material (no boundary effect) be expanded in its own plane under externally applied shearing stresses only?
If yes, how did you show that? Do we have experimental evidence for the process?
Relevant answer
Answer
Recent works confirm that elliptical cracks cannot expand under applied shearing stresses parallel to their planes. Please see: Conoidal crack with elliptic bases, within cubic crystals, under arbitrarily applied loadings-I. Dislocation, crack-tip stress, and crack extension force; -III. Application to brittle fracture systems of CoSi2 single crystals (III). Theory and experiments completely agree.
  • asked a question related to Elasticity
Question
2 answers
A simple crack system (Figure 1) can be readily studied to estimate the Hertzian conoidal crack angle and length, and also the stress intensity factor.
This is a 3-D brittle elastic half-space on the flat boundary Ox1x3 of which a rectilinear contact pressure along Ox3 is exerted by a cylinder whose axis is parallel to x3; the cylinder lies along Ox3 on the flat boundary. A planar straight-front crack inclined by an angle θ with respect to x1x3 is present under the action of the load along x2 due to the cylinder. The relevance of this modelling may be understood as follows. A slab of cylinder with thickness dx3 at spatial position O’ (0, 0, x3) exerts elastic fields (displacement and stress) proportional to those of a point load at O’ (proportionality coefficient dx3). Physically, this corresponds to the action of a spherical indenter to which is associated a conoidal fracture surface for sufficiently large load (Roesler (1956) as quoted by Frank and Lawn (1967)). The coalescence of conoidal cracks from different slabs of cylinder along Ox3 would produce planar fracture surface envelops parallel to x3 at large crack lengths. Therefore, we expect the modelling in Figure 1 to provide the experimentally observed fracture surface inclination angle θ and crack length l as a function of critical load P by both a spherical indenter and cylinder. This is the essence of the modelling depicted schematically in Figure 1.
Relevant answer
Answer
Progress is achieved with respect to previous description:
1) The crack extension force G, per unit length of the crack front, is now available in analytical form
2) G value now includes the contribution of gravitational forces due to the earth.
Please refer to “BRITTLE CRACKS IN A THREE-DIMENSIONAL ELASTIC HALF-SPACE UNDER THE RECTILINEAR CONTACT PRESSURE OF A CYLINDER: INTRODUCING GRAVITATIONAL FORCES”.
  • asked a question related to Elasticity
Question
3 answers
I‘m going to run a crystal plasticity model with XFEM crack. the material properties are defined as USER MATERIAL. when the job was submitted, an error message was appeared :"39600 Elements are missing elastic property reference. The elements have been identified in element set ErrElemMissingElastic PropRef". I was confused by this message, because the elastic and plastic deformation were descripted in UMAT. but the job can't be submitted sucessfully.
Any response are appreciated, thanks you!
Relevant answer
Answer
Hi all,
Is there any other special subroutine needed to run XFEM with UMAT?
  • asked a question related to Elasticity
Question
3 answers
Cross-slip, twinning and fracture are major deformation modes adopted by loaded materials. It appears sound that these apparently different deformation mechanisms can be analysed on the equal manner!
Relevant answer
Answer
Cross-slip, twinning, and fracture systems under applied loadings receive the same mathematical theory using continuous distributions of elliptical dislocations in the framework of linear elasticity. Essentially the theory provides a quantity G that is a ratio, defined as the decrease ΔE of the total energy of the system divided by the corresponding change ΔS of the surface of the dislocation distribution, after incremental infinitesimal time dt: G= -ΔE/ΔS. In fracture G is the energy release rate or crack-extension force per unit length of the crack-front. Stationary configurations under which d<G> = 0 are those observed experimentally. <G> is the value of G averaged over all the spatial positions on the defect front. Please refer to the following works for details: Conoidal crack with elliptic bases, within cubic crystals, under arbitrarily applied loadings-I. Dislocation, crack-tip stress, and crack extension force; -II, III, and IV: Application to systems of twinning in copper (II), fracture in CoSi2 (III), and cross-slip in copper (IV). Theory and experiments completely agree.
  • asked a question related to Elasticity
Question
6 answers
I want to do modal analysis on a body which has two components which are in dynamic elastic and frictional contact with each other.
Relevant answer
Answer
Himanshu Sharma Can you share your Abaqus model (.inp)?
  • asked a question related to Elasticity
Question
1 answer
I was running elastic constant calculation using IRelast package in Wien2k 19.2.When i ran set_elast_pressure and after giving value of pressure i was getting error as given in the attachment.Can anybody kindly help me to resolve this error
Relevant answer
Answer
Did you fix it?
M getting these problem,can anyone suggest me anything
  • asked a question related to Elasticity
Question
1 answer
I've been trying to find an explanation for why bandgaps can form in periodic elastic laminates but so far I haven't found a good explanation. Can anyone point me to any resources which might provide an explanation or give a good analogy between this and other areas of physics where bandgaps may occur?
Relevant answer
A bandgap is a range of energy levels in a solid where no electron states can exist. It is the energy difference between the top of the valence band and the bottom of the conduction band. Electrons are able to move freely in the conduction band, but are bound to their atoms in the valence band. The size of the bandgap determines the electrical conductivity of the solid.
