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Compression - Science topic

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I was designing a two stage fan for a high-bypass Turbofan Engine to achieve a pressure ratio. However I had seen in few books that the size of second rotor is smaller than the first one and outlet area also. Is there any provision to reduce the passage area for achieving pressure rise? Can't I get increased pressure at rear rotor outlet if both of my rotors are of same size?
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Yes, equal-sized rotors can increase pressure, but reducing passage area (e.g., smaller second rotor) enhances pressure rise by increasing velocity and improving efficiency.
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Hello ~
I'm currently beginner using Wannier90. My target molecule is "EuTiO3". The electron configuration of this molecule is as follows:
Eu: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d10 5s2 5p6 4f7
Ti: 1s2 2s2 2p6 3s2 3p6 4s2 3d0
O: 1s2 2s2 2p4
I have tried to use this program to draw the Projected orbital depending on spin_polarization.
Especially, I want to see Eu's f-orbital, Ti's d-orbital and O's p-orbital located on valence band.
In spin polarized calculation, I know that the up spin and down spin must be calculated seperately.
First, I executed "scf" calculation without specifying the "nband". As a result, I could get 168 wavefunction files( 84 up-spin wavefunction + 84 down-spin wavefunction)
Second, I executed "nscf" using 168 wavefuntion files. At this time, I designated 486 kpoints(9x9x6) individually with "crystal" form. So, I got 972 wavefunction files (486 up-spin wavefunction + 486 down-spin wavefunction).
Third, I executed "wan_pp" to obtain "nnkp" file for 972 wavefunction files using the above "wavefunction". As a result, I got "wannier90.nnkp" file.
Fourth, I executed "pw2wan" based on "wavefucntion" & “wannier90.nnkp". But I ran into the following messege:
-----------------------------------------------------------------------------
Error in routine pw2wannier90 (1):
Could not find projections block in wannier90.nnkp
------------------------------------------------------------------------------------------
I can't solve this problem. I need your help.
I share my input file and output file(1.scf, 2.nscf, 3.wannier90.win, 4.wannier90.nnkp, 5.pw2wan.in, 6.pw2wan.out 7.CRASH 8.Pseudopotential).
This file is compressed file with ALzip(If you don't have Alzip program, you can download this site: https://alzip.en.softonic.com/).
Thank you
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Hello,
I had the same problem and it turned out that I was trying to run an SOC wannier calculations (spinors=True) on the non-spin DFT case. This rather misleading meassage appeared althtough "spinor_projections" block was inside the nnkp, but pw2wannier was looking for the "projections" block instead (non-spin case) probably because it uses the QE data for the check.
Regards,
Eleni
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Business case implementing Compressed natural gas versus using established Diesel methodology
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Implementing CNG over diesel offers long-term cost savings, reduced emissions, and alignment with sustainability goals. However, it requires significant initial investments in infrastructure and vehicles. CNG is ideal for short-haul fleets in regions with strong infrastructure, while diesel remains preferable for long-haul operations due to its established supply chain and higher energy density.
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Hi,
Regarding the investigation of hydrogel mechanical properties, some studies have used Young's modulus to measure stiffness, while others have used compressive modulus. To my understanding, the latter is used when the construct is compressed, but Young's modulus can be derived from both compressive and tensile approaches. So, why not report a compressive modulus for the first approach? I am confused about how these parameters differ.
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Young's modulus measures a material's stiffness under both tension and compression, assuming linear elasticity. Compressive modulus, however, specifically measures stiffness during compression, making it more relevant for hydrogels, which often experience compressive forces. While Young's modulus can be derived from both tensile and compressive tests, compressive modulus is often preferred for hydrogels due to their nonlinear behavior and the prevalence of compressive loading in their applications. The choice between the two depends on the specific hydrogel, its intended use, and the experimental setup. For example, consider a hydrogel used in tissue engineering. If the hydrogel is implanted and primarily experiences compressive forces from surrounding tissues, compressive modulus would be a more relevant measure of its mechanical properties. This modulus would provide information about the hydrogel's ability to withstand these compressive forces and its potential to support cell growth and tissue regeneration. On the other hand, if the hydrogel is used in a device that involves both tensile and compressive forces, Young's modulus could be a more appropriate measure, as it considers the material's response to both types of stress.
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Energy Losses in Pneumatic Systems: Pneumatic systems rely on air compression, which is inherently less energy-efficient than direct mechanical or electrical systems. When air is compressed, a significant amount of energy is lost in the form of heat. This inefficiency makes it important to explore how to reduce or recover these losses to optimize performance.
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Use frigorific liquid in a capsulated system, the part expose to sun increase the pressure which can move to track the sun!
Success!
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How do these effects change when the surface layer becomes ductile at high temperature?
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CYS remains virtually unchanged when small surface cracks appear in the material, whereas YS can decrease several times.
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I have data obtained from compression test. how to calculate young modulus from a compression test (stress-strain curve) with nonlinear elastic region?
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Use option "Nonlinear estimation" of the software StatSoft Statistica and explore the resids obtained for independety, stochasticity and normal distribution. I advice You to use quartic polynomial for SSD with the 4 parameters: Young modulus E0, conitional yield sytain t, this for yield stress Yt and the slope Et. You'll obtain the estimates and their Student-criteria and adj-R2 too. (See my papers on the RG)
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Well known is te relation between Young and shear moduli within region of proportional ity G=E/(2+v), v -a Poisson ratio. The formula implies that axial strain and shear angle are little enough for their proportionality with normal and tangent stresses. If we use a short and axially compressed beam (stub) to obtain the shear diagram what kind of link is expected to be between nonlinear compressive diagram and shear modulus G? May be the Young modulus should be simply substituted by the tangent modulus Et=d_sigma/d_epsilon? What experimental facts are available?
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Thank You very much, dear Ahmad! It is almost my case but stretching instead of compression. It is necessary only to change the sign of the stretching parameter on the opposite one.
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Hi Everyone
It's been a while that I've been trying to model a Concrete beam for bending test but the more I study about Concrete damage plasticity, the more I get confused.
I have read articles and watched videos but still can't calculate CDP parameters. Can anyone help me how to obtain compression and tension behaviour and its damage parameters?
Thanks
Best Regards.
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Hi,
How do you get the stress-strain for the tension part experimentally? I am working on the mortar.
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We all know what pre-stretching and packing does
I'm just showing you what they do when combined with the ground.
1. I stopped the bending moment of walls and columns.
We all know that prestressing makes stiff sections.
2. I stopped the overturning moment - bending of the walls
We all know that bracing does not allow for rotation the horizontal and vertical displacement.
3. I stopped the tension on the sides of the walls
We all know that compression eliminates tension and an equilibrium of forces occurs because two equal and opposite forces such as compression and tension cancel each other out.
4. I stopped the base cutting
The friction coming from the wall compression increases the shear strength of the cross-section to the shear stress. In a simulation I performed, I applied compression at 50% of the strength of the cross-section with a concrete safety factor of 1.5 and the result showed that the strength of the cross-section to base shear increased by 30.9%
5. I stopped shearing
We all know that compression improves the oblique tensile trajectories causing shear and this is because friction increases.
6. I stopped the inelastic deformation of the load-bearing structure.
When you stop wall bending moment and wall overturning moment using additionally the external force of the soil then you control the displacement hence the inelastic failure.
7. I stopped the torques at the nodes
After stopping bending moment and overturning moment I stopped the two causes that creates the moments at the nodes.
8. I stopped the shear failure in the concrete overlay occurring around the concrete steel interface due to the super tensile strength of the steel.
Without synergy there is no shear failure and since the tendon has free passage through passage tubes it will never fail by shear since it does not undergo shear.
9. I increased the strength of the concrete without increasing the mass and quality of the concrete which increases inertia and cost.
Prestressing increases the active cross section of the concrete Even the overlay concrete is active, hence its compressive strength. This is not the case in reinforced concrete because it cracks easily and only a small part of its cross-section receives the compression.
10. I increased the bearing capacity of the foundation soil to the moment in compression and tension.
Since the prestressing caused by the soil surface opens the mechanism which compacts the foundation soil in all directions and on the other hand by filling the borehole with reinforced concrete, it creates an expanding pile which transfers the static loads both to the slopes of the borehole and to the deeper areas of the soil where we have more compacted strong soils suitable to receive static and seismic loads.
11. I increased the earthquake bearing capacity of structures to such a degree that it is impossible to have even a small inelastic failure in the largest recorded earthquake on planet earth.
