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Value of the golden ratio (number Φ) knowing the side length of a square

Authors:
  • Université de la Sorbonne Nouvelle Paris 3 & EHESS & CAMS-CNRS
  • Universitat Autònoma de Bsrcelona - UAB
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Abstract and Figures

This paper explains how to obtain the number Φ, using a square with side length equal to a, the right triangle with sides a/2 and a, and a circle with radius equal to the hypotenuse of this right triangle. In particular, from a square whose side length is equal to a, we will show how to obtain a segment b in such a way that the value of a/b is the number Φ. It is well known that this ratio is also calculated from equating the ratios obtained by dividing a segment of length a + b by a (being a always the largest segment) and a by b, that is, (a + b)/a = a/b. This equality is a consequence of the ratio of proportionality in triangles applying Thales's Theorem. And, we must mention also how this golden ratio it is obtained as a consequence of the Fibonacci sequence. However, the golden ratio as a consequence of the limit of Fibonacci sequence was found later than many masterpieces, as for instance the ones of Leonardo da Vinci. This is the main reason because we analyzed how to find the proportionality golden ratio using the most common geometric figures and its symmetries. This paper aims to show how the golden ratio can be obtained knowing the side length a of a square.
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Value of the golden ratio (number Φ) knowing the the side
length of a square
Christophe Jouis1, Mercedes Or´us–Lacort2
1Centre d’Analyse et de Math´ematique Sociales – CAMS, 2Online teacher
of College Mathematics UOC–UNED
July 24, 2021
Abstract
This paper explains how to obtain the number Φ, using a square with side length equal to
a, the right triangle with sides a
2and a, and a circle with radius equal to the hypotenuse of this
right triangle. In particular, from a square whose side length is equal to a, we will show how
to obtain a segment bin such a way that the value of a
bis the number Φ. It is well known that
this ratio is also calculated from equating the ratios obtained by dividing a segment of length
a+bby a(being aalways the largest segment) and aby b, that is, a+b
a=a
b. This equality
is a consequence of the ratio of proportionality in triangles applying Thales’s Theorem. And,
we must mention also how this golden ratio it is obtained as a consequence of the Fibonacci
sequence. However, the golden ratio as a consequence of the limit of Fibonacci sequence was
found later than many masterpieces, as for instance the ones of Leonardo da Vinci. This is
the main reason because we analyzed how to find the proportionality golden ratio using the
most common geometric figures and its symmetries. This paper aims to show how the golden
ratio can be obtained knowing the side length aof a square.
Key Words: Number Φ, Golden ratio, Fibonacci.
1 Introduction
The Φ number, the golden ratio, has always been and is a number that has amazed and surprised
us.
Transcendent number, we usually call it. He and someone else received that name because they
simply have characteristics that make them different from others.
This number leaves us thoughtful. It seems that the beauty of the most harmonic forms resides
in it, and it makes us wonder: how can this happen?.
Many times, as a mathematicians, we have felt a very small human being when we observe
certain results, because they seem to be not by chance, but the work of someone whose conjunction
between mind and soul is supreme, divine.
It is well known that this ratio is also calculated from equating the ratios obtained by dividing a
segment of length a+bby a(being aalways the largest segment) and aby b, that is, a+b
a=a
b. This
1
equality is a consequence of the ratio of proportionality in triangles applying Thales’s Theorem,
see Fig.(1).
Figure 1: Right triangle where a+b
a=a
b.
And, we must also mention how this golden ratio it is obtained as a consequence of the Fibonacci
sequence. This sequence, which terms are {1, 1, 2, 3, 5, 8, 13, 21, 34,.. .}has numerous applications
in computer science, mathematics, game theory, in topological quantum computing with a system
of Fibonacci anyons described by the Yang–Lee model the SU(2) special case of the Chern-Simons
theory and Wess-Zumino-Witten models [25], as well as in Linguistics in the syntactic derivation
of sentence structures [26]. It also appears in biological configurations, such as in the branches of
trees, in the arrangement of leaves on the stem, in the flowers of artichokes and sunflowers, in the
inflorescences of Romanesco broccoli, in the configuration of coniferous conifers, in the reproduction
of rabbits and in how DNA encodes the growth of complex organic forms. And allow us to draw a
spiral using squares with side length equal to each term of the sequence, as it shows Fig. (2). The
growth ratio is Φ, that is, the golden ratio.
Figure 2: Fibonacci spiral.
This Fibonacci spiral, it is found in the spiral structure of the shell of some mollusks, such as
the nautilus as it shows Fig. (3), and also in Leonardo da Vinci’s masterpieces, as for instance it
is shown in Fig. (4).
2
Figure 3: Nautilus and Fibonacci spiral.
Figure 4: Mona Lisa and Fibonacci spiral.
Mathematicians like Edouard Lucas [24] and Kepler studied this sequence, and the Scottish
mathematician Robert Simson found in 1753 (later than Leonardo da Vinci’s masterpieces) that
the relationship between two successive Fibonacci numbers approaches the golden ratio Φ when n
tends to infinity.
