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Combinatorics - Science topic

Combinatorics is a branch of mathematics concerning the study of finite or countable discrete structures. Aspects of combinatorics include counting the structures of a given kind and size (enumerative combinatorics), deciding when certain criteria can be met, and constructing and analyzing objects meeting the criteria (as in combinatorial designs and matroid theory), finding "largest", "smallest", or "optimal" objects (extremal combinatorics and combinatorial optimization), and studying combinatorial structures arising in an algebraic context, or applying algebraic techniques to combinatorial problems (algebraic combinatorics).
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Dear Researchers,
Do researchers/universities value students/researchers having published sequences to the OEIS?
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Dear Marco Ripà ,
I have done both. I cited my work in the sequences and the sequences in my work.
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Let G be cubic plane graph such that every face boundary of G is of length divisible by four. By an indirect proof, it follows that the number of vertices in G must be divisible by eight.
Can you prove this by an elementary method? (which should be possible I think, though I don't have such a proof).
Disclaimer: Cross-posted in stackexchange (https://cstheory.stackexchange.com/q/50959/47855).
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This is NOT an answer to the question; rather a comment on the answer by Peter Breuer .
Yes, a cubic graph is graph such that every vertex has degree three. And, by "face boundary" I mean the edges that form the boundary of a face, and "length" means the number of edges in that boundary.
Thank you for your effort. But, the argument "he number of edges must be some multiple of 4 times the number of faces" seems wrong to me. For instance, a graph can have exactly 3 faces with boundary lengths 4,8 and 8 respectively, yet 4+8+8 is not a multiple of F=3.
Remark: The above one is not an actual example though; a graph with 10 faces and face boundaries 8,8,4,4,...,4 is a proper counterexample to the argument.
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Is the reciprocal of the inverse tangent $\frac{1}{\arctan x}$ a (logarithmically) completely monotonic function on the right-half line?
If $\frac{1}{\arctan x}$ is a (logarithmically) completely monotonic function on $(0,\infty)$, can one give an explicit expression of the measure $\mu(t)$ in the integral representation in the Bernstein--Widder theorem for $f(x)=\frac{1}{\arctan x}$?
These questions have been stated in details at the website https://math.stackexchange.com/questions/4247090
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It seems that a correct proof for this question has been announced at arxiv.org/abs/2112.09960v1.
Qi’s conjecture on logarithmically complete monotonicity of the reciprocal of the inverse tangent function
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Dear Colleagues
I need an inequality for the ratio of two Bernoulli numbers, see attached picture. Could you please help me to find it? Thank you very much.
Best regards
Feng Qi (F. Qi)
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Dear Collegues,
Could you please recommend conferences in 2019-2021 having Finite Group theory and Combinatorics in their topics?
I will be very thankful for any references!
Thanks in advance!
Best wishes,
Natalia
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In addition to the excellent suggestions of Mohamed Amine Bahayou I would recommend this conference list: faculty.math.illinois.edu/~west/meetlist.html
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Do you know the web sites of the journals Ars Combinatoria and Utilitas Mathematica? Are these two journals ceased? One of my manuscripts was accepted a long time ago for publishing in the first journal, but now I cannot contact any editor, I cannot find its website, and I cannot get any message of these two journals. So I wonder if these two journals have been ceased.
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Dear colleagues,
I trust you are fine. As far as I know, new managing editors and editors-in-chief for Ars Combinatoria have been chosen. I remember, the last time I saw their website, they had written they would create a new website on which the papers would be appear (not only their titles with the names of authors as before). You can ask Dr. J.L. Alston, the former managing editor of Ars Combinatoria about this.
Regards,
Babak
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I need some suggestions what are the growing topics in algebraic combinatorics and graph theory for research? Thank you in advance to everyone who will answer.
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(enhanced) power graphs of groups
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I have written an analysis article but cannot seem to find an appropriate journal.
Could you recommend average level journals as well as low level journals in analysis?
Thank you for participating in this discussion.
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The journal “American Journal of Mathematical Analysis” http://www.sciepub.com/journal/ajmais published by Science and Education Publishing (SciEP) a publisher included in the Beall’s list of potentially predatory publishers: This is a red flag. There are more, for example: https://beallslist.net/
-Misleading contact address suggesting US origin while they are not
Better avoid.
Roudy El Haddad indeed the journal “Moroccan Journal of Pure and Applied Mathematics” 2605-6364 https://sciendo.com/journal/MJPAA is having a pretty solid publisher behind it and received a Scopus indexing https://www.scopus.com/sourceid/21101026926, so most likely a safe choice.
The journal “International Journal of Nonlinear Analysis and Applications” https://ijnaa.semnan.ac.ir/ seems a pretty safe choice as well. Scopus indexed https://www.scopus.com/sourceid/21100873480 and indexed in ESCI.
Best regards.
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I have confirmed that the Hessenberg determinant whose elements are the Bernoulli numbers $B_{2r}$ is negative. See the picture uploaded here. My question is: What is the accurate value of the Hessenberg determinant in the equation (10) in the picture? Can one find a simple formula for the Hessenberg determinant in the equation (10) in the picture? Perhaps it is easy for you, but right now it is difficult for me.
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In the 19 hundreds, many though that an explicit formula for the partition function was never going to be found. In 2011, finally, an explicit formula for the partition function was discovered.
For that reason, I am fascinated by how close do mathematicians think we are currently to discovering an explicit formula for prime numbers.
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How many more years do you predict it will take before the Riemann Hypothesis is solved?
Do you think we are close or does it seem that we are still very far?
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I agree with you. Although year after year we are getting closer. A few year ago, it was proven that at least 40% of zeros have to be on the critical line. So a lot of progress has been done. Many conjecture have also been presented, which if proven, they would imply the Riemann Hypothesis. So have gotten some important result, however, we have not quite solved it yet.
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I have written two articles about a generalization of Multiple zeta values and Multiple zeta star values. I also presented applications for this generalization including partition identities, polynomial identities, a generalization of the Faulhaber formula, as well as MZV identities. If you are intrested check them out on my profile and give me your opinion.
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The Riemann Z function finds applications in physics Dear Roudy El Haddad, I just cannot remember all of them, but the theory of phase transitions, Planck radiation, statistical sums, we use the identities without too much thinking for several partition functions.
Also, some applications are related to the most general class of Z functions with multiple Z values.
The Riemann Hypothesis is somehow connected to some real eigenvalues of a hermitian “Riemann Operator” so that these zeroes are spectral, according to some authors (Lyon, 2008).
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I find that multiple sums are a very interesting concept. However, an even more interesting concept for me is the sum of such sums (the sum of multiple sums). The sum of multiple sums can be turned into a simple product by the formula in the first attached image.
What mathematical applications could this formula have? Where could it be useful?
I have found 2 interesting applications:
1- sum of multiple zeta values (see image 2).
2- sum of multiple power sums (see image 3).
Could you suggest any applications for these 2 particular cases? Could you suggest additional particular cases that would be of interest to mathematicians or physicists?
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Why are you asking?
Please respond when you read this.
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I am considering to distribute N-kinds of different parts among M-different countries and I wan to know the "most probable" pattern of distribution. My question is in fact ambiguous, because I am not very sure how I can distinguish types or patterns.
Let me give an example. If I were to distribute 3 kinds of parts to 3 countries, the set of all distribution is given by a set
{aaa, aab, aac, aba, abb, abc aca, acb, acc, baa, bab, bac, bba, bbb, bbc, bca, bcb, bcc, caa, cab, cac, cba, cbb, cbc, cca, ccb, ccc}.
The number of elements is of course 33 = 27. I may distinguish three types of patterns:
(1) One country receives all parts:
aaa, bbb, ccc 3 cases
(2) One country receives 2 parts and another country receives 1 part:
aab, aac, aba, abb, aca, acc, baa, bab, bba, bbc, bcb, caa, cac, cbb, cbc, cca, ccb 17 cases
(3) Each county rceives one part respectively:
abc, acb, bac, bca, cab, cba 6 cases
These types may correspond to a partition of integer 3 with the condition that (a) number of summands must not exceed 3 (in general M). In fact, 3 have three partitions:
3, 2+1, 1+1+1
In the above case of 3×3, the number of types was the number of partitions of 3 (which is often noted p(n)). But I have to consider the case when M is smaller than N.
If I am right, the number of "different types" of distributions is the number of partitions of N with the number of summands less than M+1. Let us denote it as
p*(N, M) = p( N | the number of summands must not exceed M. )
N.B. * is added in order to avoid confusion with p(N, M), wwhich is the number of partitions with summands smaller than M+1.
Now, my question is the following:
Which type (a partition among p*(N, M)) has the greatest number of distributions?
Are there any results already known? If so, would you kindly teach me a paper or a book that explains the results and how to approach to the question?
A typical case that I want to know is N = 100, M = 10. In this simple case, is it most probable that each country receives 10 parts? But, I am also interested to cases when M and N are small, for example when M and N is less than 10.
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Thank, Luis Daniel Torres Gonzalez , you for your contribution. My question does not ask the probability distribution. It asks what is the most probable "pattern" when we distribute N-items among M-boxes. I have illustrated the meaning of "pattern" by examples, but it seems it was not sufficient. Please read Romeo Meštrović 's comments above posted in March, 2019.
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I am a researcher in combinatorics and Semigroup in Ahmadu Bello University, Zaria seeking to know the binding line between both.
Thank you.
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Thank you for your answers and recommendations.