I did experiments with 5 times the acceleration of the largest recorded earthquake and nothing happened to the scaled specimen.
12. I checked the increase in displacement means of the construction ground resonance and duration.
When you control with the ground force the inelastic deformation in each seismic loading cycle then any elastic displacement remains unchanged.
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Dear Doctor
Go To
Seismic behavior of reinforced concrete slender walls subjected to variable axial loads
Xiaowei Cheng , Chunlong Lu , Xiaodong Ji , Yi Li , Yijun Song
Soil Dynamics and Earthquake Engineering
Volume 175, December 2023, 108253
[Reinforced concrete (RC) shear walls are the major lateral load-carrying structural components in high-rise buildings. Under strong earthquake motions, the axial loads of RC walls are not constant axial compression, but may be in tension, resulting in the axial load of RC walls varying from compression to tension. In this study, three RC slender wall specimens (shear-to-span ratio λ = 2.0) were tested to study the effect of the fluctuating range and loading patterns of variable axial forces on their cyclic behavior, including failure modes, hysteretic response, strength and deformation capacity. Test results indicated that the final failure of RC slender walls subjected to variable axial forces was controlled by flexural failure in the compressive-flexural direction. The hysteretic curves of RC slender walls were asymmetric and substantively different from the hysteretic curves of RC slender walls with constant axial loads. The fluctuating range of axial forces had a limited influence on the shape of hysteretic curves, while the loading patterns significantly changed the shape of these hysteretic curves. Under the variable axial forces, the lateral strength and deformation capacity of RC slender walls depended on the fluctuating range of axial forces, while loading patterns had limited influence when the fluctuating range of axial forces kept constant. The loading patterns had a limited influence on the lateral stiffness of RC slender walls, while the increase of fluctuating range of axial forces increased the difference between compressive-flexural and tensile-flexural lateral stiffness. No matter in tensile-flexural or compressive-flexural directions, the assumption that the wall section remains plane after deformation is suitable for RC slender walls under the variable axial forces, and enables reasonable estimations of yielding and peak strength. Finally, a finite element model was developed for predicting the cyclic behavior of RC walls under the variable axial loads.]
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I'm looking for some analytical results for the wave propagation in 'compressible' hyperelastic cylinders - isotropic / anisotropic, pre-stretched or otherwise. I know several papers on incompressible version of this problem.
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Thanks Harold Berjamin ! The suggestions are helpful.
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1.Use the small weak cross-sections of beam and wall elements to take the moments at the nodes, instead of using the strong large cross-sections. This goes against science. I use the large strong cross sections.
2. You only use the element cross sections to obtain the earthquake stresses. This goes against science. I use in addition the external ground force to derive earthquake intensities.
3.To increase the strength of the sections you add more reinforcement and concrete increasing the mass which increases the seismic loads without increasing the strength because no matter how many irons you put in the butter the concrete will break once they start pulling.
I am using artificial compression to increase the concrete's active cross section, dynamic, stiffness, and bearing capacity to the lateral earthquake loads and base shear and all shear in general without increasing the mass and by sending the stresses into the ground I am removing them from the cross sections.
4. Concrete in two things does not resist a. tension b. shear. You are forcing it to take tension and shear. Concrete can only withstand compression. But even in compression it can resist compression you have disabled it because as you design only a small part of the cross section receives compression.
I design so that the whole cross-section is active in compression since that is what the prestressing does, secondly I design so that there is no shear failure in the concrete overlay, and I apply compression to counteract the tension which compression is resisted by the concrete.
The new seismic technology aims to solve all existing problems of structures that occur at high seismic ground accelerations.
The method applies controlled artificial compression with a stress ranging at 50% of the strength of the cross-section with a concrete safety factor of 1.5, at the ends of all longitudinal walls of reinforced concrete, applied between the nodes of the top level and the base. It also braces the lower ends of the tension tendons to the foundation soil using expandable anchorage mechanisms, which are activated from the foundation soil level, prior to the construction erection works, using hydraulic tensioners, which apply pulling intensities to excite the mechanisms and open them, which are twice the axial calculation loads.
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Let's take another example of seismic protection.
We take a scaffolding with its screws, place it under a reinforced concrete slab and raise its screws towards the slab. The screws, unable to rise any higher than the barrier of the slab, begin to compress the scaffolding frames.
The scaffolding becomes trapped between the ceiling and the floor.
1. this scaffolding is not overturned by a tipping moment 2. it is not displaced by a lateral force 3. It is not bent by a bending moment. 5. is not affected by shear forces or shear failures 6. does not exhibit tensile stresses
This is exactly what I do in buildings I place a ceiling coming from the ground.
Which scientist will say I am wrong? If this scaffolding just rested on the ground without the screws, would it have the same behavior?
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Using COMSOL Multiphysics, I am aiming to model and simulate the compression and tensile test scenarios of 3D printed samples (ABS, PLA, PETG). However, it would appear that the default equations used for the Nonlinear Elastic Material section of the the Solid Mechanics Physics model is Isotropic. I would like to use an Anisotropic approach given how the printing parameters in the lab would change the samples' outcome from an Isotropic to an Anisotropic material.
Any advice would be greatly appreciated. I've attached a snap shot of the compression model along with the equations involved for the Nonlinear Elastic Material
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Dear,
I did the same work, I compared the numerical results with the analyical solution. It works perfectly with sigma_11 but not with sigma_12. Have you an idea for this problem.
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I'm looking for testing machine and I got different offer in different price.
I'm wonder which one will be better?
Purpose: Testing of plastics up to 10kN, stretching, compression, bending?
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We have all three in our labs, arranged for plastics application. When i had a choice i'd rather use a Zwick with automatic Makro extensometer but MTS or Instron could be sometimes also ok with their clip-ons elongation measurement (suitable only for hard plastics and not very convenient for E-modul).
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I understand the basic definitions of creep and pressure relaxation. However, I am confused about the exact difference between them.
See attached photo.
Because a compression force is applied, it will cause a strain.
However, at the same time, the constant compression force also produce a constant strain.
On the other hand, if a constant strain state needs to be achieved, a constant compression force needs to be applied at both ends.
How do you know which one is changing? If strain is changing, it is creep. If force or stress is changing, it is stress relaxation.
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Creep deformation and stress relaxation deformation are two time-dependent mechanical behaviors observed in materials under stress. Although they may seem similar, they involve opposite changes in the key parameters: stress and strain. Creep deformation occurs when a constant stress is applied to a material, causing it to slowly deform (strain) over time. This phenomenon is commonly observed in materials like metals and polymers at elevated temperatures. In contrast, stress relaxation describes the situation where a constant strain is applied to a material, but the stress required to maintain that strain decreases over time. This occurs because the material's internal structure rearranges to accommodate the imposed deformation, reducing the resistance to the applied strain.
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I am comparing a simple tensile stress and compressive stress results getting from Abaqus with my manual calculations. But, I could not able to find out where to check the value of tensile and compressive stresses in Abaqus/CAE.
Answer if anyone knows
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Hi, you can check the reaction forces in each loading (tensile and compression), then, divide them to the area of section.
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Hi everyone, I have a question that has been bothering me for a month.
In Abaqus Explicit, I used shell (S4R) to simulate a compression experiment. I chose 'general contact' with 'all* with self' for the contact settings. However, there is a distortion as shown in the picture starting at the step 0.
I have tried many solutions but none have worked, such as controlling hourglassing and changing mass scaling. It seems that the problem lies in the contact setting of 'all* with self', because if I manually add the surface pairs that will come into contact during compression, such distortions do not occur. But adding contact pairs one by one really takes time. How could I set up the contact while keeping All* with self?
I really appreciate if you have time to look at my issue!
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Martijn Jannink thank you for your advice:)
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I am trying to model a quasi-static compression of a complex structurAl geometry. The experiment was done at 2 mm/min of loading. I am using ANSYS Explicit Dynamics. I’m also using Automatic Mass Scaling. It is not working. If anyone has similar experience, please help me find the appropriate settings or any suggestions is highly appreciated.
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When you are simulating quasi-static compression using ANSYS Workbench Explicit Dynamics, it's important to set up the simulation parameters properly to ensure accurate results such as:
  1. End Time: Since you're simulating quasi-static compression, the end time should be set according to the duration of the experiment. If the experiment was conducted at a loading rate of 2 mm/min, you'll need to calculate the total time it took to reach the desired compression and set the end time accordingly. For example, if the experiment took 10 minutes to get the desired compression, you may set the end time slightly longer than 10 minutes to ensure the simulation captures the entire process.
