24th Jun, 2020

University of Kabianga

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Question

Asked 23rd Jun, 2018

I have used Kruskal-Wallis test to determine whether there is a significant difference in awareness level of bacteria resistance, in Non-Normally distributed data, among physicians, pharmacists, and nurses?

@Liang Ma, it is possible to get a significant post hoc test even with a non SIG KW test, but it is meaningless. As a rule post hoc tests as the name implies means you only go for it after an omnibus test has shown a significant difference. Otherwise you don't.

The following is an example for reporting Kruskal-Wallis test:

Kruskal-Wallis Test was conducted to examine the differences on renal dysfunction according to the types of medication taken. No significant differences (Chi square = 3.71, p = .39, df = 6) were found among the five categories of participants (none, ACE inhibitors, ARB, ACE inhibitor and ARB, NSAID, and ACE inhibitor or ARB and NSAID).

18 Recommendations

The test is appropriate if the assumption of independent observation is met and the outcome is ordinal, which should be stated in the report. If SPSS is used then check the test statistics table result, to find the *p*-value associated with Asymptotic Significance row which indicate the p-value to be interpreted. If less than 0.05 there is statistically significant difference between the outcome of the 3 independent groups (nurses, physicians and pharmacists). On the other hand If the *p*-value is greater than 0.05, then the finding is not statistically significant. If the *p*-value is less than 0.05, then a Mann-Whitney U test or a Dunn for pairwise comparisons in a post hoc manner is indicated.

2 Recommendations

The following is an example for reporting Kruskal-Wallis test:

Kruskal-Wallis Test was conducted to examine the differences on renal dysfunction according to the types of medication taken. No significant differences (Chi square = 3.71, p = .39, df = 6) were found among the five categories of participants (none, ACE inhibitors, ARB, ACE inhibitor and ARB, NSAID, and ACE inhibitor or ARB and NSAID).

18 Recommendations

Dear Olaide Bamidele Edet,,

thank you for your response. actually, I have used bonferroni correction when P values were less than 0.05.

1 Recommendation

Dear Dr.Abdulsalam

Krukal Wallis test used for not normal continuous data to compare among more than two groups for you ( physicians, pharmacists and nurses), Now if the p>0.05, it means the three groups have no significant difference in "score" but if less than 0.05 we have significant difference among groups but to know this significant difference where you have to compare between:

Physician and pharmacists

Physician and nurses

pharmacists and nurses

Maybe you will find significant in more than one comparisons

Generally Mann Whitney U test used for pairwise comparison, in SPSS you can do both tests(Kruskal and Mann Whitney U) at once... I advice you to read more about bonferroni correction it is not always helpful..

Good luck

3 Recommendations

Thank you for this post, l categorically benefited from the points raised which l subscribe to as well.

1 Recommendation

I found this example elsewhere:

A Kruskal-Wallis H test showed that there was a statistically significant difference in pain score between the different drug treatments, χ2(2) = 8.520, p = 0.014, with a mean rank pain score of 35.33 for Drug A, 34.83 for Drug B and 21.35 for Drug C.

After that post hoc test is required

4 Recommendations

Tashi Dendup I think this example can be found on that website here: https://statistics.laerd.com/spss-tutorials/kruskal-wallis-h-test-using-spss-statistics.php

They explain a lot about the Kruskal-Wallis Test in general, so I thought it might be useful to post a link.

1 Recommendation

I have done a Kruskal-wallis test but my output doesn't seem to have chi-square, have I done something wrong along the way?

2 Recommendations

Jamie McNulty , the chi-square value is the **Kruskal-Wallis H **Value in the **Test statistics **table. I don't think you have done anything wrong, if you can identify the **Kruskal-Wallis H **Value.

The SPSS version 25 doesn't display a chi-square value

3 Recommendations

I should also that if significant differences were detected using a global test, which in this case is the Kruskal-Wallis test, you would want to conduct a posthoc test. You should apply the Conover test as posthoc test for pairwise multiple comparisons of the ranked data (i.e. use Conover test as posthoc if Kruskal-Wallis p-value < 0.05). I don't use SPSS, but in RStudio, the command line is very straightforward.

1 Recommendation

I got feedback from a journal peer reviewer recently stating the following - "Please use the Kruskal-Wallis H test statistic when reporting results of that test, i.e.,

H(3)=3.514, p=.319." My understanding was the test statistic was *χ2* (chi quared lovingly edited by researchgate). Who is correct?

1 Recommendation

Hi, Karl E. Bridges , May I know that the best way to report the Kruskal-Wallis H test is like H(3)=3.514, p=.319 ?

1 Recommendation

I never got an answer - this thread is very dated but I still persist with chi squared. My searches on the internet appear to recommend chi squared more so than H.

3 Recommendations

How to visualize the Kruskal-Wallis H test? ANy ideas for graph - seven groups were pairwise tested?

3 Recommendations

Olga Gyarfasova perhaps as a heatmap similar to a correlation matrix? If you are working in R there are a few suitable plotting techniques in various packages, e.g. ggplot2 and plonly.

1 Recommendation

@olga Gyarfasova try check this link may help https://www.datanovia.com/en/lessons/kruskal-wallis-test-in-r/

1 Recommendation

I think Chi square values are reserved for Chi square test. APA style requires that you Report Kruskal Wallis statistic, the H statistic.

1 Recommendation

Article

- Jan 1984

The problem of testing the equality of the medians of several populations is considered. Standard distribution-free procedures for this problem require that the populations have the same shape in order to maintain their nominal significance level, ever asymptotically, under the null hypothesis of equal medians , A modification of the Kruskal-Wallis...

Data

- Sep 2017

Figure S1: G1m allotypes are not associated with the disease severity in MS. The MS severity score (MSSS) was estimated for G1m3 homozygous patients (n = 50), G1m1/G1m3 heterozygous patients (n = 58), and G1m1 homozygous patients (n = 18). Bars depict mean ± SD, and differences between the three groups were tested using Kruskal–Wallis test.

Article

- Jan 1968

Thesis (M.S.)--University of North Carolina at Chapel Hill, 1968.

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