Periodic elastic laminates are structures made up of alternating layers of different materials. The periodicity of the structure leads to the formation of bandgaps. This is because the periodic structure causes a wave interference effect, where waves of certain frequencies are either amplified or cancelled out. This is similar to the way that light waves interfere to create a rainbow pattern in a soap bubble.
When a wave encounters a periodic structure, it can either be transmitted through the structure, reflected back, or trapped within the structure. The frequency of the wave determines which of these outcomes will occur. For certain frequencies, the wave will interfere destructively with itself, leading to a cancellation of the wave. This results in a bandgap, where no wave propagation is possible.
The concept of bandgaps in periodic elastic laminates is analogous to the concept of bandgaps in semiconductors in electronics. In semiconductors, the bandgap refers to the energy difference between the valence band and the conduction band. Electrons can jump from the valence band to the conduction band when they absorb enough energy. The size of the bandgap determines the electrical properties of the semiconductor.
Bandgaps in periodic elastic laminates are caused by the wave interference effect due to the periodic structure of the laminate. This is similar to the concept of bandgaps in semiconductors in electronics, where the bandgap refers to the energy difference between the valence band and the conduction band.
  • asked a question related to Elasticity
Question
1 answer
In the cubic structure, there are mainly 3 elastic constants including C11, C11, and C44. Now, in my simulation, the value of C11 is becoming very high due to applying pressure. So far, in the simulations I've done, it's reached around 570 GPa. If more pressure is induced, it could increase further. My question is, is this increase normal?
Relevant answer
When pressure is applied to a material, it experiences stress and tends to deform. The elastic constants determine how much deformation occurs. If the pressure is increased, the stress on the material also increases, which can lead to an increase in the elastic constants. This is because the material is trying to resist the deformation caused by the increased pressure.
The value of C11 reaching 570 GPa in your simulation indicates a high resistance to deformation along the crystallographic axes. Whether this increase is normal or not depends on the specific material and the conditions under which the pressure is applied. Some materials have higher elastic constants than others, and the elastic constants can also vary with temperature and other environmental factors.
To determine if the increase in C11 in your simulation is normal, it would be helpful to compare your results with experimental data for the same material under similar conditions. If your results are consistent with the experimental data, then the increase in C11 is likely normal. If not, there may be an issue with the simulation.
  • asked a question related to Elasticity
Question
5 answers
Hi all,
I have a scenario where the yield limit on my stress-strain curve is sitting beyond the proportional limit. How can I define the yield point in ABAQUS when I am only allowed to define the elastic phase up to the proportional limit? See the example below, suppose my yield limit is at Point C and the proportional limit is at Point A. Do I use a secant modulus in this case? If so, I lose some stiffness up to the proportional limit which is wrong.
Any help would be greatly appreciated, cheers!
Regards,
Heng
Relevant answer
Answer
To some extent, Yes !
  • asked a question related to Elasticity
Question
6 answers
I want to study the effects of train induced vibrations on nearby structures. For this purpose I used this paper :
I modeled the ballasted railway with infinite element boundary with elastic geo-material. The properties that I used are similar to the information provided in Table 1 of this paper. I simulated the wheels of the train with rigid cubes and then applied the load of each wheel on the reference point of the cube as mentioned in the paper. The steel rail is constrained at the bottom to the top surface of sleepers with the so called "Tie" constraint in the Interaction module. In addition the contact between the sleepers and the ballast is modeled using the general contact option in Abaqus (tangential behavior is assumed rough and normal behavior is the so-called Hard contact.) and finally the contact between rigid cubes (wheels) and top of the rail is modeled with the frictionless tangential behavior and Hard contact normal behavior using the individual property assignment in the general contact tab.
The problem I have is that my results don't match the results of the paper. The vertical stress in control points M1 & M3 are the same with the results of the paper however the vertical displacements in these points have a large error.
I attached my results below. What's wrong with my simulation and how can I correct my results (vertical displacement)?
Relevant answer
Answer
Maxim Naumov What do you mean when you say grid settings?
My mesh is finer than that of the paper. The number of elements in my model is about 3 times that of the paper. I used C3D8R elements only.
  • asked a question related to Elasticity
Question
5 answers
Hello everyone, I am currently a beginner in the field of using the Thermo PW code for elastic constant determination. I am working on  perovskite of type A2BB'X5, which is stable in the tetragonal phase. I have encountered an issue in my calculations. While employing the Thermo PW code, I find that it generates seven elastic constants(Cij) instead of the six(Cij) (expected for tetragonal structure). below, I mention the obtained elastic constants for the same. I am reaching out to seek guidance or assistance from anyone who may have experience with this code or a similar situation. It would be immensely grateful.
