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CURRENT Pi DOES NOT SATISFY QUADRATURE

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Pi
3.14460551... does not Square circle
[16/Π]^2 -[Π]^2
[16/Π]^2 -[Π]^2- 1{}{}
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PANAGIOTIS STEFANIDES FOR
[16/Π]^2 -[Π]^2- 16=0
FOR THIS VALUE OF Π :
Π =3.14460551..
FOR THE VALUE OF DIAMETER
CIRCUMFERENCE = 16 = A SQU
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Pi value 3.14460551…. Satisfies Quadrature
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[16/Π]^2 -[Π]^2- 16=0 PANAGIOTIS STEFANIDES [FOR WolframAlfa]
http://www.wolframalpha.com/input/?i=%5B16%2F%CE%A0%5D%5E2+-%5B
%CE%A0%5D%5E2-+16%3D0
FOR THIS VALUE OF Π :
Π =3.14460551..
FOR THE VALUE OF DIAMETER = [16/ Π ] = 5.0880786..
CIRCUMFERENCE = 16 = A SQUARE WITH SIDE [4]=QUARTER CIRCLE.
THIS QUARTER SIDE [4] MULTIPLIED BY THE DIAMETER [16/ Π ]
EQUALS [4]*[16/Π] = [ 64/ 3.14460551..] = 20.3523144..
ROOT OF THIS IS A SQUARE OF SIDE 4.511353943..
AREA OF CIRCLE OF DIAMETER [16/Π] = [Π/4]*[16/Π]^2 =
= [ 0.786151378..]*[5.0880786..]^2 = [ 0.786151378..]*[25.88854384] =
= 20.35231441..
THIS AREA OF CIRCLE IS EQUAL TO THE SQUARE OF SIDE 4.511353943..
REF: http://www.stefanides.gr/Html/QuadCirc.htm
http://www.stefanides.gr/Html/theo_circle.htm
© Copyright 1999 - 2002 P. C. Stefanides.
PANAGIOTIS STEFANIDES FORMULA:
[16/Π]^2 -[Π]^2- 16=0
FOR THIS VALUE OF Π :
Π =3.14460551..
FOR THE VALUE OF DIAMETER = [16/ Π ] = 5.0880786..
CIRCUMFERENCE = 16 = A SQUARE WITH SIDE [4]=QUARTER CIRCLE.
THIS QUARTER SIDE [4] MULTIPLIED BY THE DIAMETER [16/ Π ]
EQUALS [4]*[16/Π] = [ 64/ 3.14460551..] = 20.3523144..
ROOT OF THIS IS A SQUARE OF SIDE 4.511353943..
AREA OF CIRCLE OF DIAMETER [16/Π] = [Π/4]*[16/Π]^2 =
= [ 0.786151378..]*[5.0880786..]^2 = [ 0.786151378..]*[25.88854384] =
= 20.35231441..
THIS AREA OF CIRCLE IS EQUAL TO THE SQUARE OF SIDE 4.511353943..
REF: http://www.stefanides.gr/Html/QuadCirc.htm
http://www.stefanides.gr/Html/theo_circle.htm
© Copyright 1999 - 2002 P. C. Stefanides.
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