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The following formally published papers are related to this question:
[1] Feng Qi, Diagonal recurrence relations for the Stirling numbers of the first kind, Contributions to Discrete Mathematics 11 (2016), no. 1, 22--30; available online at https://doi.org/10.11575/cdm.v11i1.62389
[2] Feng Qi and Jiao-Lian Zhao, Some properties of the Bernoulli numbers of the second kind and their generating function, Bulletin of the Korean Mathematical Society 55 (2018), no. 6, 1909--1920; available online at https://doi.org/10.4134/bkms.b180039
[3] Feng Qi and Bai-Ni Guo, A diagonal recurrence relation for the Stirling numbers of the first kind, Applicable Analysis and Discrete Mathematics 12 (2018), no. 1, 153--165; available online at https://doi.org/10.2298/AADM170405004Q
[4] Feng Qi and Bai-Ni Guo, Explicit formulas for special values of the Bell polynomials of the second kind and for the Euler numbers and polynomials, Mediterranean Journal of Mathematics 14 (2017), no. 3, Article 140, 14 pages; available online at https://doi.org/10.1007/s00009-017-0939-1
[5] Feng Qi, Da-Wei Niu, Dongkyu Lim, and Yong-Hong Yao, Special values of the Bell polynomials of the second kind for some sequences and functions, Journal of Mathematical Analysis and Applications 491 (2020), no. 2, Paper No. 124382, 31 pages; available online at https://doi.org/10.1016/j.jmaa.2020.124382
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Where to find the answer?
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The following formally published papers are related to this question:
[1] Feng Qi, Diagonal recurrence relations for the Stirling numbers of the first kind, Contributions to Discrete Mathematics 11 (2016), no. 1, 22--30; available online at https://doi.org/10.11575/cdm.v11i1.62389
[2] Feng Qi and Jiao-Lian Zhao, Some properties of the Bernoulli numbers of the second kind and their generating function, Bulletin of the Korean Mathematical Society 55 (2018), no. 6, 1909--1920; available online at https://doi.org/10.4134/bkms.b180039
[3] Feng Qi and Bai-Ni Guo, A diagonal recurrence relation for the Stirling numbers of the first kind, Applicable Analysis and Discrete Mathematics 12 (2018), no. 1, 153--165; available online at https://doi.org/10.2298/AADM170405004Q
[4] Feng Qi and Bai-Ni Guo, Explicit formulas for special values of the Bell polynomials of the second kind and for the Euler numbers and polynomials, Mediterranean Journal of Mathematics 14 (2017), no. 3, Article 140, 14 pages; available online at https://doi.org/10.1007/s00009-017-0939-1
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Bell polynomials of the second kind Bn,k(x1,x2,...,xn-k+1) are also called the partial Bell polynomials, where n and k are positive integers. It is known that Bn,k(1,1,...,1) equals Stirling numbers of the second kind S(n,k).
What are the values of the special Bell polynomials of the second kind Bn,k(0,1,0,1,0,1,0,...) and Bn,k(1,0,1,0,1,0,...)? Where can I find answers to Bn,k(0,1,0,1,0,1,0,...) and Bn,k(1,0,1,0,1,0,...)? Do they exist somewhere?
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The following formally published papers are related to this question:
[1] Feng Qi and Bai-Ni Guo, Explicit formulas for special values of the Bell polynomials of the second kind and for the Euler numbers and polynomials, Mediterranean Journal of Mathematics 14 (2017), no. 3, Article 140, 14 pages; available online at https://doi.org/10.1007/s00009-017-0939-1
[2] Feng Qi, Da-Wei Niu, Dongkyu Lim, and Yong-Hong Yao, Special values of the Bell polynomials of the second kind for some sequences and functions, Journal of Mathematical Analysis and Applications 491 (2020), no. 2, Paper No. 124382, 31 pages; available online at https://doi.org/10.1016/j.jmaa.2020.124382
[3] Feng Qi, Da-Wei Niu, Dongkyu Lim, and Bai-Ni Guo, Closed formulas and identities for the Bell polynomials and falling factorials, Contributions to Discrete Mathematics 15 (2020), no. 1, 163--174; available online at https://doi.org/10.11575/cdm.v15i1.68111
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Dear Researchers,
Kindly let me know about 5 top most research problems in number theory which are concerning to
Double series and / or combinatorics
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How to prove or where to find a proof of the lower Hessenberg determinant showed by two pictures uploaded here?
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Dear All Colleagues
The final version has been accepted for publication in the Mathematica Slovaca. For details, please click at the website:
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It is well known that for every nonnegative n, there exist Steiner triple systems STS(6n+1) and STS(6n+3). I see similarities between this statement and the one that I included in my question, but perhaps you can shed light on this issue. Thanks.
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According to a theorem of Doyen and Wilson, the answer to this question is "yes".
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From a combinatorics perspective, what if what you are requiring of the optimization algorithm is too scattered?
In other words, from a combinatorics perspective, what if what you are requiring in terms of the optimization problem specification, also referring to the constraints, including equality constraints, implies too scattered and sparse coefficient (variable cell) ranges.
Is this possible? The algorithm may then struggle to locate the feasible regions or ranges.
I am particularly referring to a nonconvex nonlinear optimization problem.
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Do you have bounded, e.g. binary, variables or unbounded ones. I the case of unbounded variables, the problem may not have an algorithm.
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I have three tasks for 3 participants - task 1 (EO), task 2 (BCST), task 3 (RMET). I use six measures - M1 (CD), M2 (LLE), M3 (HFD), M4 (MSE), M5 (MFDFA), M6 (Kc). I have 20 EEG channels. I use Wilcoxon signed rank to compare each channel pair between two states. I get p-values for 3 H: tests -1H0: EO=BCST, 2HO: BCST=RMET, 3H0: EO=BCST. The other three are reciprocal adding to 1. So comparing p-values from the tests I get 12 possible outcomes - 1: EO=BCST>RMET, 2: EO=BCST<RMET, 3: BCST=RMET>EO, 4: BCST=RMET<EO, 5: EO=BCST>RMET, 6: EO=BCST<RMET, 7: EO>BCST>RMET, 8: BCST>RMET>EO, 9: RMET>EO>BCST, 10: EO>RMET>BCST, 11: RMET>BCST>EO 12: BCST>EO>RMET.
Question: Given a confidence level of 0.05 is the probability of getting all 3 participants to have the same order based on p-values below the 0.05 CL threshold thus excluding any two tasks being equal based on the following: 0.05 x 0.05 x 0.05 x 6 x 6 = 0.0045?
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I have N lattice points which are arranged linearly and equally spaced. I want to make connections(say with some wire or thread) with each lattice site with another. The first one has N-1 possibilities and the second one has N-3 as each one cannot make connections itself and the first one has already formed one. So the total possibility is (N-1)(N-3)(N-5)(N-7)..... and so on. Now I want to impose two conditions.
Case(i): If I impose a condition that each site cannot be connected with the nearest neighbor, how many ways I can make the connections. How do complete this counting problem with this condition?
Case(ii): Apart from the above condition(immediate neighbors should not be connected), If I impose a further condition that each site can be connected with other or it can also be left unconnected. How do I count the number of ways doing this?
I know both case(i) and case(ii) will have different answers. I really don't know where to start this problem at all
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Is your lattice a line with N vertices?
And you want to connect them by forwarding paths? To make your question is clear. Assume that your lattice includes 4 vertices.
Sketch some graph, then attach it as a pdf file. Then we may help.
Best regards
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I am working on the  construction of Barnette graphs for given diameter. I would like to know the reason why many cubic 3 connected planar , (not  a bipartite)  are  both non-Hamiltonian and Hamiltonian graphs. I found a unique property of those Hamiltonian graphs. I need the latest results related to my question.
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If any one property of Barnatte graph is dropped it is non hamiltonion
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for k=1, 2, 3 we get 7, 13, 19 as primes.
for k=5,  6, 7 we get  31, 37,  43,  as primes.
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Such arithmetic progression does not exist. Namely, suppose that k_n=a+(n-1)d is a desired arithmetic progression, where a is a fixed integer, d is a fixed positive integer, such that 6k_n+1 is a prime number for all n=1,2,3,… . This means that 6k_n+1=6(a+(n-1)d)+1=(6a+1)+(n-1)(6d) would be an arithmetic progression containing only prime numbers. However, this is obviously impossible by the well known Prime Number Theorem for Arithmetic Progressions.
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Do you think that the iThenticate/CrossCheck/Similarity Index would cause heavy and serious confusion in mathematics? Even destroy, ruin, damage Mathematics? Our mathematics and mathematicians should follow and inherite symbols, phrases, terminology, notions, notations in previous papers, but now we have to change these to avoid, to escape, to hide, to decrease the iThenticate/CrossCheck/Similarity Index! It’s very ridiculous for mathematics and mathematicians! Mathematics is disappearing! being damaged!
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Yes! Even standard mathematical symbols and notations are captured in similarity index. The habit of using unconventional symbols and notations just to reduce similarity index is destroying the beauty and taste of mathematics.
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Many text books claim that particles that obey Boltzmann statistics have to be indistinguishable in order to ensure an extensive expression for entropy. However a first principle derivation using combinatorics gives the Boltzmann only for distinguishable and the Bose Einstein distribution for indistinguishable particles (see Beiser, Atkins or my own text on Research Gate). Is there any direct evidence that indistinguishable particles can obey Boltzmann statistics?
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Is it a variant of Vandermonde convolution formula for falling factorials? What is the answer? See the picture.