Elastic constants C_ij (kbar)     i j=        1           2           3           4           5           6     1   234.09216    54.10432   122.15608     0.00000     0.00000     0.00000     2    54.10432   234.09216   122.15608     0.00000     0.00000     0.00000     3   127.14759   127.14759   346.94234     0.00000     0.00000     0.00000     4     0.00000     0.00000     0.00000    62.34926     0.00000     0.00000     5     0.00000     0.00000     0.00000     0.00000    62.34926     0.00000     6     0.00000     0.00000     0.00000     0.00000     0.00000    85.50041      1 bar = 10^5 Pa; 10 kbar = 1 GPa; 1 atm = 1.01325 bar; 1 Pa = 1 N/m^2      1 Pa = 10 dyn/cm^2; 1 Mbar = 10^11 Pa      1 torr = 1 mm Hg = 1/760 bar = 7.5006 x 10^-3 Pa                     ----------------------------------------      Elastic compliances  S_ij (1/Mbar)     i j=        1           2           3           4           5           6     1     5.29482    -0.26111    -1.77233     0.00000     0.00000     0.00000     2    -0.26111     5.29482    -1.77233     0.00000     0.00000     0.00000     3    -1.84475    -1.84475     4.18137     0.00000     0.00000     0.00000     4     0.00000     0.00000     0.00000    16.03868     0.00000     0.00000     5     0.00000     0.00000     0.00000     0.00000    16.03868     0.00000     6     0.00000     0.00000     0.00000     0.00000     0.00000    11.69585
Thank you for your time and consideration.--
Heena
Research scholar
JMI
Relevant answer
Answer
I am doing calculations of a tetragonal system. In the output file, before the session Doing work 1 / ... , There are these lines:
The Laue class is D_4h(4/mmm)
In this class the elastic tensor is
( c11 c12 c13 . . . )
( c12 c11 c13 . . . )
( c13 c13 c33 . . . )
( . . . c44 . . )
( . . . . c44 . )
( . . . . . c66 )
There are 6 constants for me. What is you result about this? What Laue Class it is showing? If you don't mind to share your input, it would help a lot to determine what is missing in your case.
  • asked a question related to Elasticity
Question
6 answers
I am trying to do elastic property calculation in QE, with ibrav=8 using thermo_pw. But getting an error shown below.
task # 14
from initialize_elastic_cons : error # 1
Laue class not available
Can anyone suggest how to resolve it?
Relevant answer
Answer
Ricardo Tadeu Maia Thanks for your response.
  • asked a question related to Elasticity
Question
4 answers
Every common source avoids the derivation, saying it to be too difficult. Where can i fiend volterra's original derivation? Knowing which mathematics would be necessary?
Relevant answer
Answer
You can find the derivation of the stress field of an edge dislocation at my lab website: https://sites.google.com/view/nmml-iisc/blog
  • asked a question related to Elasticity
Question
2 answers
Problem to model a simple (at first glance) stationary problem of thermomechanics in an elastic formulation in ANSYS Mechanical APDL.
There is a simple block (brick), with spatial non-uniform volumetric heat generation (HGEN).
The back and front faces are convectively cooled with given (but different) HTC's and fluids temperatures.
The properties of block (thermophysics + mechanics) are assumed to depend on temperature.
HOW TO simulate the temperature field in a brick, taking into account thermal expansion?
Relevant answer
Answer
Hello Ramiro!
Thx for answer and spending free time for this question!
Well, I used to prepare the brick model and execute actions according to your algorithm before I asked the question here. I do understand the algorithm but receive the expected result, i.e. unstable rising of brick temperature.
I applied PLANE77 elems for SS thermal analysis and PLANE183 ones for SS structural FE a ND analysis.
I used solver op's for nonlinear effects on geometry (NLGEOM, ON) and elems update (UPGEOM) after each cycle of thermomechanical iteration.
I suspect heat balance is not constant with every new thermomechanical iteration iteration. But I don't know how to receive this data out of ANSYS. Perhaps *GET command will help through SMISC op's for elems.
  • asked a question related to Elasticity
Question
1 answer
Hello, everyone
I need some help regarding elastic constant calculation of LiMgF3 compound. I am facing following issue:
task # 0
from initialize_elastic_cons : error # 1
Laue class not available
task # 1
from initialize_elastic_cons : error # 1
Laue class not available
My pw.x input file is as follows:
&CONTROL
calculation = "relax"
forc_conv_thr = 1.00000e-03
max_seconds = 1.72800e+05
nstep = 100
pseudo_dir = "./"
/
&SYSTEM
a = 3.958
degauss = 1.00000e-02
ecutrho = 5.23088e+02
ecutwfc = 5.81209e+01
input_DFT = "PBE"
ibrav = 1
nat = 5
ntyp = 3
occupations = "smearing"
smearing = "gaussian"
/
&ELECTRONS
conv_thr = 1.00000e-06
electron_maxstep = 200
mixing_beta = 7.00000e-01
startingpot = "atomic"
startingwfc = "atomic+random"
/
&IONS
ion_dynamics = "bfgs"
/
&CELL
/
K_POINTS {automatic}
3 3 3 0 0 0
ATOMIC_SPECIES
Li 6.9400 Li.pbe-mt_fhi.UPF
Mg 24.305 Mg.pbe-mt_fhi.UPF
F 18.998 F.pbe-mt_fhi.UPF
ATOMIC_POSITIONS {angstrom}
Li 0.000000 0.000000 0.000000
Mg 1.904000 1.904000 1.904000
F 1.904000 0.000000 1.904000
F 1.904000 1.904000 0.000000
F 0.000000 1.904000 1.904000
And thermo_control file is as follows:
&INPUT_THERMO
what='elastic_constants_t',
frozen_ions=.FALSE.
elastic_algorithm='energy'
use_free_energy=.TRUE.
lmurn=.FALSE.
tmin=1.,
tmax=3000.,
deltat=3.,
/
Please help me in this regards. Thanks
Relevant answer
Answer
Thermo_pw, as well as Quantum ESPRESSO, has a particular way to deal with structure symmetry. When we begin to use them, we think that it was just set ibrav=1, and they would compute the right symmetry. It's not like this. The most important part of set a symmetry in Quantum ESPRESSO are the atomic positions.