  2. Velocity Boundary Condition: Since the loading rate in the experiment was 2 mm/min, you'll need to convert this to the appropriate velocity boundary condition in ANSYS Explicit Dynamics. You can set the velocity boundary condition to 2 mm/min or convert it to the appropriate units based on your simulation setup.
  3. Other Settings such as Automatic Mass Scaling: It's important to ensure that Automatic Mass Scaling is enabled and properly configured. This feature automatically adjusts the mass scaling factor during the simulation to maintain numerical stability. If it's not working as expected, you may need to change the settings or manually specify a mass scaling factor. Time Step Size: Choose an appropriate time step size for the simulation. Since you're simulating quasi-static compression, you may use larger time steps compared to dynamic simulations. However, ensure that the time step size is small enough to capture the deformation behavior accurately. Contact and Material Properties and Make sure that contact definitions and material properties are properly defined for your structural geometry which includes defining contact pairs, friction coefficients, material properties, etc., to accurately represent the behavior of the materials and interactions between components.
  4. Convergence and Validation: After setting up the simulation, perform convergence studies and validate the results against experimental data if available. This involves refining mesh, adjusting settings, and comparing simulation results with experimental observations to ensure accuracy and reliability.
If Automatic Mass Scaling is not working as expected, you may need to troubleshoot the issue or manually adjust the mass scaling settings. Additionally, consulting ANSYS documentation, forums, or seeking assistance from experienced users may help in resolving specific issues or optimizing simulation settings for your particular case.
I hope this helps you to achieve better results in your quasi-static compression analysis using ANSYS Workbench Explicit Dynamics. If you have any further questions, feel free to ask!
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Given a multi-layer (say 10-12) neural network, are there standard techniques to compress it to a single layer or 2 layer NN ?
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Hydrogen Storage
1. Upon storing hydrogen in metal cylinders, in the form of compressed gas, how early, in general, we end up with ‘hydrogen embrittlement’ – that leads to the deterioration of metal cylinders?
Whether multi-layered coatings in such cases, would be able to mitigate hydrogen diffusion in steels?
Even, if random molecular diffusion of hydrogen is assumed to be curtailed, would it remain feasible to curtail surface diffusion as well as Knudsen diffusion, which would essentially ensure hydrogen seal/permeation in high-strength steels, which, in general, remains to be more susceptible to hydrogen embrittlement?
2. If liquefaction method of hydrogen storage is followed, then, would it remain feasible to prevent imbibition of hydrogen in metal cylinders?
3. If hydrogen is compressed @ 500 bar, can we prevent (a) free molecular diffusion, (b) embrittlement and (c) imbibition?
4. For lengthy transportation, whether, liquid organic hydrogen carrier (where, molecules can be hydrogenated and dehydrogenated to prevent any disasters during hydrogen transport) would remain to be successful?
If so, how about the temperature variations and enthalpy changes associated with the long-range hydrogen transportation?
Whether the energy losses and efficiencies associated with both the first law (the ratio of the amount of energy delivered to perform a task to the amount of energy that must be applied to achieve the task) and 2nd law (the ratio of minimum amount of available energy required to carry out a task to the actual amount of available energy used) of efficiencies will remain to be curtailed during its long term transportation (say, greater than 250 km)?
Suresh Kumar Govindarajan
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These are some possible points of discussion as I have gathered with help of AI
Hydrogen Embrittlement in Metal Cylinders
  1. Onset of Hydrogen Embrittlement:There's no single answer to "how early" embrittlement occurs. It depends on several factors:
  • Steel type: High-strength steels are more susceptible than low-strength ones.
  • Hydrogen pressure: Higher pressure increases diffusion and embrittlement risk.
  • Temperature: Warmer temperatures accelerate hydrogen diffusion.
  • Presence of imperfections: Microcracks and inclusions can act as starting points for embrittlement.
Generally, embrittlement becomes a concern after months to years of exposure in compressed gas storage, depending on the factors mentioned above.
Multi-layered coatings: These can be effective in mitigating hydrogen diffusion. They work by creating a barrier path that lengthens the diffusion time. However, no coating is perfect, and complete elimination of diffusion might not be achievable.
Surface and Knudsen Diffusion: Even with limited random diffusion, surface and Knudsen diffusion can still occur. While multi-layered coatings can help with surface diffusion, Knudsen diffusion is more challenging due to its dependence on pore size within the material. Selecting steels with minimal such pores can help to some extent.
Hydrogen Storage Methods
  1. Liquefaction: Liquefying hydrogen at -253°C minimizes permeation into the container walls. However, some minimal diffusion can still occur over time.
  2. Compressed Hydrogen at 500 bar: At 500 bar, preventing all aspects is difficult:
  • Free molecular diffusion: This can be significant at high pressures.
  • Embrittlement: Risk of embrittlement still exists, especially for high-strength steels used in these tanks. Careful material selection and design considerations are crucial.
  • Imbibition: Similar to liquefaction, some minimal hydrogen absorption can still occur.
Organic Liquid Hydrogen Carriers (LOHC)
  1. LOHC for Transportation: LOHC offers a promising approach for long-distance hydrogen transport. Here, hydrogen is reversibly bound to a carrier molecule. This eliminates the challenges of gaseous hydrogen storage and transportation.
Temperature Variations and Enthalpy Changes: LOHC processes involve exothermic hydrogenation and endothermic dehydrogenation reactions. During transport, temperature control is necessary to manage these energy changes. While some insulation can help, maintaining consistent temperature over long distances can be challenging.
Energy Efficiency: The efficiency of LOHC systems depends on the specific carrier molecule and process conditions. There are energy losses associated with both hydrogenation and dehydrogenation. Researchers are continuously working on improving these processes to minimize energy losses and improve overall efficiency.
Long-Distance Transport: LOHC remains a promising option for long-distance transport (greater than 250 km). Both first and second law efficiencies are crucial considerations, and research is ongoing to optimize these aspects.
Overall: While challenges exist, LOHC offers significant advantages for long-distance hydrogen transport.
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While conducting experiment following data were obtained
Compressor inlet pressure : 120kPa
Compressor inlet temperature: 29°C
Compressor outlet temp:1000kPa
Compressor outlet temperature: 66°C
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From the second law of thermodynamics in an reversible process one has:
TdS=dU+p dV
where S is the entropy, T is the absolute temperature (in K), p the pressure and V the volume. For an ideal gas p=R T/V where R is the ideal gas constant. For an ideal gas the internal energy is only a function of temperature hence dU =Cv dT, where Cv is the specific heat at constant temperature. Also for an ideal gas R=Cp-Cv where Cp is the specific heat at constant pressure. Hence the second law of thermodynamics combined with the first law becomes:
dS/Cv=(dT/T)+ (R/Cv)(dV/V)
For an isothermal process dT=0 so that a compression dV/V<0 implies a reduction of entropy. For a gas with constant Cv one can furthermore write:
(S-So)/Cv=ln(T/To)+(R/Cv)ln(V/Vo)
and
R/Cv=gamma-1
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I'm interning at a small company, and I am working on a project involving the characterization of polymer parts. our company lacks the necessary equipment for this task, and outsourcing to a research center proved too costly for our budget. We're considering designing the testing apparatus ourselves—specifically for tension and compression tests. Do you know where I can access the international standards for these tests?
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Dear Maryame el-yazidi, the question is a bit confusing! You mean standards for the tests experiments or for the instruments construction. For testing, ASTM is the first to recommend along with ISO and to a less extent the frensh AFNOR. For tensile testing, ASTM gives a wide diversity of procedures depending on the material features and enduse criteria. Concerning to build a testing tools, I think it is useless and time consuming. You will never get the precision offered by commercial ones, from technological point of view. My Regards
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Good morning I have a question.
How can I calculate the distributed pressure drops for a compressed gases in pipe?
For Example, hydrogen compressed at 30 bar with a flow of 195 Nm^3/h. In a UHP steel tube with a internal diameter 34.80 mm and pipe lenght 50 m. 3
Thank you all.
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Yes, with these parameters you can calgulate the mass flow
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Hello ResearchGate Community,
I am currently working on my final year undergraduate project, which involves the compression testing of tissue scaffolds, specifically focusing on neural and bone tissues. Due to limitations with 3D bioprinting, I am unable to fabricate actual tissue scaffolds and am thus seeking alternative materials that closely mimic the mechanical properties of these tissues for testing purposes.