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See the picture uploaded here.
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Points are two-combinations of n phase names. Lines are three-combinations of phase names. Point and line are incident upon one another if the two phase names comprising the point are part of the name of the line (e.g., point AB and line ABE are incident upon one another). In attached figures, lines of perspective are red, perspective triangles are green, and points of perspective of pairs of green triangles are connected with orange lines. Brute force counting of adjacencies is doable for Desargues configuration (n=5) , but impractical as system number of phases increases.
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It's been a while, but I've finally achieved an answer to my question. In the Euclidean plane, given points as two-combinations of n phase names and lines are three-combinations of the phase names there must be 1 point adjacent to 2n-4, 2 points adjacent to 2n-5, 3 points adjacent to 2n-6, ..., n-1 points adjacent to n-2.
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A-B-C ABOUT IDENTIFICATION OF GRAPHS
John-Tagore Tevet
Let us try to open the essence of graphs, from that's so far tried to circumvent.
1. What is a graph
Graph is an association of elements with relationships between these that has a certain structure.
Graphs are represented for different purposes. On the early rock paintings have been found the constellations show schemes. Graphs was used also for explain the theological tenets.
Example 1. Graph (structural formula) of isobutane C4H10:
Graphs began to investigate after then when Leonhard Euler in 1736 has solved the problem of routing on the seven bridges between four banks of Königsberg [1].
Example 2. Königsberg’s bridges and corresponding graph:
Also in present time used the graphs mainly for solving the problems of routing and flowing. Already in 1976 considered that such one-sided approach is a hindering factor for studying of graphs [2]. To the essence of graph, to its structure and symmetry properties has the interest practically non-existent. The last explorer was evidently Boris Weisfeiler in 1976 [9].
Definition a graph as an object consisting in node set V and edge set E, G=(V, E), is a half-truth that beget confusions. Essential is to explain the properties of inner organizing (inner building) or structure, i.e. identification of graphs.
Graph is presentable: 1) as a list L of adjacencies; 2) in the form of adjacency matrix E; 3) graphically G, where the elements to “nodes” and relations to “edges” called.
Example 3. List of adjacencies L, corresponding adjacency matrix E and for both corresponded graphs GA and GB:
Explanations:
The outward look and location of the enumerated elements in graph not have something meaning. But on the emotional level it rather engenders some confusion.
One graph can be differs from the other on its looking or its inner organizing (inner-building) or structure S what in ordinarily visually not be opened. Maybe just due to this is to the present days the existence of structure ignored.
We can here make sure that graphs GA and GB have the same structure and these are isomorphic GA @ GB. Ordinarily differentiate in the objects just the “outward” differences and refuse to see some common structure.
 
Propositions 1. Structure axioms:
P1.1.    Structure S is presentable as a graph G and each graph G has its certain structure S.
P1.2.    Isomorphic graphs have the same structure – structure is the complete invariant of isomorphic graphs.
 
Identification of graph is based on identification the binary relations between elements [3 - 8]. Binary relation can a “distance relation”, “circle relation”, “clique relation” etc. and is measurable. Binary relation characterized by corresponding binary sign.
2. Identification of the graph
For identification of the graphs uses two each others complementary ways:
Multiplicative identification (products of adjacency matrixes);
Heuristic identification.
 
Propositions 2. Multiplicative identification: multiplication the adjacency matrixes:
P2.1.       To multiplying the adjacency matrix with itself E´E´E´…=En and fixing in case of each degree n the number p of different multiplicative binary signs enij that as rule enlarges. Forming the sequence vectors ui of different multiplicative binary signs.
P2.2.       In each case if p enlarges (change) must transpose the rows and columns of En correspondingly to the obtained frequency vectors ui.
P2.3.       Stop the multiply if p more no enlarges and to present the current En and the following En+1.
Explanation: Multiplicative signs differentiate the binary signs but no characterize these.
Example 4. Adjacency matrix E and its transposed products E2, E3 of graphs on example 3:
1  2  3  4  5  6| i
                0  1  0  1  0  1| 1
                1  0  1  0  1  1| 2
          E    0  1  0  1  0  1| 3
                1  0  1  0  1  0| 4
                0  1  0  1  0  1| 5
                1  1  1  0  1  0| 6
                                         ui
2  6| 1  3  5| 4     |    i    0 1 3 4   k
4  3| 1  1  1| 3     |    2    0 3 2 1   1
3  4| 1  1  1| 3     |    6    0 3 2 1   1
E2   1  1| 3  3  3| 0     |    1    1 2 3 0   2
1  1| 3  3  3| 0     |    3    1 2 3 0   2
1  1| 3  3  3| 0     |    5    1 2 3 0   2
3  3| 0  0  0| 3     |    4    3 0 3 0   3
ui
 2  6| 1  3  5| 4|   i    0 2 3 6 7 9 10  k
 6  7|10 10 10| 3|   2    0 0 1 1 1 0 3   1
 7  6|10 10 10| 3|   6    0 0 1 1 1 0 3   1
E3   10 10| 2  2  2| 9|   1    0 3 0 0 0 1 2   2
10 10| 2  2  2| 9|   3    0 3 0 0 0 1 2   2
10 10| 2  2  2| 9|   5    0 3 0 0 0 1 2   2
 3  3| 9  9  9| 0|   4    1 0 2 0 0 3 0   3
Explanations:
a)      The set of similar relations (and elements) recognize their position W in the structure. Position W is in group theory known as transitivity domain of automorphisnsms, equivalence class or orbit.
Multiplicative binary signs enij recognize here five positions of binary relations WR and on they base three positions of elements WV.
 
Propositions 3. Position axioms:
P3.1.       If structural elements (graph nodes) vi , vj , … have in graph G the same position WVk then corresponding sub-graphs (Gi=G\vi) @ (Gj=G\vj) @....   are isomorphic.
P3.2.       If relations (edges) eij, ei*j*, … have in graph G the same binary(+)position WR+n then corresponding greatest subgraphs (Gij=G\eij) @ (Gi*j*=G\ei*j*) @....  are  isomorphic.
P3.3.       If relations (“non-edges”) eij, ei*j*, … have in graph G the same binary(–)position WRn– then corresponding smallest supergraphs (Gij=GÈeij) @ (Gi*j*=GÈei*j*) @....  are isomorphic.
 
Before elaboration of the multiplicative identification way was elaborated a heuristic way.
Propositions 4. Heuristic identification:
P4.1.       Fix an element i and form its neighborhood Ni, where the elements, connected with i divide according to distance d to entries Cd.
P4.2.       Fix an element j and fix its neighborhood Nj by condition P4.1.
P4.3.       Fix the intersection Ni ÇNj as a binary graph gij, and fix the distance –d between i and j (in case of adjacency collateral distance +d), the number n of elements (nodes) in gij, number q of adjacencies (edges). Fixing the heuristic binary sign ±d.n.q.ij of obtained graph gij.
P4.4.       Realize P4.1 to P4.3 for each pair i,jÎ[1, |V|]. Obtained preliminary heuristic structure model SMH.
P4.5.       Fixing for each row i its frequency vector ui. Transpose the preliminary model SM by frequency vectors ui lexicographically to partial models SMk.
P4.6.       In the framework of SMk transpose the rows and columns lexicographically by position vectors si to complementary partial models. Repeat P4.6 up to complementary transposing no arises.
Explanation: Heuristic binary signs differentiate the binary signs and characterize these.
Example 5. On the Example 3 presented differently enumerated graphs GA and GB, their heuristic binary signs and structure models SMA and SMB with their common product E3:
ui
 3  4| 1  4  5| 2|   iA
 1  2| 1  2  5| 6|        iB    0 2 3 6 7 9 10  k
 6  7|10 10 10| 3|   3    3    0 0 1 1 1 0 3   1
    6|10 10 10| 3|   4    6    0 0 1 1 1 0 3   1
E3         | 2  2  2| 9|   1    1    0 3 0 0 0 1 2   2
…..  |    2  2| 9|   2    4    0 3 0 0 0 1 2   2
     |       2| 9|   5    5    0 3 0 0 0 1 2   2
     |        | 0|   6    2    1 0 2 0 0 3 0   3
Explanations:
”Diverse” graphs GA and GB have equivalent heuristic structure models SMA » SMB and the same multiplicative model E3. This means that structures are equivalent and all on the examples 2 and 4 presented graphs GA and GB are isomorphic GA @ GB.
The binaries are divided to five binary positions WRn, where the “adjacent pairs” or “edges” divided to three binary(+)positions (full line, a dotted, dashed-line) that coincide with heuristic binary signs C, D, E and corresponding multiplicy binary signs 10, 7, 2, and with two binary(–)positions with signs –A and –B and multiplicative signs 9 and 3. In base of these divide the structural elements to three positions WVk.
The column ui constitutes frequency vectors, where each element i characterize its relationships with other elements. On the base of frequency vectors ui obtained the positions of elements WVk.
The column si constitutes position vectors that represent the connecting of i with elements on the position k.
A principal theoretical algorithm of isomorphism recognition exists really – it consists in rearranging (transposing) the rows and columns of adjacency matrices EA of graph GA as yet these coincides with the EB of GB. But this has an essential lacking – it is too complicated, the number of steps can be up to factorial n!
Propositions 5. On the relationships between isomorphism and structural equivalence:
P5.1.    Isomorphism GA@GB is a such one-to-one correspondence, a bijection j: VA®VB, between elements what retains the structure GS of graphs GA and GB.
