Minimum mass bound in AdS space suggests that sufficiently small perturbations will NOT lead to black hole formation in AdS space?

The 'standard model' of theoretical physics says the basic forces are transmitted between bodies and detectors by particles or fields, as speeds up to the velocity of light.  The LIGO gravitational signal is found to be of short duration (light crossing time of the emitter, perhaps) and very close to light speed. .Very likely to be waves on the gravitational field (Einstein) but could still be 'gravitons'. Black holes can't emit light waves, likewise they can't emit gravity waves and cannot exert gravitational force on matter outside.  So how do the proponents explain two black holes pulling on each other, orbiting in the gradually closing binary system?

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It was suggested many years ago by Jacob Bekenstein that the rotation parameter of a black hole should be quantized as in usual quantum mechanics: J=n * hbar.

The quantum field theoretic prediction for the vacuum energy density leads to a value for the effective cosmological constant that is incorrect by between 60 to 120 orders of magnitude. In a paper, George Ellis et al. (2010) review an old proposal of replacing Einstein's Field Equations by their trace-free part (the Trace-Free Einstein Equations), together with an independent assumption of energy--momentum conservation by matter fields. While this does not solve the fundamental issue of why the cosmological constant has the value that is observed cosmologically, it is indeed a viable theory that resolves the problem of the discrepancy between the vacuum energy density and the observed value of the cosmological constant. Therefore they confirm that no problems arise in such a scheme: hence, the Trace-Free Einstein Equations are indeed viable for cosmological and astrophysical applications. 

So what do you think? Can the Trace-Free Einstein Equations be a Viable Alternative to General Relativity? Your comments are welcome

I wish to know that in what scenario (with conditions), which order of perturbation will give more accurate results.

As electrons, protons and neutrons become degenerate......