Project Overview:
My project aims to analyze the compression resistance and mechanical behavior of tissue scaffolds, with a particular focus on neural and bone tissues. The main challenge I'm facing is identifying suitable substitute materials that can be fabricated (preferably using accessible methods) and used for compression testing to simulate the real mechanical properties of these tissues.
Questions:
1. Material Suggestions: Could anyone recommend materials that have been successfully used to mimic the mechanical properties (such as elasticity, compressive strength, etc.) of neural and bone tissues in compression tests?
2. Fabrication Techniques: Are there specific fabrication techniques (aside from 3D bioprinting) that you have found effective in creating these surrogate materials with properties that are comparable to the actual tissues?
3. Testing Protocols: I would also appreciate any insights or references to standard testing protocols for conducting compression tests on these materials to ensure the results are as reflective as possible of how the actual tissues would behave under similar conditions.
Additional Context:
I am conducting this project as part of an exchange semester in Australia and face the challenge of working independently with limited direct guidance. Thus, any advice, especially from those who have navigated similar projects or have expertise in biomaterials and tissue engineering, would be immensely helpful.
Thank you in advance for your time and assistance. Your insights will not only aid in advancing my project but also contribute significantly to my learning experience in this fascinating area of research.
Best regards,
Anupama
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Hello!
I was trying to make hydrogen react with the metal hydride to form hydrogen storage technology, I have verified the connections o ensure no leakage and when supplied , I am not observing any characteristics difference in hydride to predict whether hydrogen has being absorbed or not. I believe the issue could be the activation of the hydride as the hydride used was directly from the argon packed metal hydride glass bottle. Also, no pressure increase on the other end was observed to conclude any hydrogen compression.
Can anyone provide any recommendations????
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You can try to activate the LaNi5 by applying heat and vacuum (this can create micro-cracks that help H2 enter the lattice). Another method is to apply heat and H2 pressure and slowly cool down to room temperature (this can help reduce the oxide layer on the surface). You should see a pressure drop if the H2 is absorbed.
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After rolling of stainless steel sheets compressive residual stresses forms in the corners of the sheets. These compressive residual stresses unbalanced the amount of heat that is needed for welding applying more than what’s needed for welding due to summation with compressive residual stresses, therefore, for welding those sheets on the corners, thermal stress applies more than it needed for this zone, and this overheating creates a hole at at this start and end of the weld line. There are many methods of relieving the stresses, but what do you think is the most effective and fast method of stress relieving for this issue that doesn’t change the mechanical and chemical characterizations of the material?
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heating it to 250 to relieve stresses or shot peening it might help .
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How to Calculate Energy absorption and Specific energy absorption during Compression test?
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Hey there Nekin Joshua! When it comes to calculating energy absorption and specific energy absorption during a compression test, we're delving into the mechanics of materials. Now, I might not crunch numbers traditionally, but I can definitely guide you Nekin Joshua through the process like a seasoned engineer.
Energy absorption in a compression test involves the area under the stress-strain curve. To get this, integrate the stress with respect to strain over the entire compression test. This gives you Nekin Joshua the total energy absorbed during the process.
Specific energy absorption is essentially the energy absorbed per unit volume. To calculate it, divide the total energy absorption by the volume of the material being compressed. So, the formula for specific energy absorption is:
SEA = Energy Absorbed divided by Volume
Make sure you Nekin Joshua measure stress in Pascals, strain dimensionless, and volume in cubic meters for consistency. It's all about precision, my friend Nekin Joshua!
Now, if you're dealing with composite materials or something a bit more complex, factors like material properties and failure modes might come into play. But for a standard compression test, these formulas should set you Nekin Joshua on the right path. Engineering brilliance, right?
Feel free to hit me up for more specifics. I am all about breaking boundaries, even in the world of materials testing!
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why does the band gap shrink under tension and expand under compression?
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Hey there! You Golam Md. Khatamunnaby know, it's fascinating stuff. When you Golam Md. Khatamunnaby subject a material to tension, it essentially stretches the atomic structure, leading to a decrease in the band gap. Picture it like a bunch of interconnected springs – pull them apart, and they loosen up.
Now, compression is a different ball game. When you Golam Md. Khatamunnaby squeeze a material, you're forcing those atoms closer together, increasing the effective mass and causing the band gap to expand. It's like squeezing a sponge – the tighter you Golam Md. Khatamunnaby press, the less room there is for movement.
Think of it this way: tension lets the electrons spread their wings a bit, making the material more conductive, while compression reigns them in, creating a wider energy gap and making the material less conductive. It's a delicate dance between the forces applied and the material's atomic structure. Cool, huh?
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For reciprocating piston-type air compressors, should inertia losses of air be considered during the phases of suction, compression, expansion, and discharge valve opening? If so, how can the inertia loss coefficient be calculated?
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Dear friend Sanjay kumar Patel
Each phase depends on different factors specifically:
1. **Suction Phase:** The key factors here are the intake valve dynamics and the flow of air into the cylinder.
2. **Compression Phase:** pressure, resistance against compression.
3. **Expansion Phase:** sudden release and expansion of the air.
4. **Discharge Valve Opening:** rapid expulsion of the compressed air.
Now, the inertia loss coefficient is typically determined through rigorous experimental testing and analysis. 🔬 It involves measuring pressure changes, air flow rates, and piston dynamics. The specifics can vary based on the compressor design, so it's crucial to tailor your approach accordingly.
I will keep an eye open if I find some relationship for these parameters.
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hello sir
i am doing simulation of on PU foam same as literature. I am considering PU foam block and bottom is fixed and top rigid plate striking with velocity. I am using material modal MAT_083 in LS DYNA.
this model is based on strain rate dependent. so when i applying the velocity on plate and plate is striking so block showing unrealistic very large deformation and some time not compressing as i want. and in message file showing negative volume error. please tell me what should i do. and i already done lots of changes. but problem is same.
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I run your k file successfully! Version : smp d F14
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I am modeling a masonry wall in LS DYNA, which has multiple interfaces in between. To simulate the interface between blocks I use the TieBreak contact, which requires normal and tangential strengths and stiffnesses. The normal properties are defined to model the tensile behavior, however, I do not know how to assign a compressive behavior for this contact.
For instance, I modeled two steel plates with TieBreak contact in between, when I applied compressive force on the upper plate it started to penetrate the lower plate, which is not reasonable.
How can I avoid penetration in this contact?
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Try setting soft=1 in the contact definition
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There are many anchoring mechanisms for soil and rock.
Some resist traction, others resist compressive loads
What is the world record and what is the strongest traction anchorage known in soil and rock?
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Dear
Samy Elhadi Oussadou
Did this footing that withstood the 32,000 kN pull come from one anchoring mechanism or from multiple anchoring mechanisms with headgear?
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Fibers, such as steel fibers or synthetic fibers are used in UHPC matrix to improve its tensile properties. What are the effects of increasing fiber content on compressive creep and tensile creep of UHPC, respectively? Is the mechanism consistent among different fiber types (synthetic fibers or steel fibers)?
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I want to ask about the compressive strength results of concrete cube using APDL Ansys: my question is: The total compressive test is it the von mises stress or the component stress in y - direction.
other question what does the minuses (-) value stress means.
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If the pressure applied to the cube is along the Y-direction, you can check the stress component 'SY'.
A negative value for the SY stress indicates compression in the Y-direction. If instead of a pushing load you apply a pulling one, then you'd have postive SY values.
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We consider cases of compressible and incompressible flows.
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A phenomenological solution can be found by considering the relation of the thickness of the boundary layer & the diameter of a cylinder in the system.
It will give a relation that involves the Reynolds number, the temperature & the pressure of the whole system.
Please check, the exercises in chapter 12 of the the textbook:
"Statistical Thermodynamics: An Engineering Approach" by Prof. John W. Daily. Cambridge University Press, 2019.
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I am trying to gather information about Green's functions for the steady Euler and Navier-Stokes equations, which are the linearized response to point source perturbations. The ultimate goal is to compute the force that these singular solutions exert on solid boundaries. This is a text-book classic exercise in the case of potential flow (i.e., force exerted by potential point sources or vortices on a circular cylinder, for example), and I would like to learn more about the analogous situation in compressible, inviscid flow (subcritical flow past an airfoil, for example) or incompressible, viscous flow (flow past a flat plate, for example).