3
And like them, many others worked and wrote about it [1] to [24].
In our case, one day observing Leonardo da Vinci’s masterpieces, we wondered how it was
possible that the Fibonacci spiral and consequently the number phi were present in his masterpieces,
if Fibonacci was born centuries later than Leonardo da Vinci.
The Vetruvian Man caught our attention too. Analyzing this masterpiece, anyone can observe
that he was using squares and circles circumscribing a human body to obtain certain body
proportions.
It was at that moment when we begin to build the idea shown in this paper, playing with the
most basic geometric figures and concepts.
This paper only aims to show how we can obtain the Φ number using the most basic geometric
shapes: a square, a right triangle and a circle.
In particular, from a square whose side length is equal to a, we will show how to obtain a
segment bin such a way that the value of a
bis the number Φ.
The paper is organized as follows: in Sec.2 we explain how we can obtain Φ using these basic
geometric figures and concepts and in Sec.3 we wrap up our conclusions.
2 How to obtain Φnumber
First, as it shows the Fig. (5), we draw a square with side length equal to a.
Figure 5: Square with side length equal to a.
Next, we divide this square in two equal rectangles, see Fig. (6), and we draw the rectangle
diagonal OC (hypotenuse hof the right triangle OCD ) as it shows Fig. (7).
4
Figure 6: Square divided in two equal rectangles.
Figure 7: Right triangle with sides a
2and aand hypotenuse h.
Now, considering the point Oas the center and the diagonal OC as the radius, we draw a circle
as it shows Fig. (8), and we call bto the distance between Dand F.
Figure 8: Circle with center Oand radius OC .
Note that the distance OF is the radius OC , that is, the hypotenuse of the right triangle OC D,
5
and at the same time it is equal to a
2+b.
The number Φ is the proportion between aand b, that is, a
b.
Hence, to obtain a
bvalue, we calculate it as follows.
From the right triangle OC D, the radius O C, that is, the hypotenuse is equal to:
OC =r(a
2)2+a2=a5
2(1)
And since OC =OF , we have:
a5
2=a
2+b
a5
2a
2=b
a(5
21
2) = b
a
b=2
51=2(5 + 1)
(51)(5 + 1) =2(5 + 1)
4
a
b=5+1
2
(2)
Therefore, the golden ratio a
balso known as the number Φ is equal to:
Φ = a
b=1 + 5
2(3)
3 Conclusions
In this paper we have shown how to calculate two segments aand b, so that a
bis the number Φ.
In particular, we have shown how from a square whose side measures a, this length being
arbitrary, the appropriate segment of length bis the one that allows us to build a circle of radius
a
2+b, centered on the base of the square at point a
2, and so that the semicircle of this circle
circumscribes the upper part of the square, as it is shown in Fig. (9).
6
Figure 9: Circle with radius O C =OF and segment b=DF .
Acknowledgements: we acknowledge to all scientists, mathematicians and physicists, for a
critical reading and proposing the dissemination of this result.
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8
... Hence, fractality plus a variational principle (i.e. the search for equilibrium) are a sufficient condition to imply the golden rule. Figure afterJouis and Orús-Lacort (2021).Interpretation according toGregori et al. (2022). ...
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And the same applies in architecture, to the rectangles representing these and other ratios (e.g. the 'golden cut'). The sole value of these ratios is that they are intellectually fruitful and suggest the rhythms of modular design
  • Summerson John
Summerson John, Heavenly Mansions: And Other Essays on Architecture (New York: W.W. Norton, 1963) p. 37. "And the same applies in architecture, to the rectangles representing these and other ratios (e.g. the 'golden cut'). The sole value of these ratios is that they are intellectually fruitful and suggest the rhythms of modular design."
Dynamic Symmetry: The Greek Vase
  • Jay Hambidge
Jay Hambidge, Dynamic Symmetry: The Greek Vase, New Haven CT: Yale University Press, 1920.
Universal Principles of Design: A Cross-Disciplinary Reference
  • William Lidwell
  • Kritina Holden
  • Jill Butler
William Lidwell, Kritina Holden, Jill Butler, Universal Principles of Design: A Cross-Disciplinary Reference, Gloucester MA: Rockport Publishers, 2003.
De divina proportione, Luca Paganinem de Paganinus de Brescia (Antonio Capella) 1509
  • Luca Pacioli
Pacioli, Luca. De divina proportione, Luca Paganinem de Paganinus de Brescia (Antonio Capella) 1509, Venice.
Me, Myself, and Math: Proportion Control
  • Steven Strogatz
Strogatz, Steven (September 24, 2012). "Me, Myself, and Math: Proportion Control". The New York Times.
Golden Ratio Conjugate
  • Eric W Weisstein
Weisstein, Eric W. "Golden Ratio Conjugate". MathWorld.