Figure 2 - Nascent deductive proof schemes and proof readiness in adolescence

P[11]'s response to Q5. "We see at first the triangles ΓΘA and ΘΔA. We know that Θ is the perpendicular bisector of Γ and Δ [sic]. Thus, ΓΘ = ΘΔ. We have also common side ΘA thus also ΓA and AΔ are equal sides. Thus, for the triangles ABΓ and ABΔ we have AB common side, ΓA and AΔ equal sides and the angle B equal because it is divided by AB, thus they are equidistant B 1 and B 2 . From all the above the triangles ABΓ and ABΔ are equal."

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Reference

Nascent deductive proof schemes and proof readiness in adolescence - Scientific Figure on ResearchGate. Available from: https://www.researchgate.net/figure/P11s-response-to-Q5-We-see-at-first-the-triangles-GTHA-and-THDA-We-know-that-TH-is-the_fig4_375272243 [accessed 21 May 2025]

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Figure 2. P[11]'s response to Q5. "We see at first the triangles ΓΘA and ΘΔA. We know that Θ is the perpendicular bisector of Γ and Δ [sic]. Thus, ΓΘ = ΘΔ. We have also common side ΘA thus also ΓA and AΔ are equal sides. Thus, for the triangles ABΓ and ABΔ we have AB common side, ΓA and AΔ equal sides and the angle B equal because it is divided by AB, thus they are equidistant B 1 and B 2 . From all the above the triangles ABΓ and ABΔ are equal."

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<a href="https://www.researchgate.net/figure/P11s-response-to-Q5-We-see-at-first-the-triangles-GTHA-and-THDA-We-know-that-TH-is-the_fig4_375272243"><img src="https://www.researchgate.net/profile/Elena-Nardi/publication/375272243/figure/fig4/AS:11431281203817744@1699459522645/P11s-response-to-Q5-We-see-at-first-the-triangles-GTHA-and-THDA-We-know-that-TH-is-the.jpg" alt="P[11]'s response to Q5. "We see at first the triangles ΓΘA and ΘΔA. We know that Θ is the perpendicular bisector of Γ and Δ [sic]. Thus, ΓΘ = ΘΔ. We have also common side ΘA thus also ΓA and AΔ are equal sides. Thus, for the triangles ABΓ and ABΔ we have AB common side, ΓA and AΔ equal sides and the angle B equal because it is divided by AB, thus they are equidistant B 1 and B 2 . From all the above the triangles ABΓ and ABΔ are equal.""/></a>