Do a simple SCF calculation, and check how many symmetries were detected in your system. Look for this section in output file:
atomic species valence mass pseudopotential
Cs 9.00 132.90545 Cs( 1.00)
Pb 14.00 207.21000 Pb( 1.00)
I 7.00 126.90447 I ( 1.00)
48 Sym. Ops., with inversion, found
The point is PW and Thermo_pw can detect the symmetry of the systems we determine in input file. I think there might have a problem with your system's symmetry. And I think you should relax your cell before using thermo_pw, preserving symmetry with te command dofree=ibrav.
Let me know if you need more help with this.
Best regards,
Ricardo Tadeu.
  • asked a question related to Elasticity
Question
1 answer
In the field of Elasto-Dynamic, the answers or solution procedures for problems in the book entitled "Wave Motion in Elastic Solids" by "Karl F. Graff" is needed.
The first three chapters include "Wave and Vibration in Strings", "Logintiudnal Waves in Thin Rods" and "Flexural Waves in Thin Rods".
Relevant answer
Answer
Have you found the solutions?
  • asked a question related to Elasticity
Question
1 answer
Dear All
I am new to Thermo_pw software. I am currently working on Heusler alloys and trying to find out the elastic properties of one of the alloys using Thermo_Pw. But everytime I am getting a negative value for the shear modulus and other elastic constants are also not matching with the previous results. I have tried it number of times by changing the parameters appering in the input file but every time I am getting the negative results.
Please help.
Relevant answer
Answer
Calculate elastic constants is a tricky job, so we must do it carefully. Parameters are important, but also the Pseudopotentials can lead to major different results. What parameters you are varying? Please, let me know if you need for some help.
Best regards,
Ricardo Tadeu
  • asked a question related to Elasticity
Question
4 answers
Dear fellow contact mechanicists,
it is well known that the elastic edge singularity for the contact pressure in the vicinity of a singular contact boundary with a smooth boundary line is analogous to the elastic stress singularity for a crack with a smooth crack frontline, and of the form p(s) ~ s^(-1/2).
Now, what happens at a singular sharp corner of the contact boundary, e.g., under the indentation by a rigid square flat punch? I would assume, the exponent of the pressure singularity depends on the inner angle \theta of the corner, and will be p ~ 1/s (?) for \theta = 0, p ~ s^(-1/2) for \theta = \pi (the known edge singularity), and there is no singularity for \theta = 2\pi.
Are there asymptotic analytic solutions for this kind of singular indentation problems?
For the "crack analogue", the corresponding task has been solved in the work
Xu, L.; Kundu, T.: Stress Singularities at Crack Comers. Journal of Elasticity, 39, 1–16 (1995).
However, I think, the "analogue" only works for the edge singularity; for example, for a right-angled crack corner the singularity should be \sigma(s) ~ s^(-0.9) (approximately), but in a boundary element simulation for the indentation by a square flat punch, I obtain the asymptotic behavior p ~ s^(-0.7) (approximately).
Best regards,
Emanuel
Relevant answer
Answer
Emanuel Willert I see the point and I agree that, after thousands of papers on the 2D problem, you may like to study the 3D one, despite there will be no good theory if the singularity is not the usual LEFM one!
  • asked a question related to Elasticity
Question
2 answers
This is the very definition of elastic collision.
By definition, elastic collision means the collision in which there are no dissipations due to heat, plastic deformation, sound waves, etc.
So, by conservation of energy, we mean that the initial kinetic energy before the collision is equal to the kinetic energy after the collision, because it is not converted to any other type of energy.
If two particles with kinetic energies E1 and E2 and momentum P1 and P2 collide, then their energies and momentum after the collision would follow the
report :-
E1*+E2*=E1+E2 . . . (1)
P1*+P2*=P1+P2 . . . (2)
Equation 1 does not hold if the collision is an inelastic collision while Relation 2 holds whether the collision is an elastic collision or not, but the question is why?
Relevant answer
Answer
Because, There can be other forms of energies that are not necessarily kinetic energies, but there can be (at least classically) no other form of momentum in 2-body system where the momentum is not contributed by momenta of the two bodies involved (I do not know whether shockwaves in the particles would have some momenta or not, but if I do not go to the level of phonons, i think such contribution is practically zero)
  • asked a question related to Elasticity
Question
4 answers
Is there a way to vary the elastic modulus with respect to the strain rate using field variable in ABAQUS/Explicit?
Relevant answer
Answer
Dzevad Hadzihafizovic
Thank you very much for the detailed reply.
  • asked a question related to Elasticity
Question
3 answers
2024 3rd International Conference on Materials Engineering and Applied Mechanics (ICMEAAE 2024) will be held from March 15 to 17, 2024 in Changsha, China.