P5.2.    Isomorphism recognition does not recognize the structure GS and its properties (positions etc.), but the structure models SM and En recognize the structure and its properties with exactness up to isomorphism.
P5.3.    Structural equivalence SMA»SMB and EnA»EnB is a coincidence or bijection j: WA®WB on the level of binary positions WRn and positions of nodes (elements) WVk.
P5.4.    In the case of large symmetric graphs recognizes the products En the binary positions more exact than heuristic models SM, where need to use the binary signs of higher degree. That why it is necessary to treat both in together, bearing in mind also that the heuristic binary signs characterize the essence of relationship itself.
P5.5.    Recognition of the positions by the structure model is more effective than detecting the orbits on the base of the group AutG.
Example 6. To the recognition on the Example 1 represented structure of isobutane suffice use the heuristic model SM:
Explanation: Decomposing the elements C and H to four positions corresponds to actuality. The positions are visually appreciable also on the Example 1.
3. List of tasks that solving based on the identified graphs (structure)
To conclusion it should be emphasized that the recognition of graph’s structure (organizing) is based on the identification (distinction) of binary relations between elements. Binary relation can be measured as a “relation of the distance”, “circle relation”, “clique relation”, etc. Binary relation is recognizable by the corresponding binary sign.
The complex of tasks that are based to recognizing structures is broad, various and novel (differ from up to now set up) [3 - 8]. We list here some.
1.      The relations between structural positions, automorphismsm and group-theoretical orbits.
2.      Structural classification the symmetry properties of graphs.
3.      Measurement the symmetry of graphs.
4.      Analyzing different situations of structural equivalency and graphs isomorphism.
5.      Positional structures that open the “hidden sides” of graphs.
6.      Unknown sides of well-known graphs.
7.      Adjacent structures and reconstruction problem. It is connected with general solving the notorious Ulam’s Conjecture.
8.      Sequences of adjacent structures and their associations – the systems of graph structures.
9.      Probabilistic characteristics of graph’s systems.
10.    The relations of graph systems with classical attributes.
References
1.       Euler. L. Solutio problematis ad geometriam situs pertinentis. – Comment. Academiae Sci. I. Petropolitanae 8 (1736), 128-140.
2.       Mayer, J. Developments recents de la theorie des graphes. – Historia Mathematica 3 (1976) 55-62.
3.       Tevet, J.-T. Semiotic testing of the graphs: a constructive approach and development. S.E.R.R., Tallinn, 2001.
4.                     Hidden sides of the graphs. S.E.R.R. Talinn, 2010.
5.                     Semiotic modeling of the structure. ISBN 9781503367456, Amazon Books. 2014.
6.                     Süsteem. ISBN 9789949388844. S.E.R.R., Tallinn, 2016.
7.                     Systematizing of graphs with n nodes. ISBN 9789949812592. S.E.R.R., Tallinn, 2016.
8.                     What is a graph and how it to study. ISBN 9789949817559. S.E.R.R., Tallinn, 2017.
9.       Weisfeiler, B. On Construction and Identification of Graphs. Springer Lect. Notes Math., 558, 1976 (last issue 2006).
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It is easy to prove that (quote wikipedia):
If A is an adjacency matrix of the directed or undirected graph G, then the matrix An (i.e., the matrix product of n copies of A) has an interesting interpretation: the element (i, j) gives the number of (directed or undirected) walks of length n from vertex i to vertex j. If n is the smallest nonnegative integer, such that for some i, j, the element (i, j) of An is positive, then n is the distance between vertex i and vertex j.
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I want to build a kind of guess game. I do not know the right name but the concept of the game is: person-1(P-1) thinks a name(of anything) and person-2 will have to predict that name by asking as less questions as possible. For example:
p1: thinks something(Steve jobs)
p2: Are you talking about man?
p1: yes.
p2: Is he/she media guy?
p1: No
P2: is he tech personality?
p1: yes
p2: steve jobs.
p1: yes.
So p2 has to ask 4 questions. It could be even more as number of predictors are infinite. Now I want to model this scenario. My Goal is to reduce the number of question. Note that the number of predictors are limited. So situation is not that broad.
I can think of decision tree. But question is, how can I decide where to split so that length of the brunch will be small.
Any suggestion/reference will be appreciated.
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Maximize the entropy, the information gain
for every question.
Regards,
Joachim
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Assume we have a class of graphs. Now what does this sentence mean?
"each of the graphs in the class, monotonically should make no difference". 
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@Nazanin "A graph peoperty is monoton if every subgraph of a graph with property P, also has the property P"  is called "hereditary property".  
As for the original (part of a) sentence: if we join it to another domain of mathematics, it makes sense such as it is, despite imprecise wording: e.g. in a class of exponential functions with a basis a>1... 
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If there are k sets of vertices in a graph, with the condition that each vertex in a set should be connected to at least one vertex from each of the other sets, then what is the least number of complete sub-graphs $K_{k}$ in this graph?
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Here you have another counterexample, is this what you mean? 
I don't understand your question about being $\chi$-colorable. Usually, $\chi(G)$ stands for the chromatic number of G... In the case of the graph I sent, it's 2-colorable.
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A NSWE-path is  a path consisting of North, South, East and West steps of length 1 in the plane. Define a weight w for the paths by  w(N)=w(E)=1 and w(S)=w(W)=t. Define the height of a path as the y-coordinate of the endpoint. For example the path NEENWSSSEENN has length 12, height 1 and its weight is t^4.
Let B(n,k) be the weight of all non-negative NSEW-paths of length n (i.e. those which never cross the x-axis) with endpoint on height k.
With generating functions it can be shown that for each n the identity
(*)            B(n,0)+(1+t)B(n,1)+…+(1+t+…+t^n)B(n,n)=(2+2t)^n
holds. The right-hand side is the weight of all paths of length n.
Is there a combinatorial proof of this identity?
For example B(2,0)=1+3t+t^2 because the non-negative paths of length 2 with height 0 are EE with weight 1, EW+WE+NS with weight 3t, and WW with weight t^2.
B(2,1)=2+2t because the non-negative paths are NE+EN with weight 2 and NW+WN with weight 2t. And  B(2,2)=1 because w(NN)=1.
In this case we get the identity
B(2,0)+(1+t)B(2,1)+(1+t+t^2)B(2,2)=(2+2t)^2.
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In the meantime I have found a combinatorial proof in the literature: Naiomi T. Cameron and Asamoah Nkwanta, On some (pseudo) involutions in the Riordan group,  J. Integer Sequences   8 (2005), Article 05.3.7, proof of identity 1. https://www.researchgate.net/profile/Asamoah_Nkwanta/publications?sorting=newest
Instead of NSWE-paths they use bicolored Motzkin paths, but their proof can easily be translated to the situation of NSWE-paths. So my question has been answered.
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Let $n\ge 4$ and $W=\{w_1,w_2,\cdots,w_{n-1}\}$ be a given sequence of positive numbers. Suppose that $w_i$ corresponds the weight of the edge $e_i$ of the weighted path $P_n$ for $i=1,2,\ldots, n-1$. Let also $M_i$ be an $i$-matching of $P_n$.
Denote by $W(M_i)$ the weight of such an matching, {\it i.e.,} the product of all weights of such an $i$-matching, and by $WM(i)$ the sum of all weights of $i$-matchings of $P_n$.
{\bf Question:} Who know the applications, including combinatorics and physics, of the
parameter $WM(i)$?
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Read 《Integer Flows and Cycle Covers of Graphs》 and 《Circuit Double Covers of Graphs》, the author is Prof. Cunquan Zhang. Another field is circular flow theory, you may read Prof. Genghua Fan's papers.  Hope it is useful.
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Can someone suggest me a good software for drawing graphs? The suggested software should be one which can be used to draw the attached graph (together with mathematical symbols) .
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Thanks everyone for your kind suggestions. I tried most of the suggested softwares and found ipe the best one. Special thanks to Seyyed Aliasghar Hosseini,  Imran Khaliq and Darren Strash. 
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Or generally:
\sum _{i=1}^n \sum _{j=1}^i \left\lfloor \frac{-j+n+1}{2 i}\right\rfloor
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I'm assuming from your question that you're looking for a closed form solution.
Let q = Floor[n/2i] and r = n - q*2i (quotient and remainder when n is divided by 2i). Therefore, 0 <= r < 2i.  Since i <= n,
     sum_{j=1}^i Floor[(n-j+1)/2i] = iq - d,
where d=0 if i-1 <= r < 2i, and d=i-1-r if 0 <= r < i-1.
This gives a closed form for the inner summation.  Obtaining a closed form over both summations looks like a harder problem, but maybe possible.
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what are the classes of posets closed under taking ordinal sum of posets?
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Let X and Y be two posets on the disjoint sets P and Q. The  disjoint union P+Q is defined as:
(1)if (x 'less than, or equal to' y) is in P, for x and y in P, then x <=  y in P+Q and
(2)if  (x 'less than, or equal to' y) is in Q, for x and y in Q, then x <= y in P+Q. 
The ordinal sum P*Q is defined as the partial order on P U Q, that satisfy (1) and (2), and the additional condition: (3) (x 'less than, or equal to' y) in P*Q for x in P, and y in Q.
The disjoint union + is commutative, but the ordinal sum '*' is not. 
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Since a uniform permutation has a probability of 1/n!, only distances of O(1/n^n) can be regarded as negligible. Section 2.2 of the attached paper gives a network with distance O(1/n^n) but the depth is O(n). Is there a permutation network with the same distance but an asymptotically smaller depth?
