... If 11 ̸ = 0, 1 = 0, 2 ̸ = 8 , 2 ̸ = 0, 3 = 0, and 8 = 0, selecting 1 = 3 0 / 2 , the nullity of 2 9 + 4 is invariant. If 4 ̸ = − 2 9 , selecting 2 0 = 2 ( 2 9 + 4 )/ 2 2 ̸ = 0, the subfamily is 10 (0, 1, 0, 1, 0, 0, 0, 0); else with 1 = 3 0 / 2 the subfamily is 11 (0, 1, 0, 0, 0, 0, 0, 0). If 11 ̸ = 0, 1 = 0, 2 ̸ = 8 , 2 = 0, and 3 ̸ = 0, selecting 1 = 4 0 / 3 ̸ = 0, 0 = 3 / 8 ̸ = 0, and 1 = − 3 ( 4 − 9 8 )/ 3 8 , the subfamily is 12 (0, 0, 1, 0, 0, 0, 1, 0). ...