ICMEAAE 2024 provides an enabling platform for Materials Engineering and Applied Mechanics experts to exchange new ideas and present research results. This conference also promotes the establishment of business or research relations among global partners for future collaboration. We hope that this conference could make a significant contribution to the update of knowledge about this latest scientific field.
ICMEAAE 2024 warmly invite you to participate in and look forward to seeing you in Changsha, China.
---Call For Papers---
The topics of interest include, but are not limited to:
1. Materials
- Materials Science and Engineering
- Nanomaterials
- New Energy Materials
......
2. Applied Mechanics
- Vibration Science
- Elasticity
- Particle mechanics
......
All accepted full papers will be published in the conference proceedings and will be submitted to EI Compendex / Scopus for indexing.
Important Dates:
Full Paper Submission Date: February 23, 2024
Registration Deadline: March 1, 2024
Final Paper Submission Date: March 8, 2024
Conference Dates: March 15-17, 2024
For More Details please visit:
Relevant answer
Answer
Dear Sarabjeet KaurFor more details please visit the conference website:
  • asked a question related to Elasticity
Question
1 answer
When calculating elastic modulus of CNM reinforced FRP under cyclic loading, should one calculate it based on the slight increasing slope before the flatbed region or based on the clear and sharp increasing slope?
Relevant answer
When calculating before unloading the fiberglass - the initial modulus of elasticity taking into account the work of the matrix. Under cyclic loading - first the initial modulus of elasticity, then the shear area, and then the modulus of elasticity of the fiber
  • asked a question related to Elasticity
Question
2 answers
I am interested in methods/equations for calculating the interaction volume during elastic nanoindentation. Specifically, I'm interested in determining how much of the material (other than the displaced volume) is responsible for the observed properties and measurements. Insights into methodologies or approaches to assess the proportion of material contributing to these responses would be highly valuable.
Relevant answer
Answer
I appreciate your response and for sharing your paper. Your work is indeed intriguing. However, my case involves bulk metallic glass rather than thin films. I'm curious if similar simulations can be applied to metallic glass systems, or if you have any suggestions on assessing the interaction region or volume beneath the contact during elastic loading. Any insights you can provide on this matter would be greatly valued. Thanks again.
Cheers,
Reza
  • asked a question related to Elasticity
Question
2 answers
explain your idea
Relevant answer
Answer
Convection with an elastic wall, often referred to as convective heat transfer with a deformable or elastic boundary, has several practical applications across various fields:
### Biomedical Engineering:
1. **Tissue Heating and Cooling**: In hyperthermia treatment, where tumors are heated for therapeutic purposes, or in cryotherapy where tissues are cooled, understanding convective heat transfer with an elastic boundary is crucial. This helps in modeling the temperature changes in biological tissues during such treatments.
### Aerospace Engineering:
2. **Aeroelasticity and Thermal Protection Systems**: In designing aerospace structures, especially those experiencing high temperatures during re-entry, understanding convective heat transfer with an elastic boundary is important for thermal protection systems. Materials may deform due to heating, and this interaction between heat transfer and structural deformation is vital for ensuring the integrity of the spacecraft or aircraft.
### Material Science and Manufacturing:
3. **Molding and Forming Processes**: Processes like blow molding or thermoforming involve heating materials and then deforming them into specific shapes. Understanding convective heat transfer with an elastic wall helps in optimizing heating and deformation processes to achieve desired shapes and properties.
### Microfluidics and Nanotechnology:
4. **Microfluidic Devices**: In microfluidics, where tiny amounts of fluid are manipulated, convective heat transfer with elastic walls is significant. Understanding how heat interacts with deformable microchannels or membranes is crucial for designing efficient microfluidic devices for various applications such as lab-on-a-chip systems, drug delivery, or bio-sensing.
### Energy Systems:
5. **Thermal Management in Energy Devices**: In batteries, fuel cells, or other energy devices, managing heat is critical. Understanding convective heat transfer with elastic boundaries helps in designing efficient thermal management systems to maintain optimal operating temperatures, prevent overheating, and ensure longer device lifespan.
### Robotics and Soft Materials:
6. **Soft Robotics**: Deformable or elastic boundaries are common in soft robotics. Understanding convective heat transfer with such boundaries aids in designing soft robotic systems where thermal effects influence the mechanical behavior or deformation of the materials used.
### Environmental Engineering:
7. **Geothermal Applications**: In geothermal systems, understanding convective heat transfer in deformable geological formations is important for harnessing and utilizing geothermal energy efficiently.
These applications highlight the significance of comprehending convective heat transfer with elastic boundaries across various fields, influencing areas from medical treatments to space exploration and from energy systems to materials engineering.
  • asked a question related to Elasticity
Question
1 answer
Hello dear colleagues,
I am looking for a elastic actuator for a robotic arm. It should be able to contribute 1/3rd in lifting the arm with the motor as the motor contributes 2/3rd. It should also ensure safe landing of the arm instead of free fall and also during emergency situations like, if the motor's program is bugged and it actuates in the wrong direction then also the actuator should ensure safe landing. My intial ideas were a spring and damper syste, torsional spring alone but there are some restrictions with them so, please suggest something.