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Please attach the file because the link is not redirecting to appropriate web page of MIT.  
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Let the set of all repunits (repeated units) i.e., 1,11,111,... is X.
=> X = { Rn : n belongs to postive integer }
(Repunit of n defined by Rn. 1 is R!. 11 is R2, etc....)
Generally is not satisfy closed property.
  1. Under what condition or when X satisfy closed property?
  2. For which n, R2n+1 is prime?
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Yes dear Srinivasan, put the second "word" just next the first one. In French we call it juxtaposition, I think the terminology is the same in English .
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Let q be an odd positive integer, and let Nq denote the number of integers a such that 0 < a < q/4 and gcd(a, q) = 1. How do I see that Nq is odd if and only if q is of the form pk with k a positive integer and p a prime congruent to 5 or 7 modulo 8?
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I see that you, too, follow the Putnam Exam.
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Assuming we have a planar Graph G=(V,E). There is a function f(G) which returns a positive real number and we wish to assign either 0 or 1 to each node in order to minimize the function f(G). Trying all different combinations of assigning 0 or 1 to each node to find the combination which returns the minimum value of f(G) would be computational intractable. Hence, the question is whether there exists a algorithm to find (or approximate) the minimum for such a function.
Note that the function f has the properties that a solution exists and is unique. Further, it is known that the Graph that minimizes the function has 0 in the vast majority of nodes and the set where the nodes are 1 is connected. 
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Thilo,
One heuristic you might try, given that you have the "sum of squares of distances is small" phenomenon, is to start by looking at all vertices at distance <= k from a fixed vertex.  These sets of vertices, essentially closed balls, will often have small sums of squares of distances, I'd guess (I'm sure that there's an isoperimetric result out there of which I'm unaware...)   Then looking at local changes to these sets might enable you to find better --- and perhaps even optimal --- solutions.  At the very least they'd give you a good choice of upper bounds.
Neil
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Is there any provision to apply combinatorial analysis on image fusion?
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The exercise I'm dealing with asks me to show that by adding S = K to the usual reduction rules for the SKI-calculus, one obtains an inconsistent equivalence. This must be done without using Böhm's theorem.
Now, I've found two terms (not combinators) M and N with the following properties:
M = x
N = y
M can be obtained from N by replacing one or more occurrences of S with K
From the rule S = K we thereby get that M = N, and hence that x = y. Which means that any term can be proved equal to any other.
Do you think such an answer could work? Actually, Böhm's theorem (as shown in the book I am studying) establishes that, for distinct combinators G and H, there is a combinator D such that DxyG = x and DxyH=y. So, I feel it would have been more appropriate to find a combinator D such that Dx1x2S = x_i and Dx1x2K = x_j with i , j = 1 , 2 and i ≠ j. But I have HUGE problems in finding combinators, so I have only found terms respectively reducing to one of the variables, and obtainable one from another by replacing S with K or vice versa.
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Yeah I see now there's a much simpler solution. But I wondered if I had "well done" the exercise. Actually, it seems to me it works. I found two terms, M and N, the first one reducing to an arbitrary x and the second one to an arbitrary y. Moreover, M can be obtained from N by replacing an occurrence of S with K and therefore, as soon as one admits S = K as a rule, it follows that M = N. Since M = x and N = y, by transitivity one should get x = y for every x and y.
Actually, M and N, as I built them, contain other terms which are in the end not relevant to respective reducibility to x and y. But that's should not be a problem. It should be like to have two terms with variables (x, y, z, w), possibly with z = w, respectively reducing to x and y.
That's how I did the exercise...
PS: inconsistent in the sense that one can trivialize the equality relation.
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When a bipartite complete graph Km,n is given, two subgraphs of Km,n are in the same class when the degree of each right vertex coincides. I want to know the number of all spanning trees in a given class.   
Any spanning tree in Km,n has M+N-1 edges. A class whose right degrees do not sum up to M+N-1 does not contain any spanning tree. The number of classes with total degree M+N-1  is the repeated combination of country labels taken N -1 times. Thus the number take the form
                 (M + N - 2)! / (M - 1)! (N -1)! . 
From Scoins' formula the number of all spanning trees in Km,n is
                   MN-1NM-1 .
As a consequence, there are in general many spanning trees in a class in which the right degrees sum up to M+N-1.  I want to know an explicit formula that gives the number of all spanning trees for a given class with degree sum M + N -1.
This question is derived in the course of Ricardian trade theory study.  
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Dear Robert A. Beeler,
thank you for your comment. I am expecting to hear from you good news. 
Shiozawa
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We usually use differential equations, ordinary and partial, difference and delayed. But, could dynamics be captured using discrete mathematics structures, or combinatorics?
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If you look applications of tools provided by discrete mathematics in dynamical systems then this book can be good place to start:
Lind, Douglas; Marcus, Brian. An introduction to symbolic dynamics and coding. Cambridge University Press, Cambridge, 1995. xvi+495 pp. ISBN: 0-521-55124-2; 0-521-55900-6
It provides a very smooth introduction into symbolic dynamics from point of view of discrete structures (graphs, formal languages, Perron-Frobenius theory, etc.) and then reveal connections with topology, mixing, topological entropy, etc.
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I found this problem without comments in a french exercise book of 1982, now out of print : {\em 1932 exercices de mathématiques} by Luc Moisotte, ISBN 2-04-015483-3.
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 I send my proof as a file attachment.pdf . Please, answer me. Your sincerely, Anna Tomova. 
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In 1969 , David Barnette conjectured that 3 regular , 3-connected , bipartite , planar graph is Hamiltonian. . I am interested  to generate Barnette  graph for given  even number of vertices. There are countably finite number of Barnette graphs available in the literature.
Consider a grid graph with 4 vertices (cycle C 4) which is Hamiltonian. Increasing dimension in one direction , we see that the resulting graph is always Hamiltonian but not Barnette. Can one generate  countably infinite number of  Barnette graphs from one small Barnette graph?     
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It has been shown that fullerenes are hamiltonian [1] and they form an infinite family of cubic, 3-connected, planar graphs with faces of size at most 6. There is at least one fullerene on 2k vertices for each k greater than 11. Of course these are not bipartite since they contain pentagons, so I guess you are mainly interested in the other Barnette's conjecture. But, the thesis by Jan Goedgebeur also talks about this second conjecture and not the one about bipartite graphs.
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I am trying to calculate the most compact way of grouping a set of pixels together. Does anyone have a readable guide on how to do this?
My initial results are given below for clusters of up to 10 pixels. Results are expressed in terms of the sum of unique interpixel distances for a given cluster (e.g. for a 3 pixel cluster it is the sum of the the distances ab, ac, bc).
1 = 0
2 = 1
3 = 3.4
4 = 6.8
5 = 13.5
6 = 21.1
7 = 31.4
8 = 44.1
9 = 58.9
10 = 78.5
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I looked at the paper. So at least for L1 distances, we do not have uniqueness, the incremental approach partially fails (some optimal solutions do not extend to +1 optimal solutions, while some optimal solutions are not extension of -1 optimal solutions), and 4x4 square would yield L1 sum of 320, while the optimal result of 318 is displayed in the paper. Good luck.
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In \cite{Roman} page 25 we read that,  a sequence $s_n(x)$ is Sheffer for $(g(t), f(t))$, for some invertible $g(t)$, if and only if
$$ s_n(x+y)=\sum\limits_{k=0}^{\infty}\binom nk p_k(y) s_{n-k}(x),$$
for all $y$ in complex numbers,  where $p_n(x)$ is associated to $f(t)$. 
Noting to the fact that $e_q(x+y) \neq e_q(x)e_q(y)$, leads to conclude that $ s_{n,q}(x+y) \neq e_q(yt)s_{n,q}(x)$, and ,therefore, we do not have the $q$-analogue of the identity above directly. Is it possible to express the $q$-analogue of the above mentioned identity in any other way, or should we neglect such an identity for $q$-Sheffer sequences at all?
Any contribution is appreciated in advance. 
\bibitem{Roman}Roman S., Rota G. The umbral calculus. Advances Math. 1978;27:95–188.
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Dear Dr. Waldemar W Koczkodaj
Thanks for your response. I faced with this question, for the first time, while I was studying the sequence of $q$-Appell polynomials. Since that time, this question has been in my mind for a long time and so far I have not been able to make myself convinced by a perfect answer to it. The reason to ask this question here, actually, is to consult with the experts of this field and read about their different ideas which are originated, clearly, from different points of view. Although I am enthusiastic for learning more and more and go forward through the science, in case that I found a good answer which helps me to publish my studies, I make you sure that I will definitely obey the publication rules and humanity. 
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Some authorities like Davenport have already explained that traditional (Small?) data relates to corporate operations while Big data relates to corporate products and services.
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In these papers, I have argued that small data analysis based on Gaussian statistics, while BIG data based on power law statistics, and small data analysis based on Euclidean geometry, while BIG data based on fractal geometry.
Jiang B. (2015b), Geospatial analysis requires a different way of thinking: The problem of spatial heterogeneity, GeoJournal, 80(1), 1-13, Preprint: http://arxiv.org/ftp/arxiv/papers/1401/1401.5889.pdf
Jiang B. (2015a), Head/tail breaks for visualization of city structure and dynamics, Cities, 43, 69-77, Preprint: http://arxiv.org/ftp/arxiv/papers/1501/1501.03046.pdf
Jiang B. and Miao Y. (2014), The evolution of natural cities from the perspective of location-based social media, The Professional Geographer, xx(xx), xx-xx, DOI: 10.1080/00330124.2014.968886, Preprint: http://arxiv.org/abs/1401.6756
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Last year, Dr. Yitang Zhang has published a paper for the upper bound of twin primes, which is 7*10^7. Does anyone has idea to achieve lower bounded gap?