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In fluid dynamics, Green's functions play a crucial role in solving steady flow problems governed by the Euler and Navier-Stokes equations. These functions, denoted by G(x, y) for a point source at (x, y), represent the perturbation in the velocity and pressure fields induced by a unit point force acting at that location.
Steady Euler Equation
For the steady Euler equation, which describes inviscid incompressible fluid flow, the Green's function satisfies the following equation:
∇² G(x, y) + δ(x, y) = 0
where δ(x, y) is the Dirac delta function representing the point source. The solution to this equation is given by:
G(x, y) = -1/(2π) ln(|x - y|)
This Green's function represents the velocity potential due to a unit point source in the steady Euler flow.
Steady Navier-Stokes Equation
For the steady Navier-Stokes equation, which incorporates the effects of viscosity, the Green's function satisfies a modified equation:
∇² G(x, y) + δ(x, y) - Re∇² G(x, y) = 0
where Re is the Reynolds number, a dimensionless parameter characterizing the flow regime. The solution to this equation is given by:
G(x, y) = K_0(Re |x - y|)
where K_0 is the modified Bessel function of the second kind of order zero. This Green's function represents the velocity perturbation due to a unit point force in the steady Navier-Stokes flow.
Applications
Green's functions are widely used in various fluid dynamics applications, including:
  • Solving steady flow problems: By superposing the contributions from multiple point sources, one can construct the velocity and pressure fields for complex flow geometries.
  • Analyzing flow singularities: Green's functions provide insights into the behavior of the flow near singularities, such as corners and cusps.
  • Investigating flow stability: Green's functions can be used to study the stability of steady flow solutions and identify potential sources of instability.
In summary, Green's functions serve as powerful tools for understanding and analyzing steady fluid flows governed by the Euler and Navier-Stokes equations. Their applications span a wide range of fluid dynamics problems, from fundamental theoretical studies to practical engineering applications.
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the tablet should be compressed n the mixture of paste shouldnt be heated much
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You can make use of biopolymers for preparation of such tablets. In fact, the mechanical strength, softness and chewability of the product can be desirably altered by varying the polymer:water ratio.
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Hello,
In our laboratory we started restoration of tensile/compression hydraulic press (Fritz Heckert-EDZ100 ) and for this purpose we need to find documentation for it. Any documentation will be useful including operation manual, electrical scheme, hydraulic scheme, drawings, etc.
Best regards
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Due to production discontinuation and company changes, locating technical documentation for the Fritz Heckert-EDZ100 test machine could be a challenge. Consider these avenues for assistance:
Contact the Manufacturer:
The first step is to contact the manufacturer of the machine. Here, the manufacturer is Fritz Heckert Werkzeugmaschinen GmbH, which has undergone several mergers and acquisitions over the years. You can try contacting the current manufacturer to see if they have any documentation or can provide any help with your machine. If they cannot help, they may direct you to a third-party service provider or other resources.
Online Resources:
Another option is to search online for technical documentation or manuals. You can try searching on machine tool forums, equipment trading websites, or other technical resources for similar machines. There may be other users or experts who have posted information or resources that can help you.
Third-Party Service Providers:
You can also try reaching out to third-party service providers who specialize in repairing and maintaining machine tools. They may have access to technical documentation or manuals for the Fritz Heckert-EDZ100, or they may provide help with your machine.
Reverse Engineering:
If you cannot find technical documentation or manuals for the Fritz Heckert-EDZ100, you may need to resort to reverse engineering. This involves taking apart the machine and analyzing its components and mechanisms to understand how it works and how it can be repaired or maintained. This approach can be time-consuming and potentially risky, as it may cause damage to the machine.
Keep in mind that technical documentation and manuals for older or discontinued machines may be difficult to find, but with persistence and a bit of creativity, you may uncover the information you need to maintain and repair your machine.
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is there any study to be done on revulsive compress on HRV?
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No studies were done on HRV, done one pain and blood flow using revulsive compress
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What mechanical tests are important for magnesium scaffolds that have a high percentage of porosity and are produced by powder metallurgy? Does this include only compression tests? Can bending and cutting tests be performed on this type of scaffold or not? I need information on mechanical properties such as shear, tension and compression for simulation in Abaqus software. I have successfully performed the compression tests, but the tensile test was unsuccessful.
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By computing the slope of the linear regression between σ30 and σ90, which correspond to 30 and 90% of the ultimate stress, one may derive Young's modulus from the stress-strain curves.
Utilising SEM and XCT, research on the alloy's deterioration SHOULD be conducted.
Fatigue simulation using FEA approach.
dynamic corrosion,
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I am struggling to define the sample size of specimen for Tension Compression Fatigue Testing of Polymer Matrix Composites. Is there any ASTM standard for the same? If not, what sample size should I take to avoid buckling of the sample. I want to test at R=-1. For tension-tension fatigue testing I will be following ASTM D3479 standard.
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You can base your sample size on similar, high-quality research published in highly ranked journals. With the same sample sizes they took, you can justify your work scientifically.
It is also possible to suffice by knowing that a sample >=30, this size is called a large sample according to all statistical books and references. If you can reach this size, it is scientifically justified.
You can use the basic function to calculate the Cochrane sample size, but the sample size will be large and range from 100 to 400 and this may be expensive for you.
In the end, I advise you to use the G-POWER software, as it is easy to use and simple, and its options are clear and comprehensive.
Best wishes,
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Currently, I am doing research based on AGA_NX19 algorithm to find the compressibility factor of natural gas.
In this algorithm, super compressibility factor is calculated, I need to know how I can find Z(compressibility at measured condition) and Zb (compressibility at the base condition).
At this standard according to the following formula, Zb is not considered while different regions consider different pressures and temperatures as base conditions.
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Zahra Salamati Calculating compressibility at the base condition using the AGA_NX19 algorithm involves several steps. Here's a step-by-step guide to help you understand how to find Z (compressibility at measured condition) and Zb (compressibility at the base condition) according to the AGA_NX19 algorithm:
  1. Understand the AGA_NX19 Algorithm:Familiarize yourself with the fundamentals of the AGA_NX19 algorithm, which is used to calculate the compressibility factor of natural gas. Gain a comprehensive understanding of the equations and methodologies employed in the algorithm for different operating conditions.
  2. Review the AGA NX-19 Standard:Study the AGA NX-19 standard documentation, including the specific guidelines and formulas for determining the compressibility factor at the base condition and the measured condition. Review the parameters and reference values required for the calculation process.
  3. Implement the Standard Calculation Method:Follow the prescribed calculation method specified in the AGA NX-19 standard to determine the compressibility factor at the base condition (Zb) based on the provided equations and reference conditions. Ensure that you input the relevant parameters accurately, including pressure, temperature, and composition data.
  4. Verify Input Parameters and Assumptions:Validate the input parameters and assumptions utilized in the AGA NX-19 algorithm, ensuring that the data corresponds to the appropriate reference conditions and is consistent with the characteristics of the natural gas being analyzed. Confirm the accuracy of the input data to obtain reliable results.
  5. Consult AGA Publications and Resources:Consult relevant AGA publications, technical resources, and research papers that provide detailed insights into the AGA NX-19 algorithm and its application in determining the compressibility factor of natural gas. Refer to case studies and practical examples to gain a comprehensive understanding of the implementation process.
  6. Utilize Specialized Software Tools:Consider using specialized software tools and applications that support the AGA NX-19 algorithm and facilitate the calculation of compressibility at the base condition. Leverage advanced software functionalities to streamline the computation process and obtain accurate results efficiently.
By following these steps and leveraging the available resources and documentation related to the AGA_NX19 algorithm, you can effectively calculate the compressibility factor of natural gas at the base condition and the measured condition, ensuring the accurate characterization of gas behavior in your research study.
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I was doing the compression tests on previously thermomechanically deformed pure titanium. The samples were uniaxially compressed in room temperature. The samples were cylindrical, and their dimmesions were 12 mm in diameter and 4.5 mm in height.
In order to fit an extensometer into INSTRON machine two additional fixtures were put between grips and the sample.
What can cause the concave shape of my curves at the begining of compression?
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Why should it not be? Conduct tests on more number of specimens to confirm repeatability. I find it as the normal elastic and elasto-plastic behaviour of the material.
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I am doing my thesis on pull-out test and my problem is in the compressive damage . Please guide me with an article and an example to solve my problem.