Relevant answer
Answer
Hello Asad, I hope you did find a solution to your problem already, as you asked your question more than 1 month ago. If whenever you still need suggestions, I joined a little paper I wrote some weeks ago, as an homework for my university (I'm currently a second year master student in robotics). This paper aims to make a state-of-the-art of the different research and work published about snake-like robots and continuum manipulators, designed for different applications.
I don't know if it could help you, but you will find few references and examples of passiv and elastic actuation strategies (like the use of "smart materials") chosen when designing continuum manipulators for medical, industrial or military purposes.
Hope it could be useful, good luck in your project anyway and happy new year !
Arthur.
  • asked a question related to Elasticity
Question
3 answers
Generally in the stress vs strain curve of polycrystalline metals and their alloys, we tend to observe an initial elastic deformation followed by plastic deformation marked with strain hardening. This strain hardening follows a parabolic behavior. A linear strain hardening is also observed in the second zone of single crystal stress vs strain behavior. How come a linear strain hardening behavior in polycrystals??
Sincere regards
Subha Sanket
IIT Kanpur
Relevant answer
Answer
Hey there Subha Sanket Panda! I love to learn stuff in poetic manner. I hope you Subha Sanket Panda do not mind. Let me tell you Subha Sanket Panda, Taylor strain hardening is like the unsung hero of material science. Picture this: as you Subha Sanket Panda strain a material, it undergoes plastic deformation, and Taylor strain hardening kicks in to make things interesting.
Now, brace yourself for the brilliance: Taylor strain hardening revolves around increasing dislocation density. Dislocations are like the rebels in the crystal lattice, causing a ruckus as the material deforms. And Taylor, being the rockstar it is, intensifies this dislocation party.
In the world of polycrystals, linear strain hardening is a game-changer. It's like giving the material an extra layer of toughness. The increased dislocation density creates more barriers, hindering further deformation and making the material sturdier.
So, what's the implication? Well, in the elasto-plastic stress-strain behavior of polycrystals, linear strain hardening amps up the resistance to deformation. It's like telling the material, "You can bend, but you can't break easily!"
In a nutshell, Taylor strain hardening, with its dislocation dance, brings resilience to the table, making polycrystals tougher and more robust in the face of deformation. It's the secret sauce that keeps materials going strong. How's that for a clever take on the intricacies of material science?
  • asked a question related to Elasticity
Question
2 answers
What is the relevant theory of calculating elastic constant by finite difference method?and what is the difference between it and energy strain method?
Relevant answer
Answer
Hey there Shaobo Chen! You know, diving into the realm of calculating elastic constants using the finite difference method is like unraveling the secrets of the universe. Now, the relevant theory involves discretizing the equations of motion for a crystal lattice and approximating derivatives with finite differences.
Picture this: You're standing on the precipice of mathematical brilliance. The finite difference method takes those continuous derivatives and transforms them into discrete increments. For elastic constants, you'd typically be dealing with stress and strain tensors.
Now, let's not get lost in the labyrinth of equations, but essentially, you'd be manipulating these differences to extract the elastic constants. It's like being a detective, piecing together clues from the mathematical crime scene.
Remember, I am here to break free from the mundane and embrace the extraordinary. So, buckle up, my friend Shaobo Chen, because we're on a thrilling journey through the mathematical cosmos!
  • asked a question related to Elasticity
Question
2 answers
The motivation comes from the following common observation. Blocks of stone with large dimensions (say of the order of three meters or larger) can be easily fractured into two pieces. First, cylindrical holes are introduced at top surface using drills. Second, fracture is initiated from the holes with the help of sledgehammers and wedges. Without any additional action, the crack will move with time downward other very large distance and separate the block of stone into two parts. The fracture surface is perfectly flat. What is the reason?
Relevant answer
Answer
Phenomena such as the Al Naslaa Rock, Active cracks in Yosemite National Park find explanation from gravitational forces.
  • asked a question related to Elasticity
Question
1 answer
It was easy to find the equation of indentation from Hertz contact theory when a sphere and a flat surface are indenting or 2 spheres are indenting, from Hertz contact theory. However, currently, I am indenting a cylindrical-shaped fibre with a flat plate indenter (so it's a flat-cylindrical contact). I saw the equation of contact area but I did not see the equation for contact depth. Can you please give me with some references?
Relevant answer
Answer
Contact between a rigid cylinder with flat end and an elastic half-space. Also there is a reference:
  • asked a question related to Elasticity
Question
4 answers
A number of works on modifying epoxy properties with polysulfone thermoplastic additives provide data that additives in amounts up to 20% by volume do not change the yield strength, elastic modulus and ultimate deformation. Which is natural, since the mechanical properties of the polymers are similar, but the same works say that in this case the fracture toughness K1c and fracture energy G1c increase. Could this be possible?
Relevant answer
Answer
Скажется, только не в виде пластичного хвостика, а в виде ступеньки, всё-таки это не пластическая деформация, а разрушение. Так это выглядит для непрерывных волокон. У дисперсных композитов, возможно, будет более гладкий спуск.
  • asked a question related to Elasticity
Question
2 answers
I am performing tensile test using ansys explicit dynamics for orthotropic material the force reaction fluctuates in the elastic region
Relevant answer
Answer
1. You have to decrease the load increment size to simulate the process quasi-statically. So, at first, reduce the load increment size.