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Terence Tao and his collaborators did tons of work on this in Polymath 8 (mentioned ambiguously in the above comment). You can read part of what was done here:
Tao's complete corpus of work on that project is:
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In Maple 16,  how can we with the software combstruct,  to give the sentence about the recurrence formula,
A(x)=1+x[A(x)3+3A(x)A(x2)+2A(x3)]/6
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Very strange, first the gf then the object to count!
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It is well known that the majority rule may not be transitive for some configurations of individual preferences. Domain restrictions are possible ways out. But what is known about maximal such domains (i) with respect to the cardinality? (ii) via set inclusion?
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Thank you very much. I also like the job done on mutiple issues.
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I and another three colleagues have an ongoing paper about the application of sociometry to multiple human resource allocation to multiple projects. The problem is mathematically quite challenging but we are on a dead end concerning one of the outcomes we are dealing with.
Particularly, we have been applying meta-heuristics and evolutionary algorithms to solve the problem of allocating groups of people so as to maximize cohesion among them. The research is quite interesting and we think it is going to open multiple and very interesting research and industry application in the near future.
However, we are stuck in one part. We are trying to calculate the number of viable combinations of people who can work either full-time, part-time or not work at all in several simultaneous projects and we need a person with advanced knowledge in combinatorics to give us a hand. We are willing to pay or to put his/her name as co-author on the paper.
Getting straight to the point, the problem statement is as follows:
There are N people (i=1...N) who can be selected to work in P simultaneous projects (j=1...P). Each person can have a dedication of work full-time (1), half-time (0.5) or not work (0), that is, three possible allocations (0, 0.5, 1).
Now, we know that each project j requires Rj people. How many different and viable combinations are there?
Numerical Example:
People available  Project j=1     Project j=2      Project j=3=P
i=1                       0 or 0.5 or 1   0 or 0.5 or 1    0 or 0.5 or 1     Row sum =<1
i=2                       0 or 0.5 or 1   0 or 0.5 or 1    0 or 0.5 or 1     Row sum =<1
i=3                       0 or 0.5 or 1   0 or 0.5 or 1    0 or 0.5 or 1     Row sum =<1
i=4                       0 or 0.5 or 1   0 or 0.5 or 1    0 or 0.5 or 1     Row sum =<1
i=5                       0 or 0.5 or 1   0 or 0.5 or 1    0 or 0.5 or 1     Row sum =<1
Requirements      R_1=2            R_2=1             R_3=1              Row sum=4
,that is, we need 2+1+1 people working in these 3 projects and 1 out of the five available people is not used. We can use each person totally (1), half-time (0.5) or not use him/her, but the combinations must be feasible, i.e., each person cannot be assigned over 1 (full-time) and the requirements have to be fulfilled.
This problem is easier when the people can only work full-time or not work, but with half-times is far more complicated.
If anyone think that he/she is able to solve it, or just want further details, please  contact me.
Thanks
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Thanks Peter. We really appreciate the time you have spend solving this problem. Your contribution will be duly ackowledged as we agreed.
Thanks too for all you laborious explanations trying to make that someone like me understood the mathematical and combinatorics vision of this problem.
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Skew room squares exist for all odd values greater than 5. If n is prime it is a simple matter to generate a skew starter. But 667 is not prime. 667=23*29 which means a computer search has to be done in order to generate one. I would be satisfied with the skew room square of side 667, even though we can show it exists we can't seem to construct it. Any suggestions on this particular problem are appreciated.
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The reference provided 10 minutes ago may not be appropriate.
But, one may try some direct product construction as follows.
Start from skew starter S_1 in Z_{23} and skew starter S_2 in Z_{29}.
Find a permutation P=(p_0,p_1,...,p_{28}) such that
P-I = (p_0-0, p_1-1, ..., p_{28}-28)
And
P+I = (p_0+0, p_1+1, ..., p_{28}+28)
Are both permutations in Z_{29}. For example, take p_s=2s.
For each pair {x, y} in S_1, construct 29 pairs {(x,p_s), (y,s)}, s=0,1,…,28.
This generates 11x29 pairs.
Add 14 more pairs {(0,u),(0v)} such that {u,v} is from S_2.
It may be easy to verify if the 11x29+14 pairs form a skew starter in Z_{23}xZ_{29}.
If it still does not work, please let me know.
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Given a permutation A on the set [n], is there a way to determine the maximum number of disjoint cycles of AC where C ranges over all n-cycles on [n]? For which class of permutations A, this problem has been studied before?  Thanks
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Hamming distance between two permutations a and b is defined to be the minimum number of transpositions needed to bring a to b. If you express a^{-1} b as a one-line sequence, then Hamming distance is n - the number of fixed points. 
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I need a good reason why improper uniform prior could be use as a prior in Serial Numbered Population (SNP) problem. Or maybe someone can tell me about improper uniform prior itself. An pdf link might be very helpful for me.
I attached the journal.
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I'm not sure if Jochen's answer is entirely correct; "An improper prior can be used when the resulting posterior is proper."  I'd modify it to say that an improper prior can be used when the resulting posterior can be achieved with a *proper* prior and the limits of the distribution, after the posterior is calculated, is taken to infinity and the result is shown to be the same.  For example, you can use a proper, bounded uniform prior and then, after you calculate the posterior, take the limits as the bounds grow to infinity to show that if you used the improper prior in the first place it would give the same answer.
Seen this way, the improper prior is a short-cut to make the analysis cleaner.  For example, I personally find E T Jaynes' analyses very clear because he uses improper priors (when he can!), and warns that one has to be careful to do it properly if there is even a hint of trouble.  I find a paper like Bretthorst's "Difference of Means" paper to be a much harder read because he uses proper priors throughout, even in cases where I think the improper prior would work.
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Could anyone suggest me some references about the uniqueness of the addresses of an Iterated Function System? E.g. points of Cantor set can be coded by a unique address, how general is this property?
More precisely, I am interested in the sufficient conditions to have a one-to-one relation between the shift space of the Iterated Function Systems and  its attractor. 
Thank you in advance!
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Dear Anna,
There are three kinds of attractors of iterated function systems, totally disconnected, just touching and overlapping. Totally disconnected attractors have metrically equivalent structure to the Cantor set. This can be found in Barnley's book Fractals Everywhere. The remaining cases may be treated with the help of lifted IFS, which is also explained in the book. 
Best regards
Miroslav
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It is well known that the secant $\sec z$ may be expanded at $z=0$ into the power series
\begin{equation}\label{secant-Series}
\sec z=\sum_{n=0}^\infty(-1)^nE_{2n}\frac{z^{2n}}{(2n)!}
\end{equation}
for $|z|<\frac\pi2$, where $E_n$ for $n\ge0$ stand for the Euler numbers which are integers and may be defined by
\begin{equation}
\frac{2e^z}{e^{2z}+1}=\sum_{n=0}^\infty\frac{E_n}{n!}z^n =\sum_{n=0}^\infty E_{2n}\frac{z^{2n}}{(2n)!}, \quad |z|<\pi.
\end{equation}
What is the power series expansion at $0$ of the secant to the power of $3$? In other words, what are coefficients in the following power series?
\begin{equation}
\sec^3z=\sum_{n=0}^\infty A_{2n}\frac{z^{2n}}{(2n)!}, \quad |z|<\frac\pi2.
\end{equation}
It is clear that the secant to the third power $\sec^3z$ is even on the interval $\bigl(-\frac\pi2,\frac\pi2\bigr)$.
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Dear Dr. Feng,
Take a look at:
Ghislain R. Franssens, On a Number Pyramid Related to the Binomial, Deleham, Eulerian, MacMahon and Stirling number triangles, Journal of Integer Sequences, Vol. 9 (2006), Article 06.4.1
in particular section: 7.1 Multinomial Euler numbers
The results in section 7.1 are for powers of sech, so you'll need to substitute t -> it.
The above paper is freely available from the Journal's website, and also from my ResearchGate pages.
Best wishes,
Ghislain Franssens
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I would like to list out all simple cycles in a connected graph.
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You need to give additional details about your problem. If you know adjacency matrix of your graph and want to count number of simple cycles of fixed length look at slides and papers in my profile.
Sergey Perepechko
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What is the best software package available for carrying out computations related to algebraic coding theory, especially codes over rings.
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You could try Macaulay 2 which is freely available.
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Please help me with a derivation of "amortized cost of a splay tree operation" . I am waiting for that please consider it fast and let me know.
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If A and B Are non-singular then we have determinant of (A^2-B^2)=-determinant of AB , Am I correct? If so, then the problem is If A and B are singular, how can we prove?
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Given your assumptions, the case that either B or A is non-singular can not happen.
Starting from A^3=B^3 multiply by B from the right and insert A^2B=AB^2. This gives A^2B^2=B^4. If B would be non-singular, we can obtain A^2=B^2, which is excluded in the assumption. By symmetry, the same statement is valid for A.
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Would like to know if (6677,333,166) could be cyclical on the torus.
