# How to convert mg/L to mg/kg ?

1. metal (mg/kg) = [conc of metals (mg/L) X volume of sample (mL)] / [sample weight (kg) x 1000]

2. metal (mg/kg) = mg/L * final volume (ml) / initial sample weight (g)

Are these formulas correct for the conversion?

1. metal (mg/kg) = [conc of metals (mg/L) X volume of sample (mL)] / [sample weight (kg) x 1000]

2. metal (mg/kg) = mg/L * final volume (ml) / initial sample weight (g)

1. metal (mg/kg) = [conc of metals (mg/L) X volume of sample (mL)] / [sample weight (kg) x 1000]

2. metal (mg/kg) = mg/L * final volume (ml) / initial sample weight (g)

- metal (mg/kg) = [conc of metals (mg/L) X volume of sample (mL)] / [sample weight (kg) x 1000] is ok, also you can use:

metal (mg/kg) = [conc of metals (mg/L) X volume of sample (L)] / [sample weight (kg)]

they are the same. - If you know the density of the solution expressed in kg/l, you can divide your value in mg/l by the density so that (mg/l) / (kg/l) results in a value in mg/kg. Have a nice day.
- Some people use L as in 1000 cm^3 of soil, i.e., soil volume. So the L in these conversions could be L of soil solids plus pore. This makes good sense as plants root on volumes of soil, more than masses of soil. A major proponent of soil volumes was Adolf Mehlich of NCSU, who wrote several papers on these issues.
- For solid samples :

Element (µg / g) = (C)(V) (d.f) / w

Where C is the concentration of the element in the sample solution in mg / L ; V is the volume of the undiluted sample solution in ml ; W is the sample weight in grams ; and d.f is the dilution factor , if used , as described below:

d.f = volume of diluted sample solution in ml / volume of aliquot taken for dilution in ml - they are the same

please use the expression "sample weight" rather than "initial sample weight"

In the first case you used the weight in kg and therefore you used "total volume of extraction (mL)*1000/sample weigh (kg)"

In the second case you used the weight in grams and therefore you used "total volume of extraction (mL)*1/sample weight (g)" - Are the same and previous researchers answer well and exhaustively
- Is it the final volume of processed sample
- My opinion is the same like has Davide Papurello
- It can be done as follows:

Metal (mg/kg) = [conc. of metal (mg/L) * volume of sample (L)] / [sample weight (kg)]. -
It can be done like Tamer A. Elbana posited and then can be converted to the other w/w forms like ug/g by dividing the numerator and multiplying the denominator by 1000.

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## Popular Answers

Tamer A. Elbana· National Research Center, Egyptmetal (mg/kg) = [conc of metals (mg/L) X volume of sample (L)] / [sample weight (kg)]

they are the same.