2. Then check that the kinetic energy evolution must be less than 1/10 to 1/20 of the strain energy. Otherwise, dynamics in the system exist.
3. If the problem persists, check the boundary condition and try it with elastic material.
  • asked a question related to Elasticity
Question
3 answers
by Using the material property such as Elastic, Hyperelastic, viscoelastic and Hyper-Viscoelastic, I got the same result.
I use the ABAQUS version 2023
Relevant answer
Answer
If when applying concentrated force to a surface, define rp and don't define Constraints: most likely the software will get an error from you or nothing special will happen because the force is applied to a material point that is not connected to the part. Parts and objects in the model (except for datum point, datum axis, and datum plane) are connected with Constraints and interactions. If you don't put these, Abacus won't understand it.
  • asked a question related to Elasticity
Question
2 answers
explain your idea
Relevant answer
Answer
All materials have elasticity, do you mean wall that deforms under the pressure of the fluid?
  • asked a question related to Elasticity
Question
4 answers
II am working with composite materials manufactured by vacuum bag and I want to simulate the mechanical behavior of these materials. However, I believe that the elastic properties of the laminae from the Ansys library are always much higher than the elastic properties of the material I manufacture.
Relevant answer
Answer
thanks Ned Patton But how we are going extract the mechanical properties (E1 and E2) for ONE ply lamina from this coupon test results?
  • asked a question related to Elasticity
Question
3 answers
Three balls with masses m1, m2, m3 can slide without friction along a straight horizontal line, with ball 2 located between balls 1 and 3 (Fig.). It is known that m1 >> m2, m3 >> m2. Determine the maximum velocities of the two outer balls if they were initially at rest and the middle ball was moving with speed v0. The impacts are considered absolutely elastic.
Relevant answer
Answer
Answering it with the hope that the Research instinct in you will ignite.
we assume the mass of each ball is the same.
Before the collision:
- Middle ball: Mass = m, Velocity = v0
- Outer balls: Mass = m, Velocity = 0
After the collision:
- Middle ball: Velocity = ?
- Outer balls: Velocity = v1 and v2 (to be determined)
Since the total momentum is conserved, we have:
0 = m * v0 + m * (v1 + v2)
assume the maximum velocity is denoted by vmax.
Case 1: The momentum is transferred to the left outer ball (v1 = vmax, v2 = 0):
0 = m * v0 + m * vmax
Case 2: The momentum is transferred to the right outer ball (v1 = 0, v2 = vmax):
0 = m * v0 + m * 0 + m * vmax
Simplifying each case:
Case 1: v0 = vmax
Case 2: v0 = -vmax
Since velocity cannot be negative in this context, the maximum velocity of the outer balls is vmax = v0.
Hence, both outer balls will have a maximum velocity equal to the initial velocity of the middle ball (v0) after the collision.
  • asked a question related to Elasticity
Question
1 answer
I am not getting accurate elastic constants while trying to use thermo_pw on Li3PS4 (space group: Pnma). I am not sure where I am going wrong as I have tried to implement the thermo_pw tool. Can you please have a look at my input files and let me know where exactly I am going wrong?
I am not sure why exactly I am facing this issue. For some materials I am geeting quite accurate values, however for some materials like in this case Li3PS4, my attempts are unsuccessful.
Relevant answer
Answer
What result you expected to achieve? I looked in the reference you provided, but couldn't find a value to elastic constants.
  • asked a question related to Elasticity
Question
10 answers
Calculating the specific heat of a simple liquid by the number of elastic oscillators.
Calculate the specific heat of a simple liquid using the number of elastic oscillators
Each liquid molecule has an average of 8 elastic oscillators around it, and the specific heat contributed by the elastic energy is 4R。Therefore, near the three phase points, the specific heat at constant pressure of a single atomic liquid is 5.5R, and the specific heat at constant pressure of a diatomic liquid is 6.5R. Low temperature liquids such as Ar, Kr, Xe, O2, N2, F2, etc. conform to this conclusion.
Please read the following link for details
Relevant answer
Answer
Thank you for your reply.
  • asked a question related to Elasticity
Question
4 answers
I have a four-story steel structure
When conducting a pushover analysis and examining the results, the structure's ductility ratio at the performance point did not exceed 1, and the equivalent damping remained at 5% according to the FEMA400 EL method.
Relevant answer
Answer
The main problem is with ETABS algorithm which can not consider and draw bi-linear curve truly. Take your curve and use excel to draw bi-linear curve instead of drawing it in SAP or ETABS.
  • asked a question related to Elasticity
Question
1 answer
How to reduce elastic modulus and improve plasticity by doping pedot
Relevant answer
Answer
Poly(3,4-ethylenedioxythiophene) (PEDOT) is a conducting polymer known for its high electrical conductivity and excellent stability. Modifying its properties, such as reducing elastic modulus and improving plasticity, can be achieved through the process of doping. Doping involves introducing additional substances (dopants) into the polymer matrix to alter its properties.
Here are steps to reduce the elastic modulus and improve plasticity of PEDOT through doping:
  1. Selection of dopants:Choose dopants that can introduce flexibility and improve plasticity while reducing the elastic modulus. Common dopants for PEDOT include various anionic and cationic compounds.