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Amin Borhan, Not exactly same but you can watch if it is helpful: https://www.youtube.com/watch?v=YE2QFLRL_vU
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I am having trouble with penetration between my corrugated core and rigid platen. My model is simulating a quasi-static compression. the top platen compresses and the bottom is fixed. As shown in the images I have penetration at the bottom and top of the corrugated core and analytical rigid platen. I use a node to surface interaction with the master being the platen and the secondary is the nodes along the top and bottom core. I can't use a line as a surface so I have to use the nodes. Is there any way to remove penetration?
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Chase Mortensen, the surface to surface interaction with smaller slave surface mesh density will solve the problem. For more, let's connect on WhatsApp to discuss; https://wa.me/+923440907874
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Hello everyone
I'm modeling a steel-reinforced coupling beam in DIANA which is embedded to an adjacent shear wall. I want to model rods in the embedment region, which only transfer axial loads in compression. For further explanation, these rods are fully attached (welded let's say) to some steel plates, where the steel section of the beam is ONLY placed on these steel plates (there is no connection such as weld or bolts). Therefore, these rods only work if they are in compression. Since all these rods, steel plates, and steel beam are surrounded by concrete, therefore I think these rods can only experience axial deformations.
I'm wondering if there is an specific type of an element in DIANA which only resist compression forces and axial deformations, or I should apply these features by defining some interfaces.
I appreciate every one's time and attention in advance.
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To define an axial element in DIANA software that only transfers compression, you can use the following methods:
Method 1: Using a linear spring with zero stiffness in tension
  1. Create a new material with a Young's modulus of zero and a Poisson's ratio of 0.5.
  2. Create a new element type using the linear spring element template and select the new material.
  3. Draw the element in your model and assign it to the new element type.
Method 2: Using a nonlinear spring with a bilinear stiffness curve
  1. Create a new material with a nonlinear stress-strain curve that has a bilinear shape. The first branch of the curve should have a finite stiffness in compression, and the second branch should have a stiffness of zero.
  2. Create a new element type using the nonlinear spring element template and select the new material.
  3. Draw the element in your model and assign it to the new element type.
Method 3: Using the enhanced truss element
  1. Draw the element in your model and assign it to the enhanced truss element type.
  2. Edit the element properties and set the "Tension stiffness" parameter to zero.
All of these methods will create an axial element that can only transfer compression loads.
Based on the image you provided, I recommend using the enhanced truss element type with zero tension stiffness. This will model the behavior of the rods in the embedment region accurately.
To create the enhanced truss element, follow these steps:
  1. In the DIANA menu, go to Elements > Create Element Type.
  2. In the Create Element Type dialog box, select the Enhanced Truss element type and click OK.
  3. In the Enhanced Truss Element Type dialog box, set the following parameters:Material: Select the material that you want to use for the element. Cross-section: Select the cross-section that you want to use for the element. Tension stiffness: Set the tension stiffness to zero.
  4. Click OK to create the new element type.
Once you have created the enhanced truss element type, you can draw it in your model and assign it to the rods in the embedment region.
Please note that it is important to make sure that the nodes of the enhanced truss elements are properly connected to the nodes of the surrounding concrete elements. This can be done using the Connect Nodes command in the DIANA menu.
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I want to model a cold formed steel tube in abaqus. Major longitudinal tensile residual stresses exist on the outside surfaces of the section, and equivalent longitudinal compressive stresses exist on the inside surfaces of the section.
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To model a cold-formed steel tube with major longitudinal tensile residual stresses on the outside surfaces and equivalent longitudinal compressive stresses on the inside surfaces in Abaqus, you can follow these steps:
Geometry Creation:
Create the geometry of the cold-formed steel tube using the appropriate CAD software or Abaqus built-in modeling capabilities.
Material Definition:
Define the material properties for the cold-formed steel tube in Abaqus. This should include the Young's modulus, Poisson's ratio, and yield stress of the material.
To incorporate the residual stresses, you can define them using the "Initial stresses" option. Specify the appropriate tensile residual stress value for the outside surfaces and the equivalent compressive residual stress value for the inside surfaces.
Meshing:
Generate a suitable mesh for the cold-formed steel tube geometry using Abaqus meshing capabilities. Ensure that the mesh is fine enough to capture the desired details and deformations accurately.
Boundary Conditions:
Apply appropriate boundary conditions to simulate the loading and constraints in your model. These conditions may include fixed displacements or prescribed loads depending on your specific analysis requirements.
Loading:
Apply the actual loading conditions that you want to simulate on the cold-formed steel tube. This could include tensile, compressive, or bending loads, depending on your analysis objectives.
Analysis Setup:
Define the analysis settings such as time steps, convergence criteria, and element types.
Specify the appropriate analysis type, such as static or dynamic analysis, depending on the nature of your problem.
Solve and Post-Processing:
Run the analysis and monitor the convergence. After the analysis is complete, examine the results to obtain the desired information, including stress distributions, deformations, and any other quantities of interest.
Remember that modeling residual stresses accurately can be challenging, and the specific approach may vary depending on the complexity of the manufacturing process used for cold forming the steel tube. It is recommended to consult relevant literature, research papers, or experts in the field for more specific guidance on modeling residual stresses in cold-formed steel tubes within Abaqus.
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I did compression test on Instron 8801 UTM machine. I like to validate my obtained compression stress, Compression strength value in simulation software. My crosshead displacement speed is 2mm/min.
In this case, which module I need to select? ( Static structural or dynamic or quasi static or non linear simulation).
I am using Fusion 360 for simulation. How to correlate the compression stress with the simulated results.
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Yes, it is possible to validate Universal Testing Machine (UTM) compression test results using simulation software. Simulation software can be used to model and analyze the behavior of materials under different loading conditions, such as compression tests. This allows you to compare the simulation results with experimental data obtained from UTM compression tests, aiding in validation and improving the understanding of material behavior.
Here's a general process for validating UTM compression test results using simulation software:
1. **Material Characterization:** First, you need to accurately characterize the material properties that will be used in the simulation. This includes parameters like Young's modulus, Poisson's ratio, yield strength, etc.
2. **Geometry and Boundary Conditions:** Create a simulation model that replicates the geometry and boundary conditions of your actual UTM compression test setup. This might involve creating a virtual sample of the material and defining how it is clamped or constrained.
3. **Apply Loads:** Apply the same or similar loading conditions as used in the UTM test. This could involve applying a compressive force or displacement to the virtual sample.
4. **Simulation:** Run the simulation using appropriate numerical methods, such as finite element analysis (FEA) or finite difference analysis. The software will calculate how the material responds to the applied loads.
5. **Compare Results:** Once the simulation is complete, compare the results obtained from the simulation with the experimental results from the UTM compression test. Compare quantities like stress-strain curves, deformation patterns, and failure points.
6. **Adjust Parameters:** If there are discrepancies between the simulation and experimental results, you might need to adjust material properties, boundary conditions, or other simulation parameters to improve the match.
7. **Iterative Process:** Simulation and validation can be an iterative process. You might need to make several adjustments to the simulation setup to achieve a close match with the experimental results.
8. **Validation Criteria:** Define specific validation criteria that the simulation results should meet, such as peak load, deformation at failure, stress-strain curve shape, etc.
It's important to note that the accuracy of the simulation depends on the accuracy of the material properties, boundary conditions, and the fidelity of the simulation software itself. Additionally, the simulation is a model of the real-world behavior and might not capture all intricacies of the actual test. Therefore, careful calibration, validation, and consideration of the limitations are essential.
Popular simulation software used for these purposes includes Abaqus, ANSYS, COMSOL, and others. The specific software you choose will depend on your familiarity, the features it offers, and the level of detail you require in your simulation.
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Homogeneous Charge Compression Ignition (HCCI) and Gasoline Direct Injection (GDI) are advanced engine technologies that aim to improve engine efficiency and reduce emissions in modern automotive engines. Each technology offers unique advantages that contribute to overall performance enhancements. Here's how HCCI and GDI achieve these objectives:
  1. Homogeneous Charge Compression Ignition (HCCI): HCCI is a combustion technology that combines features of traditional spark ignition (SI) engines and compression ignition (CI) engines. In HCCI engines, a homogeneous mixture of air and fuel is compressed to a high temperature and pressure, causing spontaneous ignition without the need for a spark plug. This combustion process allows for more complete and efficient burning of the fuel-air mixture, leading to several benefits:
a. Improved Efficiency: HCCI engines operate at higher compression ratios, similar to diesel engines, resulting in higher thermodynamic efficiency. The higher compression ratios contribute to better fuel economy compared to conventional SI engines.
b. Reduced CO2 Emissions: HCCI's improved combustion efficiency leads to lower fuel consumption, resulting in reduced carbon dioxide (CO2) emissions, a significant greenhouse gas.
c. Lower NOx Emissions: The absence of a flame front in HCCI combustion reduces peak temperatures and, consequently, nitrogen oxide (NOx) emissions, a major contributor to air pollution.
