# how we calculate of Sand, cement and aggregate of M20 ratio or other ratio?

Ex. 1:1.5:3 is the ration of M20 and now how much sand or cement or aggregate we use in this?

Ex. 1:1.5:3 is the ration of M20 and now how much sand or cement or aggregate we use in this?

## Popular Answers

Abhishek Kumar Singh· Larsen and ToubroDetailed analysis on M20 = 1:1.5:3 (Ratio)

As we know that during concreting when we place wet concrete , it gets harden after certain standard time( 30 mins IST & 10hrs FST), considering same it had be decided upon by Civil design Engineers to take a factor of safety ranging from 1.54 to 1.57 to counter that shrinkage.

i.e volume of dry Concrete = 1.54 to 1.57 times Volume of wet concrete.

Now calculations is as follows for 1cum(assumed) of Concrete work

ratio Sum = 1+1.5+3=5.5

Shrinkage or safety Factor =1.57 (you can take 1.54 also)

So Total volume of wet concrete required is :- 1.57cum

Volume of broken stone Require = (3/5.5) x 1.57 = 0.856 m3

Volume of sand Require = (1.5/5.5) x 1.57 = 0.471 m3

Volume of cement = (1/5.5) x 1.57 = 0.285 m3

= 0.285 x1440 = 411 kg

For 1m3 of M20 (1:1.5:3)

Broken stone = 0.856 m3

Sand = 0.472 m3

Cement = 8.22 bag.

Some important conclusion from above

8 bag of Cement is required for 1cum of concrete work in M20.

4.4 bag of cement is required for 1cum of concrete work in M10.

volume of dry concrete =1.54 times volume of wet concrete.

Thank You Folks!

## All Answers (17)

Usama Metwaly· Arab Academy for Science, Technology & Maritime TransportVolume = 1+1.5+3=5.5

Total volume ingredients for using =1.57

Volume of broken stone Require = (3/5.5) x 1.57 = 0.856 m3

Volume of sand Require = (1.5/5.5) x 1.57 = 0.471 m3

Volume of cement = (1/5.5) x 1.57 = 0.285 m3

= 0.285 x1440 = 411 kg

For 1m3 of M20 (1:1.5:3)

Broken stone = 0.856 m3

Sand = 0.472 m3

Cement = 8.22 bag

Dr Uttam Kalwane· D.Y.Patil College of Engineering and TechnologyTo calculate proportion of cement, sand, coarse agrregate and water, It required to do mix design & for this initially it is requird to find out the properties of all ingradients used for preparing concrete......

Amit Singh· KIIT UniversityNagendra Naik Bukke· Sree Vidyanikethan Engineering CollegeRespected sir i would like to ask one doubt i.e how the below value come .

Total volume ingredients for using =1.57

Apha Sathonsaowaphak· Nakhon Ratchasima Rajabhat UniversityDeb Dulal Tripura· National Institute of Technology, AgartalaIts good to see your queries.

M20 (1 cement :1.5 sand :3 stone/brick aggregate). To determine the proportions you have to perform mix design, for this you have to find out the sp.gr. of cement, CA, FA, and water cement ratio, type of exposure, Maximum size of aggregate etc. Once the W/C ratio is determined use 186 kg water (for 20mm CA) to find out the qty. of cement per cum of concrete. Then determine the qty. of FA and CA with the help of formula given in IS:10262-1982, and then divide all the ingredients by cement, then you will get the proportion similar to you mentioned which are in kg.Or you can follow IS:10262 -2009, where the calculations are easier.

Further queries do contact me.

Sanjeev KumarI appreciate your reply, but i doubt is coming. What is meaning of 1.57 and why we use this?

Sridhar Dulipeta· Indian Institute of Management BangalorePremith Satish· Shri Mata Vaishno Devi Universitybut, i think Mr. Usama Metwly has taken a rough value of 1.57 as total volume of ingredient.

that is if the Total volume ingredients is 1.57 then if you calculate u'll get Broken stone = 0.856 m3, Sand = 0.472 m3, Cement = 8.22 bag as answer.

instead if we assume or have: Total volume ingredients for using as 2.36 (varies), [this is when you know the overall amount of materials you have].

Volume of broken stone Require = (3/5.5) x 2.36 = 12.8 m3

Volume of sand Require = (1.5/5.5) x 2.36 = 0.64 m3

Volume of cement = (1/5.5) x 2.36 = 0.42 m3

= 0.42 x1440 = 604.8 kg

For 1m3 of M20 (1:1.5:3)

Broken stone = 1.28 m3

Sand = 0.64 m3

Cement = 12.09 bags (where 1 bag is 50 Kg)

Rafid Zainel· Bharati Vidyapeeth Deemed UniversityRafid Zainel· Bharati Vidyapeeth Deemed Universityfor 1 m3 or 1 kg or 1 ton ... Etc. Concrete 1:1.5:3

cement (1/5.5) m3 or kg, or ton...etc

sand (1.5/5.5) m3 or kg, or ton...etc

gravel (3/5.5) m3 or kg, or ton...etc

Jagadeesha Pai· Manipal UniversityBut presently, the ratio is decided after having detailed testing on the aggregates and cement. You can go through the reference of Ambuja Cement booklets on concrete

Velumani Pandi· Kalasalingam UniversityVolume of wet cement concret is 1.54 to 1.57

Abhishek Kumar Singh· Larsen and ToubroDetailed analysis on M20 = 1:1.5:3 (Ratio)

As we know that during concreting when we place wet concrete , it gets harden after certain standard time( 30 mins IST & 10hrs FST), considering same it had be decided upon by Civil design Engineers to take a factor of safety ranging from 1.54 to 1.57 to counter that shrinkage.

i.e volume of dry Concrete = 1.54 to 1.57 times Volume of wet concrete.

Now calculations is as follows for 1cum(assumed) of Concrete work

ratio Sum = 1+1.5+3=5.5

Shrinkage or safety Factor =1.57 (you can take 1.54 also)

So Total volume of wet concrete required is :- 1.57cum

Volume of broken stone Require = (3/5.5) x 1.57 = 0.856 m3

Volume of sand Require = (1.5/5.5) x 1.57 = 0.471 m3

Volume of cement = (1/5.5) x 1.57 = 0.285 m3

= 0.285 x1440 = 411 kg

For 1m3 of M20 (1:1.5:3)

Broken stone = 0.856 m3

Sand = 0.472 m3

Cement = 8.22 bag.

Some important conclusion from above

8 bag of Cement is required for 1cum of concrete work in M20.

4.4 bag of cement is required for 1cum of concrete work in M10.

volume of dry concrete =1.54 times volume of wet concrete.

Thank You Folks!

Arup Mallick· Tata Steel"Volume of cement = (1/5.5) x 1.57 = 0.285 m3

= 0.285 x1440 = 411 kg"

Why 1440 is multiplied?

Vazeer Mahammood· Andhra UniversitySpecific weight of cement

Can you help by adding an answer?