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The notation is ambiguous - what combinatorial object are these the parameters for? Is it some kind of design? If so, what kind, and what parameters are indicated? The problem is that there are hundreds of different parameterized combinatorial designs that use the same kind of notation
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I am asking for a combinatorial interpretation of a formula for Bell numbers in terms of Kummer confluent hypergeometric functions and Stirling numbers of the second kind. See the formula (8) and Theorem 1 in the attached PDF file or http://arxiv.org/abs/1402.2361. Could you please help me? Thank a lot.
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Yes, th formula (8) is not the only such formula. Some mathematician asked me to provide a combinatorial interpretation, but I do not know the combinatorial meanings of the formula (8). I think that "the formula (8) just represents one more expression for those numbers, using Kummer confluent hypergeometric function" may be not a combinatorial interpretation of the formula (8).
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Symmetric designs=combinatorial 2-designs with as many points as blocks.
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In the handbook of combinatorial designs by Jeff Dinitz and Charles Colbourne there is a table of symmetric designs. Is there a particular design or a particular type of symm design you are interested in? Symm bibd's are of great interest to me.
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There are many approaches using different matrices and eigenvectors to solve the min-cut problem. What is the best theoretical result providing a good approximation from a spectral cut to the solution?
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Indeed, the Hendrickson and Leland work were the most rescent advances using spectral tools that I have found.
Since you said in your survey that spectral techniques is still in use, I wonder if it worths to study spectral partitioning nowadays.
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I always thought that the sum of angular momentum should be zero. I am wondering if this applies on a sub-atomic scale as well as a macroscopic scale.
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spin geometry, spin representations etc are also commonly used in mathematics.
Here the term refers to the nontrivial representation of the spin group, the double covering group of the orthogonal group. i.e. they are projective representation of SO, or
spin representation of SO
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It can either be related to Key Distribution or any other application, just an overview needed.
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I can't recommend a book better than Combinatorial Designs by Douglas Stinson. It's how I learnt Design Theory. It is a little more expensive, but it is full of handy results.
Another good book is the Handbook of Combinatorial Designs. My previous supervisor and my current one wrote a pretty interesting bit in there on Lotto Designs.
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I'm writing my senior research paper on balanced tournament designs, and I am looking for the proof of the existence of them which is in this paper.
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Jennarose: Ron Mullin, Waterloo's first graduate student, proved the existence of room squares for all odd v greater than 5. The last one that needed proving was 257 which was constructed in the orient in the mid 70's. Further to this skew room squares exist for all odd v greater than 5. A skew room square is a room square where exactly one the cells (i,j) or (j,i) is occupied and the other cell is empty.
Don Giles is converting skew room squares of order 4n+3 into symmetric block designs with parameters (4n+3,2n+1,n) which in turn are being converted into Hadamard matrices of order (4n+4). All of these combinatorial structures are interrelated.
Paul Schellenberg developed the room square of order 25 as part of his PhD. He too was a student and then professor at Waterloo in the late 60's and early 70's
Addition and multiplication theorems were used after a collection of smaller room squares had been established by a host of researchers.
Hope this helps you with BALANCED TOURNAMENT DESIGNS>
I can elaborate more on their usage if you wish.
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My earlier expectation regarding the sufficiency of 4CT to adress this issue, is not correct.
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you might also be able to make a counting argument, since k_9 has 36 edges and any decomposition into two parts has at least 18 edges in one or the other part (so you might be able to prove a K_3,3 or K_5 must be in one part or the other)
none of this proves that the 4-color theorem cannot be used, but there are other possibilities
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A (discrete) n-circle is the set of complex n-th roots of unity, or: the vertices of a regular n-gon. The above question arose as part of a (nearly finished) research project on a method to produce unpredictable number sequences. Although my partial answers are no longer needed for the project, the simple-looking and still unsettled problem keeps intriguing me.
I proved that if a partition exists into pairs of distinct diameters, then n must be of type 8k or 8k+2 (k>0 integer). Computer generated examples confirm that for n <= 112, these types are *exactly* the sizes that work. The computer was stopped after running for two days on the case n=114 (having inspected nearly 0.000...001% (about 300 zeros) of the total search space). The only hope on further information must come from construction methods other than brute-force search with back-tracking and from proofs.
Specifically, the problem becomes this: Design an algorithm that is guaranteed to produce a partition (as desired) whenever there exists one and reports failure otherwise. Unlike the current backtracking brute-force search, the algorithm should provide answers in a reasonable time [Added 09-12-2013: solved]. The problem is certainly NP (Nondeterministic Polynomial), but chances are that it is NP-complete [ Added 09-12-2013: not NP complete].
A weaker problem is to find the largest number b <= n/2 such that *any* b vertex pairs with different diameters can be rotated apart in the n-circle for *any* (even) n. It might be "(n/2)-1", I haven't checked on this yet. Ultimately, one should be able to determine the best b for each individual n (including the odd case) [ Added 09-12-2013: this is still wide open. Exhaustive computer search is getting quite demanding, even for fairly low n ].
[ State of affairs 30-03-2015 ]  The maximal number of pairs (not necessarily with distinct diameters) that can be rotated apart in an n-gon has been determined (with some computer assistance) for n = 8--12, 14, 15, 18, 20, 21, 26.  Another problem that kept me busy lately is this: given n = t*m^2 with t, m >= 2, is it true that t+1 sets of size m can be rotated apart in the n-circle? For n=32 (case t=2, m=4) I already found a (rather elaborate) solution in 2012. Recently I found a promising new approach involving cyclotomic polynomials, providing a shorter proof for n=32 and , in fact, an elegant proof for all cases of type n = 2*m^2 (until recently, m needed to be prime).
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20 18 .. 2 19 2 ..18 20 9 17 15 13 11 7 5 3 19 9 3 5 7 1 1 11 13 15 17
is a generic pattern, 20=4k, 9=2k-1
21 18 .. 2 20 2 .. 18 11 21 19 .. 13 9 .. 3 20 11 3 .. 9 1 1 13 .. 19
is a generic pattern with 21=4k+1, 11=2k+1
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I am looking for a Heuristic Search to use in R for combinatorial optimization. I will need to choose a specified number of items from the set. For each combination I calculate a cost, which I want to minimize.
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At this current time I need to formalize some details before describing it in more detail. Thank you Stephen, Daniel and Gennady for taking the time to answer my question, however vague it was.
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Theta-combinator: \Theta \equiv (\lambda xy. y(xxy))(\lambda xy. y(xxy))
Y-combinator: Y \equiv (\lambda f. (\lambda x. f(xx))(\lambda x. f(xx)))
What's the difference between them? In what sense do you say Theta combinator is more powerful than the Y combinator?
In a reduction path, how can I distinguish beta-reduction and beta-equivalence of terms?
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@Peter: Did you check the references that I gave? They contain the actual beta-reduction steps for \Theta, and show how Y is different. I don't see a problem there.
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In constructing self dual symmetric balanced incomplete block designs with parameters (v,k,llamda)=(n^2+n+1,n+1,1) where p is a prime number is quite simple using my algorithm on a spreadsheet. However when n is a prime power such as 81 or 128 it's not so easy for me to do. When n is a prime I have developed an intriguing pattern that anyone can follow. I am still searching for patterns when n is a prime power. So if you could tell me how to get the multiplication table for say 2^3 and 3^2 I would be most grateful. Will be willing to share spreadsheet algorithms with you. By the way, after 3 years of intense personal research I have come up with a totally new class of combinatorial designs from which block codes can be generated from. Is anyone in Russia still interested in design theory especially balanced incomplete block designs? If so put me in contact with the person(s) if you have time to do so. Thanks so much.
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I have recently constructed a totally new class of combinatorial designs. Got green light 3 years ago from a world class mathematician in design and coding theory. Presently am engaged on the many sub-classes of these designs and am actually constructing these designs on a spreadsheet. The reason I mentioned the templates for the affine planes is that this same mathematician was flabbergasted at my algorithm. Also university of Alberta has adopted my templates for designs as well as Hadard matrix research. This is why I mentioned it. I guess this is a better mousetrap. However the class of brand new designs is important. Am trying to get NSA interested for a new
source of codes.
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What is the best way to find out whether a array is sorted or not?
I could do it with 2(n-1) comparisons. Any better idea to reduce the number of comparisons further?
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n-1, the minimum number of edges needed to make a connected graph (hence, tree) out of n nodes. Array a[1..n] is sorted if and only if for all i with 1 <= i < n we have a[i] <= a[i+1].
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A Hadamard matrix H(n) is an nxn matrix whose entries are restricted to the set {1,-1} and whose rows are pairwise orthogonal. H(n)s are conjectured to exist in orders n=1, 2 and 4k for all positive integers k (it is easy to show that they exist only in such orders). The rows of an H(n) may be permuted without destroying this property; similarly for the columns.
Some years ago I conjectured that every H(n) is equivalent (under row/column permutations) to one whose 2x2 blocks are rank 2 (that is, they are H(2)s). This has been verified up to and including order 28. It would be a big job to attempt to verify it directly for order 32 (there are over 13 million equivalence classes!).
What is desired is either a counterexample or an analytic proof of existence, rather than simply more cases verified empirically.
Aside: Originally I had also conjectured that there is always such a partition into rank 1 2x2 blocks. This was verified up to order 20 but failed in exactly one of the 60 classes of H(24) -- the Paley class (which some might find interesting ... ). There are 487 classes of H(28); a rank 1 partition exists in exactly 66 of these, but fails to exist in the remaining 421 classes.