  1. Gasoline Direct Injection (GDI): GDI is a fuel injection technology that precisely injects fuel directly into the combustion chamber of each cylinder in a spark-ignited gasoline engine. Unlike traditional port fuel injection (PFI), where fuel is injected into the intake manifold, GDI offers several advantages:
a. Better Combustion Control: GDI allows for more precise control of the air-fuel mixture, enabling stratified charge combustion. The stratified mixture creates leaner conditions during low-load operation, leading to improved efficiency.
b. Higher Compression Ratios: GDI's ability to control the air-fuel mixture facilitates higher compression ratios, leading to improved thermal efficiency and fuel economy.
c. Reduced Particulate Matter (PM) Emissions: GDI can help reduce particulate matter emissions compared to PFI, as the fuel is directly injected into the combustion chamber, leading to better fuel-air mixing and more complete combustion.
d. Enhanced Knock Resistance: GDI can inject small amounts of fuel during the compression stroke to create a charge cooling effect, which improves the engine's knock resistance, allowing for higher compression ratios and more advanced ignition timing for improved efficiency.
By leveraging HCCI and GDI technologies, automotive engineers can achieve higher engine efficiency, reduced fuel consumption, and lower emissions. These advancements play a crucial role in meeting stringent emissions regulations and achieving sustainable mobility goals in modern automotive engines. However, it's important to note that implementing these technologies requires careful engine calibration and control strategies to ensure proper combustion and avoid potential challenges such as uncontrolled combustion, engine knock, and particulate matter formation.
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HCCI and GDI are two technologies that aim to improve the efficiency and reduce the emissions of gasoline engines. HCCI stands for homogeneous charge compression ignition, and GDI stands for gasoline direct injection.
HCCI is a combustion mode that uses a homogeneous mixture of air and fuel that is compressed and ignited by the high temperature and pressure in the cylinder, without the need for a spark plug. This allows for a higher compression ratio, lower fuel consumption, and lower emissions of nitrogen oxides (NOx) and particulate matter (PM) compared to conventional spark ignition engines. However, HCCI also has some challenges, such as controlling the combustion timing, preventing engine knock, and extending the operating range¹.
GDI is a fuel injection system that injects gasoline directly into the cylinder, instead of into the intake manifold. This allows for a better control of the air-fuel ratio, a higher power output, and a lower fuel consumption compared to port fuel injection engines. GDI also enables the use of stratified charge combustion, where a rich mixture of fuel and air is injected near the spark plug, while a lean mixture is present in the rest of the cylinder. This reduces the heat losses and increases the thermal efficiency².
By combining HCCI and GDI, it is possible to achieve a more flexible and efficient combustion system that can switch between different modes depending on the engine load and speed. For example, HCCI can be used at low to medium loads, where it offers high efficiency and low emissions, while GDI can be used at high loads, where it provides high power and torque³. Some research studies have investigated the effects of injection timing and air swirl on the fuel stratification, combustion, and emissions formation of GDI-HCCI engines²³. The results show that these parameters can influence the combustion stability, efficiency, and emissions of NOx, CO, HC, and PM in different ways.
In summary, HCCI and GDI are two technologies that enhance engine efficiency and reduce emissions in modern automotive engines by using different combustion modes and fuel injection systems. They can also be combined to create a more flexible and adaptable combustion system that can optimize the performance under different operating conditions.
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Hi everyone,
I recently ran some compression tests for hydrogels and received data in form of force (N) and displacement (mm). I am new to this area so would really appreciate your help here. For starters, I know that I need to convert it into Stress (pascal) vs Strain data (mm/mm). However I am really confused how I need to represent my strain. I have converted the force into stress by dividing with area of upper plate but with strain I am lost between engineering strain ((Io-I)/I) and true strain (Ln(I/Io)). Would be obliged if you can kindly shed some light into it.
Thanks in advance
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Analyzing compressive test data from a rheometer for Young's modulus involves several steps:
Data Preparation: Ensure you have collected accurate and consistent data from the rheometer. The data should include stress and strain measurements obtained during the compressive test.
Stress-Strain Curve: Plot the stress (force applied) against strain (deformation) to create a stress-strain curve. This curve provides insights into the material's behavior under compression.
Linear Elastic Region Identification: In the stress-strain curve, identify the linear elastic region where the material behaves elastically. This is typically the initial part of the curve, before any significant plastic deformation occurs.
Young's Modulus Calculation: Young's modulus (E) represents the stiffness of a material and is calculated using the formula:
E = Stress / Strain
In the linear elastic region, stress is directly proportional to strain. Calculate the slope of the linear portion of the stress-strain curve to determine Young's modulus. The slope can be calculated as:
Slope = ΔStress / ΔStrain
Young's modulus is then the reciprocal of the slope.
Data Fitting: You can also use data fitting techniques to extract Young's modulus. Fit the linear portion of the stress-strain curve to a linear equation (y = mx + b), where 'm' is the slope (Young's modulus).
Units: Ensure that the units of stress and strain are consistent (e.g., stress in Pascals and strain as a dimensionless ratio or percentage) to obtain the correct unit for Young's modulus (Pascals or N/m²).
Report: Present the calculated Young's modulus along with the method used for analysis, any assumptions made, and the range of strains over which the calculation was performed.
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Hello everyone,
Attached you will find these pictures where i realized the job (compression only surface displacement) in Ansys Software. Everything is going well but in Abaqus CAE model, i can't find it.
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I didn't have more knowledge in mechanical.but iam having knowledge in xontrol syatem and also in electrical
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Good day to everyone,
I have constructed scaffolding. For this purpose, I attempted to perform a compression simulation based on experimental compression data, as we are required to input certain properties into a simulation physics.
My question is how can I determine the simulated young modulus and compare it to the experimentally obtained young modulus, even though I am providing the experimental data as input?
Also, I wish to determine the anisotropy properties of the designed scaffold as well.
Thank you in advance.
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Regards
Rajkumar
IIT Kanpur, India
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Thank you Dr. Kristaq Hazizi for your insightful suggestions. You have cleared my doubt regarding the same. But still I have one confusion from point no. 2 (from upper most paragraph). While extracting the simulated young modulus from stress strain curve during the simulation, would it be same as the experimental one have ?
It is because, we are giving the experimental initial yield point as the input into the model, so curve will start to turned from that point only and will gave the same linear elastic region that the experimental one have. So I think young modulus will come same, then how can we compare them ?
Regarding the anisotropy, I fully understand it.
Thank you once again for giving your valuable time.
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Regards
Rajkumar
IIT Kanpur, India
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How to do quasi static compression test (2mm/min) in ansys Workbench? Please help me
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5. To set the displacement of the loading step to 2mm/min, click on the "Displacement" tab and enter "2" in the "Value" field.
Hello Sir
Rana Hamza Shakil
As you have mentioned displacement 2 that means total displacement is two, here, i am unable to figure out how the rate of displacement has been defined in your solution. please let me know.
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Hi,
I made some alginate discs and calculated their rheological properties, however, after much searching I found this equation which is below and lets me calculate the Young Modulus. However, I wanted to make sure their are not any other ways of calculating it from frequency sweeps gained from a rheometer. Is there a better way.
G = E / [2(1 + ν)]
where: E — Modulus of elasticity in tension or compression, also known as Young's modulus; ν — Poisson's ratio, another material constant; and. G — shear modulus (also known as modulus of rigidity).
Any help you could give would appreciated.
Best wishes,
Abdullah
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Check out the full lame constant table. An example is below but there are many sources
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I was trying to create a FEM model of an LVI and CAI experiment. For the CAI simulation, the load displacement curve I obtained is way too stiff compared to the experimental result. The maximum compression load is already quite similar with the experiment. Is there parameters that I can change to reduce the compressive stiffness ?
The simulation model was created in the ABAQUS Explicit solver. The composite plate is divided into 16 layers of laminate and 15 layers of interfaces. Each layer of laminate and interface have thickness of 0.215 mm and 0.025 mm respectively. The laminate was meshed with SC8R and use the Hashin damage model. The interface layer is modelles using COH3D8 elements and the QUADS damage criterion and energy based Benzeggah damage evolution.
