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Pi

3.14460551... does not Square circle

[16/Π]^2 -[Π]^2

[16/Π]^2 -[Π]^2- 1{}{}

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PANAGIOTIS STEFANIDES FOR

[16/Π]^2 -[Π]^2- 16=0

FOR THIS VALUE OF Π :

Π =3.14460551..

FOR THE VALUE OF DIAMETER

CIRCUMFERENCE = 16 = A SQU

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Pi value 3.14460551…. Satisfies Quadrature

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[16/Π]^2 -[Π]^2- 16=0 PANAGIOTIS STEFANIDES [FOR WolframAlfa]

http://www.wolframalpha.com/input/?i=%5B16%2F%CE%A0%5D%5E2+-%5B

%CE%A0%5D%5E2-+16%3D0

FOR THIS VALUE OF Π :

Π =3.14460551..

FOR THE VALUE OF DIAMETER = [16/ Π ] = 5.0880786..

CIRCUMFERENCE = 16 = A SQUARE WITH SIDE [4]=QUARTER CIRCLE.

THIS QUARTER SIDE [4] MULTIPLIED BY THE DIAMETER [16/ Π ]

EQUALS [4]*[16/Π] = [ 64/ 3.14460551..] = 20.3523144..

ROOT OF THIS IS A SQUARE OF SIDE 4.511353943..

AREA OF CIRCLE OF DIAMETER [16/Π] = [Π/4]*[16/Π]^2 =

= [ 0.786151378..]*[5.0880786..]^2 = [ 0.786151378..]*[25.88854384] =

= 20.35231441..

THIS AREA OF CIRCLE IS EQUAL TO THE SQUARE OF SIDE 4.511353943..

REF: http://www.stefanides.gr/Html/QuadCirc.htm

http://www.stefanides.gr/Html/theo_circle.htm

© Copyright 1999 - 2002 P. C. Stefanides.

PANAGIOTIS STEFANIDES FORMULA:

[16/Π]^2 -[Π]^2- 16=0

FOR THIS VALUE OF Π :

Π =3.14460551..

FOR THE VALUE OF DIAMETER = [16/ Π ] = 5.0880786..

CIRCUMFERENCE = 16 = A SQUARE WITH SIDE [4]=QUARTER CIRCLE.

THIS QUARTER SIDE [4] MULTIPLIED BY THE DIAMETER [16/ Π ]

EQUALS [4]*[16/Π] = [ 64/ 3.14460551..] = 20.3523144..

ROOT OF THIS IS A SQUARE OF SIDE 4.511353943..

AREA OF CIRCLE OF DIAMETER [16/Π] = [Π/4]*[16/Π]^2 =

= [ 0.786151378..]*[5.0880786..]^2 = [ 0.786151378..]*[25.88854384] =

= 20.35231441..

THIS AREA OF CIRCLE IS EQUAL TO THE SQUARE OF SIDE 4.511353943..

REF: http://www.stefanides.gr/Html/QuadCirc.htm

http://www.stefanides.gr/Html/theo_circle.htm

© Copyright 1999 - 2002 P. C. Stefanides.

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