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Hi Rob: There are several cases with llamda equal to three that we are interested in. They are (81,16,3) ,(115,19,3),(155,22,3),(20128,3). The existance of these designs along with several dozen others still remain in question. Various other small oines have llamda values (4,5,6,9,10,12,15). I would like to communicate via e-mail. My address is gilesdbg@msn.com . Then I could reveal my approaches to resolving some of these mysteries. Talk to you again Rob.
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An urn has N balls, each marked with an integer number from 1 to N. For each number in [1,N], there would be exactly one ball marked in the urn. If we randomly pick n balls with replacement from the urn, then we know that there would be N^n (N power n) possible ways of picking n balls. The question is, how many of such ways we’ll have at least one occurrence of c or more successive picks having consecutive increasing numbers?
Example:
For N=9 (range of numbering 1-9, also the number of balls in the urn is 9), n=7 (number of picks), and c=3(number of successive picks with consecutive increasing numbers)
Some of the sequences that are included for answer to this specific example:
i) 1,2,3,1,2,3,1 (2 occurrences of 3 consecutive numbers)
ii) 1,2,3,3,4,5,6 (1 occurrence of 3 consecutive numbers and 1 occurrence of 4 consecutive numbers)
iii) 8,9,9,9,4,5,6 (1 occurrence of 2 consecutive numbers and 1 occurrence of 3 consecutive numbers)
Some of the sequences that are NOT included for answer:
i) 1,2, 4,5, 7,8, 8 (3 occurrences of 2 consecutive numbers. We need at least one occurrence of c=3 or more consecutive numbers)
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There are (n+1-c) possible locations for a c-sequence, there are (N+1-c) different c-sequences and N^(n-c) possibilities for the other numbers. However, cases with c-sequences in two locations have been counted twice, so we have to subtract these. Then cases with c-sequences in three locations must be added etc. Inclusion/exclusion is the name of this procedure. The formula is long but simple and for your example it gives the answer 210969.
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The graph is a weighted undirected connected 3-regular graph. The number of nodes is N.
For each node there is one loop with weight $= \frac{1}{N}, and two other edges which goes from the node to its two ``nearest neighburs with weight $= \frac{\epsilon}{N}, where \^epsilon is a small parameter.
Therefore, we would like to know for a given value of $N$ how many different paths of lenght $2T$ are possible to go from one node to another passing through $k$ edges with weight $= \frac{\epsilon}{N}$ ?
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its very easy using Maple to find such a solution. I would think there are only two cases between nodes x and y. Either x=y or x \neq y. The transition matrix is tridiagonal. I think its easy to doagonalize using orthogonal polys.
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I usually face with MIP problems. I want to know what software is better in what aspect (such as solution time, used node etc.) in MIP, CPLEX solver in GAMS or IBM ILOG CPLEX?
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As far as I know, the solver (cplex) is the same in both suites. The main difference, to me, are the modelling tools around the solver in these suites. GAMS uses an AMPL-like modeling language and cplex is one the the solvers it can use. OPL studio or concert technology (IBM ILOG) use cplex (linear/integer/mixed interger programming) or cp (constraints programming). Both cplex and cp belong to IBM. I think the choice should mostly depend on how familiar you are with one of those suites.
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I always am curious of what types of combinatorial or mathematical objects (in general) interest other researchers. For myself I have a pretty keen interest in types of restricted weak integer compositions (weak implies 0 is applied in integer sequence whereas the lack of this description means you can't use 0 in integer sequences, and restricted means finding subsets of these objects).
What combinatorial or mathematical object (preferably more elusive ones) fascinate you the most, or are your favourite
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Well, I'd say finite permutation groups. Their definition is simple, their properties are fantastic, there are many fascinating conjectures and theorems about them, in spite of their rudimentary "building blocks".
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I am interested in proving that the incidence matrix M for any symmetric balanced incomplete block design can be written in a manner where M equals M transpose. If so then the incidence matrix will also be symmetric.
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BIBDs with the first list of parameters and a symmetric incidence matrix are well known. They come from the so-called Sylvester-Hadamard matrices given in Sylvester's 1867 paper. If you're using a "2n+1" construction then you're being too complicated. It's a very simple application of block doubling.
The second follows from the H(12) constructed by Hadamard in 1893 plus the same doubling construction. The others you list follow from known symmetric Hadamard matrices in the same way. These are known for many small orders. I'm not sure at which point we do not have a symmetric one, but the first currently unresolved order of Hadamard matrices is 668. So ... find one of these designs of order 667 and you will be famous. Good luck :-)
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The square root of a 31 by 31 matrix with 6"s down the main diagonal and 1"s elsewhere is a symmetric binary matrix with six 1's in each row and column. If someone has an algorithm for this square root then perhaps they can apply it to a larger matix that Iam presently working on. This larger matrix is an 81 by 81 matrix with 16's down the main diagonal and 3's eveywhere else. The square root of this will be a binary symmetric martix with sixteen 1's in each row and column. For me this is not a simple problem. My knowledge of matrices does not extend to taking square roots of symmetric matrices and getting symmetric binary matrices as the answer.
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Donald, you're asking for a general solution to the problem of producing a certain special class of SBIBDs. The answer is, in general, unknown, and it's a hard problem. See the CRC Handbook of Combinatorial Designs. Some infinite subclasses are well-known, solved many decades ago.
The way you and others here are describing the problem it sounds as if you believe there is a unique solution in general. There is not. For example, you can expect on the order of n! permutation-equivalent solutions to a problem of this type with nxn matrices. How many inequivalent ones? Again this is hard -- much harder even than the problem of finding one in the first place. The equivalence problem is likely to remain unsolved for good unless some completely new tools are developed.
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Problem. Lets consider a binary tree T. Every node of this tree is colored by blue or red. Every leaf of this tree is colored by red. We say that node is good if it is a leaf or node is red and children are good. Node is maximal good if node is good and it's parent isn't. The tree contains at least one blue node.
There are no two maximal good nodes connected by red path. Prove that number of maximal good nodes with blue parent is greater than number of maximal good nodes with red.
I know two proofs of this fact. But I don't like both. I still think there is an elegant proof.
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ok, so if I got it right a maximal good node with red parent has either:
1 - a blue 'brother', in this case prove that there are at least 2 maximal good nodes with blue parent descending from the brother
2 - a red 'brother' which is non-good, in this case one descendant (of the brother) must be blue and you can refer to the previous proof for at least 2 maximal good nodes with blue parent
Lastly the red path constraint should be enough to prove that the blue nodes named in 1 and 2 can not be 'shared' among maximal good nodes with red parent, so that at least one of the the 2 maximal good descending nodes with blue parent can't be 'shared'. You conclude that the maximal good nodes with blue parent are at least equal to the maximal good nodes with red parent + 1.
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Hi Everyone,
I am wondering if there is anyone out there who is still studying greedoids, besides myself that is. Let me know.
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I would agree. I personally am researching the characteristic polynomial for multiply rooted undirected and directed branching greedoids.
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I want to characterize the class 3 and class 4 graphs. By class 3 I mean ch no.(G(Z,D))= 3 where D is a subset of the set of primes P. By class 4 I mean ch no.(G(Z,D))= 4 where D is a subset of the set of primes P and the cardinality of D is greater than or equal to 4. Any body working in this type of problems can contact me.
Dr V.yegnanarayanan
senior Professor, Mathematics
Velammal Engineering College
Chennai-600066, TN, India.
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Respected Dr. V. Yegnanaranayanan, I have taught Graph Theory at Engineering and Computer science and Graph theory is one of my favorite topic. Could I be involved in your research project?
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Consider the two frames
(u1, v1, O1) and (u2, v2, O2)
where
u1 = <1, 0> v1 = <1, 1> O1( origin of this frame) = (0, 0)
u2 = <1, 0> v2 = <0, 2> O2 = (2, 2)
Suppose we have the point P, with coordinates (3, 2) in the frame (u1, v1, O1). What are the coordinates of the point in the frame (u2, v2, O2)?
Need how to calculate using Cramer's Rule?
Cramer's Rule
Given any frame (u, v, w, O), and a vector t, we know that t = u u +
v v + w w for some u, v and w. Utilizing Cramer's Rule, we can
calculate these coordinates directly by the following process: If we
define
D = u · (v × w)
D1 = t · (v × w)
D2 = u · ( t × w)
D3 = u · (v × t)
then
u = D1/D ?
v = D2/D ?
w = D3/D?
The solution should be (3,0)
But how using Cramer's Rule?
Thanks
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I appreciate for commenting.
If I assume that the given two frames are in 3D and the given point is(3,2,0) int he first frame then the vector t will be 3u+2V+0W (→OP).Then is there a way to find the point relating to the second frame? If the quoted cramer's rule cannot be employed to this problem, is there any other formulation of cramer's rule to employ this problem?
Thank you.
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stephan's unprovable statement is another is equivalent to russell's paradox in such that one proves it by disproving it or disprove it by proving it.Quantum Logics sounds so fascinating
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i meant to say stephan's statement is equivalent to russell's paradox
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dear friends. Presently I am doing research in automata theory. What is the latest research going on automata theory. friends, I am now in confusion. how to start and how it grow because I am basically mathematician. I want to know more ideas. also Is there any relavant materials available net. actually I started with buchi automaton in automata theory. but I do not know proceed that I have seen many materials. please help me & suggest me good ideas.
thanks & regards
O.V.SHANMUGA SUNDARAM
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You might want to look up Cellular Automata as one topic area.