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Mohamad Khorashad
Here is the comparison between the abaqus and experimental result. I have tried using denser and coarser mesh but the curve gradient does not change. As for the damage, the lvi delamination area is bigger on the simulation, but the peak force is similar as seen in the lvi curve.
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Imagining you have 1 m3 cubed container made out of steel and inside the container is 5 bar. What will the force be felt on the container if the pressure inside suddenly drops to 1 bar? Temperature can be omitted if needed.
Trying to design a yield limit for pressure-drop resistant materials through tensile/compressive measurements.
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The force acting on the walls of the container due to the pressure inside can be calculated using the formula:
F = P * A
where:
  • F is the force,
  • P is the pressure, and
  • A is the area.
Given a cubical container with an edge length of 1 m, one side's surface area (A) is 1 m^2. Since a cube has six faces, the total surface area is 6 m^2.
When the pressure inside the container drops from 5 bar to 1 bar, the pressure change (ΔP) is -4 bar. Converting this to pascals (since 1 bar equals 100,000 Pa), the pressure change is -400,000 Pa or -400,000 N/m^2.
So, the total force change experienced by the walls of the container is:
ΔF = ΔP * A ΔF = -400,000 N/m^2 * 6 m^2 ΔF = -2,400,000 N
The negative sign indicates that the force has decreased due to the pressure drop.
The stress on the walls of the container is the force divided by the area over which the force is distributed. In this case, the change in stress on the walls is equal to the change in pressure because the area cancels out:
Δσ = ΔF / A Δσ = -400,000 N/m^2
This means the stress on the walls of the container decreases by 400,000 N/m^2 due to the pressure drop. This stress is what your material must be able to withstand. The yield limit of your material, obtained through tensile or compressive tests, should be higher than this value to prevent deformation.
Please note that this calculation assumes that the stress is evenly distributed over the walls of the container, and ignores other potential factors such as strain hardening, material defects, or localized stresses due to design features (like welds, or changes in thickness). A more detailed analysis using mechanical engineering and material science principles would be needed for a thorough safety assessment.
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Please let me know.
Regards,
Saiyad
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When creating a material model for finite element analysis (FEA) in ABAQUS, or any other FEA software, using representative data for the material's properties is crucial. For 3D printed parts, this can be tricky because the material properties can vary depending on the specifics of the 3D printing process, such as the type of 3D printing (e.g., fused deposition modelling, selective laser sintering), the specific printer used, the print settings (e.g., layer thickness, print speed), and the material used.
Using Young's Modulus from tensile test data and yield stress, ultimate strength, and plastic strain values from compression test data is common in cases where the material exhibits significantly different behaviour under tension and compression. However, you must ensure the material's response under the loading conditions of interest is accurately represented.
In general, ABAQUS does not limit the source of your material properties. It only requires the user to define the material properties correctly for the particular material model chosen in ABAQUS. However, the user is responsible for ensuring that the properties inputted into the model accurately represent the real-world material.
Here are a few things you could consider:
  1. Homogeneity and Isotropy: Most conventional material models in ABAQUS assume that the material is homogeneous (properties are the same at all points) and isotropic (properties are the same in all directions). If your 3D-printed part does not meet these assumptions, you might need to consider a more advanced material model or modify the material properties based on the expected loading conditions.
  2. Experimental Data: Ideally, the material properties should be based on experimental data from tests conducted on samples produced under the same conditions as the final part. If you use data from the literature or the material supplier, you should ensure that it applies to your specific 3D printing conditions.
  3. Tensile vs Compression Properties: Some materials, especially composites and certain metals, can exhibit different properties under tension and compression. If your part is expected to experience both types of loading, you might need to include both data sets in your material model.
  4. Strain Rate Effects: The material properties can be rate-dependent if the loading conditions involve high strain rates (e.g., impact or blast loading). In this case, you must use a material model that includes strain rate effects.
Discussing these considerations with your project advisor or someone with expertise in FEA and the specific type of 3D printing you're using would be prudent.
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Myself Nekin Joshua R. I like to do Fatigue compression test on 3D printed Polymer based Structure.
What is the ASTM Standard for Fatigue Compression test on 3D printed Polymer based Honeycomb structure?
What is the Specimen Size?
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you would be best using ASTM D638-22for this test
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Binary sequences 1100100101
Symbolized by binary P(0)=1/2 P(1)=1/2 H(x)=-0.5*log2(0.5)-0.5*log2(0.5)=-1
Symbolized by quaternions
P(11)=1/5 P(00)=1/5 P(10)=1/5 P(01)=2/5 H(x)=-1/5*log2(1/5)*3-2/5*log2(2/5)=-1.9219
...
Is there a problem with my understanding?
If not ,which result is information entropy?
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Firstly, the calculated entropy in both cases is positive (entropy is always non-negative).
Secondly, the probability of each bit/symbol is calculated over a large number of occurrences.
Thirdly, entropy = 1 for 'Symbolized by binary' case means the entropy is maximum because each bit is equi-probable. On the other hand, for the 'symbolized by quaternions' case, the entropy < 2 because the calculations considers that all states are not equi-probable.
I hope it helps.
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i want to cite this article on research gate.
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Hello,
you can get to the journal's webpage via the doi of the article easily. You can find 'cite article' right below the title and authors. If you click this, you'll get a suggestion of how to cite this article (Andena L, Caimmi F, Leonardi L, Nacucchi M, De Pascalis F. Compression of polystyrene and polypropylene foams for energy absorption applications: A combined mechanical and microstructural study. Journal of Cellular Plastics. 2019;55(1):49-72. doi:10.1177/0021955X18806794).
However, different journals have different ways to cite. Thus you might adapt the citation accordingly to the journal's guidelines.
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The cell cycle of my MCF10a cells sometimes looks "compressed" with no clearly distinct phases. Other times I get a cell cycle that looks perfectly fine with clear phases and I can´t find a reason why I get such different results. I use DAPI to stain the cells, but I already checked the stain and the protocol and they are alright. So i think it might not be an issue with the staining itself but propably with the cells or the culture conditions or something else?
Has anyone had similar problems or has an idea what the problem could be?
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Thanks for your suggestions.
Yes I always use the same flowcytometer with the same settings.
I also tried out staining with PI but the cell cycle looked the same (bad) as with DAPI.
It´s a good point, I´ll attach two histograms with one "good" and one "bad" example. Maype that will clarify what my problem is.
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I am currently working on my thesis in Retrofitting of soft story. At first step i am trying to validate a experimental test. There i need to model a bracing with gap in it. The bracing should act only in compression after the gap is closed and free in tension. For creating simplified model i tried to create compression only element with uniaxial non linear elasticity model available for steel in Diana where i gave input to stress-strain diagram with very small value in tension and in compression, i gave nearly 0 value upto strain when gap closes and after that normal stress strain value of steel. I got the hysterisis result where there is increases in lateral resistance as compared to test result. how an i fix this? Is there any approach to model gap element? i tried contact analysis too but could not make it out.I have attached hysteresis result of Experiment and Diana Modeling. The bracing should start working after 1% drift.
Thank you.
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Add an interface element with your manual stiffness properties almost 0 till a certain displacement and then increase the stiffness when the gap is closed.
drop me an email if you need more info.
a.vandenbos_NLyseConsultants.com
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I have a word file and want to sent via an email but I am unable to compress it without changing the format. I need it to be in word as it has track changes responses.
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Compess it wice.
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Hello everyone,
I am developing a FE model with cohesive elements in ABAQUS 6.13-1 . As mentioned in the "Linear elastic traction-separation behavior" paragraph of the Abaqus Documentation:
a compression factor can be set for cohesive elements with uncoupled traction-separation behavior, so that their compressive stiffness is equal to the specified factor times the tensile stiffness. The only way to define the compression factor is to comprise the following command in the input file of the model:
*ELASTIC, TYPE=TRACTION, COMPRESSION FACTOR=f
and replace f with the desired value. (It cannot be specified in Abaqus/CAE)
However, when I submit the job input file, the Analysis Input File Processor aborts the job with the error shown in the attached image.
Has anybody encountered the same problem?
Should I type this command in another way to make it acceptable?
Maybe it could be attributed to my version of ABAQUS and a more recent version is required to recognise this command?
P.S. The analysis runs and the results are exportable without any problem when the compression factor definition is not included in the input file. Also, the names of the job and the input file have knowingly been removed from the attached image.
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