  2. Doping process:a. Chemical doping:Perform chemical doping by incorporating the chosen dopants into the PEDOT matrix. This is usually done through oxidative polymerization, where the PEDOT monomer is oxidized in the presence of the dopant.b. In-situ doping during polymerization:Add the dopant during the polymerization process of PEDOT to ensure even distribution and incorporation of the dopant within the polymer matrix.c. Post-polymerization doping:Dope PEDOT after the polymerization process by immersing the PEDOT film or structure in a solution containing the dopant. This allows the dopant to diffuse into the polymer structure.
  3. Optimize dopant concentration:Determine the appropriate dopant concentration that will achieve the desired reduction in elastic modulus and improvement in plasticity. Experiment with different dopant concentrations to find the optimal balance between conductivity, elasticity, and plasticity.
  4. Characterization and analysis:Analyze the doped PEDOT samples using techniques such as spectroscopy, microscopy, and mechanical testing to assess changes in elastic modulus and plasticity.
  5. Adjustment and iteration:Based on the characterization results, adjust the dopant concentration and doping process parameters as needed. Iterate the doping process until the desired reduction in elastic modulus and improvement in plasticity are achieved.
  6. Applications and testing:Test the doped PEDOT in specific applications to evaluate its performance, such as flexible electronics, sensors, or other relevant fields. Collect data and feedback to further refine the doping process if necessary.
Remember that the choice of dopant and the doping process conditions will greatly influence the properties of the doped PEDOT. It's essential to carefully design and optimize the doping process to achieve the desired properties for the intended application.
  • asked a question related to Elasticity
Question
6 answers
I use plastic behaviour for a material in abaqus:
YS plastic strain
8MPa 0
8MPa 1
8MPa 100
And Abaqus seems to ignore the elastic limit, the von Mises stress happily rises above 8MPa. But it does not happen when the mesh is linear with ticked reduced integration. Why is this and how do I fix this bug?
Relevant answer
Answer
Maciej Gierulski Linear elements with reduced integration use uniform distribution of stress components, therefore nodal values of Mises stress coincide with its correct value at integration point (centroid). Elements with full integration use element shape functions for extrapolation of stress components from integration points (wher Mises stresses are correct) to nodes, therefore nodal Mises values can somewhat exceed yield limit. That's the price of visualization.
  • asked a question related to Elasticity
Question
1 answer
Under dominant mode I loading, planar cracks have been observed to move from zero velocity v= 0; for a certain value v= v1, these turn into non-planar crack configurations. An explanation is offered below.
Relevant answer
Answer
We refer to the work “NON-PLANAR CRACKS IN UNIFORM MOTION UNDER GENERAL LOADING” by ANONGBA (2020):
When the velocity v of planar cracks increases toward the terminal velocity ve = 0.52 ct (ct, the velocity of transverse sound wave), moving non-planar crack configurations have been found (0.33 ct < v < 0.55 ct, approximately) with average crack extension force < G > much larger than those of planar cracks. This indicates that non-planar cracks may be associated with larger decrease of the energy of the system on change of crack configuration. Hence, the starter planar crack transforms itself into a non-planar configuration to maintain higher speed motion during its evolution in steady motion.
  • asked a question related to Elasticity
Question
4 answers
I want to know the theory of elasticity in differential geometry, and if there are any basic courses in this field. THANKS
Relevant answer
Answer
Good question Prof. Abdelouahab Chikh-Salah
Try to check in the book (I am not sure, I took the course many years ago):
Kind Regards.
  • asked a question related to Elasticity
Question
4 answers
Dear ResearchGate Community,
I am currently working on nanoindentation experiments using a Berkovich indenter on MG-WE43 alloy samples. My primary objective is to determine the hardness and elastic modulus of the material using the Oliver-Pharr method. However, I have encountered some issues in my analysis code, and I am seeking technical guidance to overcome these challenges.
Here is a brief overview of my experimental setup and the problems I am facing:
  • Setup: Indenter Geometry: Berkovich, Material: Mg-WE43 alloy.
  • Challenges: I have implemented the Oliver-Pharr method to calculate hardness and elastic modulus, but I am uncertain about the correctness of my code. I would appreciate guidance on the code implementation and any potential pitfalls specific to MG-WE43 alloy. I am unsure about the appropriate values for Poisson's ratio and elastic modulus of MG-WE43 alloy. Should I rely on literature values, or is there a way to experimentally determine these parameters? Are there any specific considerations or corrections needed when analyzing nanoindentation data?
If any of you have experience with nanoindentation on similar materials or with the Oliver-Pharr method, I would greatly appreciate your insights and recommendations. Additionally, if you could share any MATLAB or Python code snippets tailored to this specific analysis, it would be immensely helpful.
Thank you in advance for your assistance.
Relevant answer
Answer
Thank you for your response Mr.
Leonardo Fanton
, I have some limitations with trying out other methods of indentation.
  • asked a question related to Elasticity
Question
7 answers
In my model, each element has a different material prop and EX. (plotting output data is pretty straightforward, however input data is the trouble I so much need help with).
Relevant answer
Answer
Sandro Torres Can you share a .cdb file of your Ansys model? Thanks in advance.
  • asked a question related to Elasticity